Btrfs: unlock inodes in correct order in clone ioctl
authorFilipe David Borba Manana <fdmanana@gmail.com>
Sat, 11 Jan 2014 21:31:25 +0000 (21:31 +0000)
committerChris Mason <clm@fb.com>
Tue, 28 Jan 2014 21:20:30 +0000 (13:20 -0800)
In the clone ioctl, when the source and target inodes are different,
we can acquire their mutexes in 2 possible different orders. After
we're done cloning, we were releasing the mutexes always in the same
order - the most correct way of doing it is to release them by the
reverse order they were acquired.

Signed-off-by: Filipe David Borba Manana <fdmanana@gmail.com>
Signed-off-by: Josef Bacik <jbacik@fb.com>
Signed-off-by: Chris Mason <clm@fb.com>
fs/btrfs/ioctl.c

index 332b624..5ed5bd0 100644 (file)
@@ -3263,9 +3263,17 @@ static noinline long btrfs_ioctl_clone(struct file *file, unsigned long srcfd,
 
        unlock_extent(&BTRFS_I(src)->io_tree, off, off + len - 1);
 out_unlock:
-       mutex_unlock(&src->i_mutex);
-       if (!same_inode)
-               mutex_unlock(&inode->i_mutex);
+       if (!same_inode) {
+               if (inode < src) {
+                       mutex_unlock(&src->i_mutex);
+                       mutex_unlock(&inode->i_mutex);
+               } else {
+                       mutex_unlock(&inode->i_mutex);
+                       mutex_unlock(&src->i_mutex);
+               }
+       } else {
+               mutex_unlock(&src->i_mutex);
+       }
 out_fput:
        fdput(src_file);
 out_drop_write: