Watchdog: fix clearing of the watchdog interrupt
authorRussell King <rmk+kernel@arm.linux.org.uk>
Tue, 18 Jun 2013 16:20:32 +0000 (17:20 +0100)
committerWim Van Sebroeck <wim@iguana.be>
Thu, 11 Jul 2013 20:18:30 +0000 (22:18 +0200)
The bits in BRIDGE_CAUSE are documented as RW0C - read, write 0 to
clear.  If we read the register, mask off the watchdog bit, and
write it back, we're actually clearing every interrupt which wasn't
pending at the time we read the register - and that is racy.

Fix this to only write ~WATCHDOG_BIT to the register, which means
we write as zero only the watchdog bit.

Signed-off-by: Russell King <rmk+kernel@arm.linux.org.uk>
Acked-by: Jason Cooper <jason@lakedaemon.net>
Tested-by: Andrew Lunn <andrew@lunn.ch>
Signed-off-by: Wim Van Sebroeck <wim@iguana.be>
drivers/watchdog/orion_wdt.c

index 4074244..4ea5fcc 100644 (file)
@@ -70,9 +70,7 @@ static int orion_wdt_start(struct watchdog_device *wdt_dev)
        writel(wdt_tclk * wdt_dev->timeout, wdt_reg + WDT_VAL);
 
        /* Clear watchdog timer interrupt */
-       reg = readl(BRIDGE_CAUSE);
-       reg &= ~WDT_INT_REQ;
-       writel(reg, BRIDGE_CAUSE);
+       writel(~WDT_INT_REQ, BRIDGE_CAUSE);
 
        /* Enable watchdog timer */
        reg = readl(wdt_reg + TIMER_CTRL);