util: Get program name based on path when possible

Some programs start with the path and command line arguments in
argv[0] (program_invocation_name). Chromium is an example of
an application using mesa that does this.

This tries to query the real path for the symbolic link /proc/self/exe
to find the program name instead. It only uses the realpath if it
was a prefix of the invocation to avoid breaking wine programs.

Cc: Timothy Arceri <tarceri@itsqueeze.com>
Signed-off-by: Nicholas Kazlauskas <nicholas.kazlauskas@amd.com>
Reviewed-by: Eric Engestrom <eric.engestrom@intel.com>

diff --git a/src/util/u_process.c b/src/util/u_process.c
index 5e59276..a1667e7 100644 (file)
--- a/src/util/u_process.c
+++ b/src/util/u_process.c
@@ -41,8 +41,29 @@ static const char *
 __getProgramName()
 {
    char * arg = strrchr(program_invocation_name, '/');
-   if (arg)
+   if (arg) {
+      /* If the / character was found this is likely a linux path or
+       * an invocation path for a 64-bit wine program.
+       *
+       * However, some programs pass command line arguments into argv[0].
+       * Strip these arguments out by using the realpath only if it was
+       * a prefix of the invocation name.
+       */
+      static char *path;
+
+      if (!path)
+         path = realpath("/proc/self/exe", NULL);
+
+      if (path && strncmp(path, program_invocation_name, strlen(path)) == 0) {
+         /* This shouldn't be null because path is a a prefix,
+          * but check it anyway since path is static. */
+         char * name = strrchr(path, '/');
+         if (name)
+            return name + 1;
+      }
+
       return arg+1;
+   }
 
    /* If there was no '/' at all we likely have a windows like path from
     * a wine application.