From b9be6d026d327593784b042aab4fa27e2de9c825 Mon Sep 17 00:00:00 2001 From: Wang YanQing Date: Sat, 14 Sep 2013 12:59:16 +0800 Subject: [PATCH] tracing: Show more exact help information about snapshot The current "help" that comes out of the snapshot file when it is not allocated looks like this: # * Snapshot is freed * # # Snapshot commands: # echo 0 > snapshot : Clears and frees snapshot buffer # echo 1 > snapshot : Allocates snapshot buffer, if not already allocated. # Takes a snapshot of the main buffer. # echo 2 > snapshot : Clears snapshot buffer (but does not allocate) # (Doesn't have to be '2' works with any number that # is not a '0' or '1') Echo 2 says that it does not allocate the buffer, which is correct, but to be more consistent with "echo 0" it should also state that it does not free. Link: http://lkml.kernel.org/r/20130914045916.GA4243@udknight Signed-off-by: Wang YanQing Signed-off-by: Steven Rostedt --- kernel/trace/trace.c | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/kernel/trace/trace.c b/kernel/trace/trace.c index 7974ba2..d5f7c4d 100644 --- a/kernel/trace/trace.c +++ b/kernel/trace/trace.c @@ -2760,7 +2760,7 @@ static void show_snapshot_main_help(struct seq_file *m) seq_printf(m, "# echo 0 > snapshot : Clears and frees snapshot buffer\n"); seq_printf(m, "# echo 1 > snapshot : Allocates snapshot buffer, if not already allocated.\n"); seq_printf(m, "# Takes a snapshot of the main buffer.\n"); - seq_printf(m, "# echo 2 > snapshot : Clears snapshot buffer (but does not allocate)\n"); + seq_printf(m, "# echo 2 > snapshot : Clears snapshot buffer (but does not allocate or free)\n"); seq_printf(m, "# (Doesn't have to be '2' works with any number that\n"); seq_printf(m, "# is not a '0' or '1')\n"); } -- 2.7.4