[ Upstream commit
bc3a024101ca497bea4c69be4054c32a5c349f1d ]
If ice_init_interrupt_scheme fails, ice_probe will jump to clearing up
the interrupts. This can lead to some static analysis tools such as the
compiler sanitizers complaining about double free problems.
Since ice_init_interrupt_scheme already unrolls internally on failure,
there is no need to call ice_clear_interrupt_scheme when it fails. Add
a new unroll label and use that instead.
Signed-off-by: Jacob Keller <jacob.e.keller@intel.com>
Tested-by: Andrew Bowers <andrewx.bowers@intel.com>
Signed-off-by: Jeff Kirsher <jeffrey.t.kirsher@intel.com>
Signed-off-by: Sasha Levin <sashal@kernel.org>
if (err) {
dev_err(dev, "ice_init_interrupt_scheme failed: %d\n", err);
err = -EIO;
- goto err_init_interrupt_unroll;
+ goto err_init_vsi_unroll;
}
/* Driver is mostly up */
ice_free_irq_msix_misc(pf);
err_init_interrupt_unroll:
ice_clear_interrupt_scheme(pf);
+err_init_vsi_unroll:
devm_kfree(dev, pf->vsi);
err_init_pf_unroll:
ice_deinit_pf(pf);