sizeof() returns a size_t but the other types involved
are unsigned long, so using min() results in a warning.
As sizeof() is called on an 11 character buffer defined
immediately above unsigned long is obviously wide enough
for the result.
Signed-off-by: Simon Horman <horms@verge.net.au>
Signed-off-by: Greg Kroah-Hartman <gregkh@suse.de>
unsigned long count, void *data)
{
char buf[] = "0x00000000";
- unsigned long len = min(sizeof(buf) - 1, count);
+ unsigned long len = min_t(unsigned long, sizeof(buf) - 1, count);
char *p = (char *)buf;
unsigned long val;
unsigned long count, void *data)
{
char buf[] = "0x00000000";
- unsigned long len = min(sizeof(buf) - 1, count);
+ unsigned long len = min_t(unsigned long, sizeof(buf) - 1, count);
char *p = (char *)buf;
unsigned long val;