One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:
struct foo {
int stuff;
struct boo entry[];
};
size = sizeof(struct foo) + count * sizeof(struct boo);
instance = alloc(size, GFP_KERNEL)
Instead of leaving these open-coded and prone to type mistakes, we can
now use the new struct_size() helper:
size = struct_size(instance, entry, count);
This code was detected with the help of Coccinelle.
Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com>
Acked-by: Simon Horman <horms+renesas@verge.net.au>
Signed-off-by: Pablo Neira Ayuso <pablo@netfilter.org>
int size;
get = (struct ip_vs_get_services *)arg;
- size = sizeof(*get) +
- sizeof(struct ip_vs_service_entry) * get->num_services;
+ size = struct_size(get, entrytable, get->num_services);
if (*len != size) {
pr_err("length: %u != %u\n", *len, size);
ret = -EINVAL;
int size;
get = (struct ip_vs_get_dests *)arg;
- size = sizeof(*get) +
- sizeof(struct ip_vs_dest_entry) * get->num_dests;
+ size = struct_size(get, entrytable, get->num_dests);
if (*len != size) {
pr_err("length: %u != %u\n", *len, size);
ret = -EINVAL;