[XLA] Don't print "{no layout}" if there is no layout.
authorA. Unique TensorFlower <gardener@tensorflow.org>
Sat, 27 Jan 2018 00:23:40 +0000 (16:23 -0800)
committerTensorFlower Gardener <gardener@tensorflow.org>
Sat, 27 Jan 2018 00:27:23 +0000 (16:27 -0800)
PiperOrigin-RevId: 183463264

tensorflow/compiler/xla/shape_util.cc

index cba73322fa924785fbc73a4e931b5f27227d89b9..d63e16ce2bf51cff0d113640d31ec6e70bfaf421 100644 (file)
@@ -475,8 +475,6 @@ StatusOr<PrimitiveType> StringToPrimitiveType(const string& name) {
       if (LayoutUtil::HasLayout(shape)) {
         tensorflow::strings::StrAppend(&result,
                                        LayoutUtil::HumanString(shape.layout()));
-      } else {
-        tensorflow::strings::StrAppend(&result, "{no layout}");
       }
     }
     return result;