Summary:
Assignment operator `operator=(long long)` currently allocates `sizeof(long)`.
On some platforms it works as they have `sizeof(long) == sizeof(long long)`,
but on others (e.g. Windows) it's not the case.
Reviewed By: labath
Differential Revision: https://reviews.llvm.org/D80995
Scalar &Scalar::operator=(long long v) {
m_type = e_slonglong;
- m_integer = llvm::APInt(sizeof(long) * 8, v, true);
+ m_integer = llvm::APInt(sizeof(long long) * 8, v, true);
return *this;
}
ScalarGetValue(std::numeric_limits<unsigned long long>::max()));
}
+TEST(ScalarTest, LongLongAssigmentOperator) {
+ Scalar ull;
+ ull = std::numeric_limits<unsigned long long>::max();
+ EXPECT_EQ(std::numeric_limits<unsigned long long>::max(), ull.ULongLong());
+
+ Scalar sll;
+ sll = std::numeric_limits<signed long long>::max();
+ EXPECT_EQ(std::numeric_limits<signed long long>::max(), sll.SLongLong());
+}
+
TEST(ScalarTest, Division) {
Scalar lhs(5.0);
Scalar rhs(2.0);