btrfs-progs: receive: fix minor resource leak

Resolves-coverity-id: 1302985
Signed-off-by: David Sterba <dsterba@suse.cz>

diff --git a/cmds-receive.c b/cmds-receive.c
index 114b718..a57f8d9 100644 (file)
--- a/cmds-receive.c
+++ b/cmds-receive.c
@@ -1002,7 +1002,7 @@ int cmd_receive(int argc, char **argv)
        struct btrfs_receive r;
        int receive_fd = fileno(stdin);
        u64 max_errors = 1;
-       int ret;
+       int ret = 0;
 
        memset(&r, 0, sizeof(r));
        r.mnt_fd = -1;
@@ -1039,10 +1039,11 @@ int cmd_receive(int argc, char **argv)
                        max_errors = arg_strtou64(optarg);
                        break;
                case 'm':
+                       free(realmnt);
                        realmnt = strdup(optarg);
                        if (!realmnt) {
                                fprintf(stderr, "ERROR: couldn't allocate realmnt.\n");
-                               return 1;
+                               goto out;
                        }
                        break;
                case '?':
@@ -1061,12 +1062,15 @@ int cmd_receive(int argc, char **argv)
                receive_fd = open(fromfile, O_RDONLY | O_NOATIME);
                if (receive_fd < 0) {
                        fprintf(stderr, "ERROR: failed to open %s\n", fromfile);
-                       return 1;
+                       goto out;
                }
        }
 
        ret = do_receive(&r, tomnt, realmnt, receive_fd, max_errors);
 
+out:
+       free(realmnt);
+
        return !!ret;
 }