sched, sysctl: Delete an unnecessary check before unregister_sysctl_table()

The unregister_sysctl_table() function tests whether its argument is NULL
and then returns immediately. Thus the test around the call is not needed.

This issue was detected by using the Coccinelle software.

Signed-off-by: Markus Elfring <elfring@users.sourceforge.net>
Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: Mike Galbraith <efault@gmx.de>
Cc: Peter Zijlstra <peterz@infradead.org>
Cc: Thomas Gleixner <tglx@linutronix.de>
Link: http://lkml.kernel.org/r/5597877E.3060503@users.sourceforge.net
Signed-off-by: Ingo Molnar <mingo@kernel.org>

diff --git a/kernel/sched/core.c b/kernel/sched/core.c
index 78b4bad..48be7dc 100644 (file)
--- a/kernel/sched/core.c
+++ b/kernel/sched/core.c
@@ -5311,8 +5311,7 @@ static void register_sched_domain_sysctl(void)
 /* may be called multiple times per register */
 static void unregister_sched_domain_sysctl(void)
 {
-       if (sd_sysctl_header)
-               unregister_sysctl_table(sd_sysctl_header);
+       unregister_sysctl_table(sd_sysctl_header);
        sd_sysctl_header = NULL;
        if (sd_ctl_dir[0].child)
                sd_free_ctl_entry(&sd_ctl_dir[0].child);