This form makes more sense (it is a range over constant arguments) and is most consistent with const_arg_iterator (there are zero instances of arg_const_iterator).
llvm-svn: 339527
typedef ExprIterator arg_iterator;
typedef ConstExprIterator const_arg_iterator;
typedef llvm::iterator_range<arg_iterator> arg_range;
- typedef llvm::iterator_range<const_arg_iterator> arg_const_range;
+ typedef llvm::iterator_range<const_arg_iterator> const_arg_range;
arg_range arguments() { return arg_range(arg_begin(), arg_end()); }
- arg_const_range arguments() const {
- return arg_const_range(arg_begin(), arg_end());
+ const_arg_range arguments() const {
+ return const_arg_range(arg_begin(), arg_end());
}
arg_iterator arg_begin() { return SubExprs+PREARGS_START+getNumPreArgs(); }
using arg_iterator = ExprIterator;
using const_arg_iterator = ConstExprIterator;
using arg_range = llvm::iterator_range<arg_iterator>;
- using arg_const_range = llvm::iterator_range<const_arg_iterator>;
+ using const_arg_range = llvm::iterator_range<const_arg_iterator>;
arg_range arguments() { return arg_range(arg_begin(), arg_end()); }
- arg_const_range arguments() const {
- return arg_const_range(arg_begin(), arg_end());
+ const_arg_range arguments() const {
+ return const_arg_range(arg_begin(), arg_end());
}
arg_iterator arg_begin() { return Args; }
typedef ArgInfo *arg_iterator;
typedef llvm::iterator_range<arg_iterator> arg_range;
- typedef llvm::iterator_range<const_arg_iterator> arg_const_range;
+ typedef llvm::iterator_range<const_arg_iterator> const_arg_range;
arg_range arguments() { return arg_range(arg_begin(), arg_end()); }
- arg_const_range arguments() const {
- return arg_const_range(arg_begin(), arg_end());
+ const_arg_range arguments() const {
+ return const_arg_range(arg_begin(), arg_end());
}
const_arg_iterator arg_begin() const { return getArgsBuffer() + 1; }