isl_basic_set_free(graph->lp);
}
- * we usually have one row, but it may be split by split_parallel),
+ /* For each "set" on which this function is called, increment
+ * graph->n by one and update graph->maxvar.
+ */
+ static int init_n_maxvar(__isl_take isl_set *set, void *user)
+ {
+ struct isl_sched_graph *graph = user;
+ int nvar = isl_set_dim(set, isl_dim_set);
+
+ graph->n++;
+ if (nvar > graph->maxvar)
+ graph->maxvar = nvar;
+
+ isl_set_free(set);
+
+ return 0;
+ }
+
+ /* Compute the number of rows that should be allocated for the schedule.
+ * The graph can be split at most "n - 1" times, there can be at most
+ * two rows for each dimension in the iteration domains (in particular,
++ * we usually have one row, but it may be split by split_scaled),
+ * and there can be one extra row for ordering the statements.
+ * Note that if we have actually split "n - 1" times, then no ordering
+ * is needed, so in principle we could use "graph->n + 2 * graph->maxvar - 1".
+ */
+ static int compute_max_row(struct isl_sched_graph *graph,
+ __isl_keep isl_union_set *domain)
+ {
+ graph->n = 0;
+ graph->maxvar = 0;
+ if (isl_union_set_foreach_set(domain, &init_n_maxvar, graph) < 0)
+ return -1;
+ graph->max_row = graph->n + 2 * graph->maxvar;
+
+ return 0;
+ }
+
/* Add a new node to the graph representing the given set.
*/
static int extract_node(__isl_take isl_set *set, void *user)