When a dso contains multiple symbols which have same name, current
dso__find_symbol_by_name() only finds an one of them and there's no way
to get the all symbols without going through the rbtree.
So make symbols__find_by_name() return the first entry with the given
name and the next patch in this series will provide a way to iterate
from there, by the name ordered rb_tree, till a suitable symbol is
found.
Signed-off-by: Namhyung Kim <namhyung@kernel.org>
Cc: David Ahern <dsahern@gmail.com>
Cc: Jiri Olsa <jolsa@redhat.com>
Cc: Masami Hiramatsu <masami.hiramatsu.pt@hitachi.com>
Link: http://lkml.kernel.org/r/1421234288-22758-2-git-send-email-namhyung@kernel.org
[ Yanked this independent hunk, without changes, from a larger patch ]
Signed-off-by: Arnaldo Carvalho de Melo <acme@redhat.com>
const char *name)
{
struct rb_node *n;
+ struct symbol_name_rb_node *s;
if (symbols == NULL)
return NULL;
n = symbols->rb_node;
while (n) {
- struct symbol_name_rb_node *s;
int cmp;
s = rb_entry(n, struct symbol_name_rb_node, rb_node);
else if (cmp > 0)
n = n->rb_right;
else
- return &s->sym;
+ break;
}
- return NULL;
+ if (n == NULL)
+ return NULL;
+
+ /* return first symbol that has same name (if any) */
+ for (n = rb_prev(n); n; n = rb_prev(n)) {
+ struct symbol_name_rb_node *tmp;
+
+ tmp = rb_entry(n, struct symbol_name_rb_node, rb_node);
+ if (strcmp(tmp->sym.name, s->sym.name))
+ break;
+
+ s = tmp;
+ }
+
+ return &s->sym;
}
struct symbol *dso__find_symbol(struct dso *dso,