fuse: call pipe_buf_release() under pipe lock
authorJann Horn <jannh@google.com>
Sat, 12 Jan 2019 01:39:05 +0000 (02:39 +0100)
committerGreg Kroah-Hartman <gregkh@linuxfoundation.org>
Tue, 12 Feb 2019 18:46:11 +0000 (19:46 +0100)
commit 9509941e9c534920ccc4771ae70bd6cbbe79df1c upstream.

Some of the pipe_buf_release() handlers seem to assume that the pipe is
locked - in particular, anon_pipe_buf_release() accesses pipe->tmp_page
without taking any extra locks. From a glance through the callers of
pipe_buf_release(), it looks like FUSE is the only one that calls
pipe_buf_release() without having the pipe locked.

This bug should only lead to a memory leak, nothing terrible.

Fixes: dd3bb14f44a6 ("fuse: support splice() writing to fuse device")
Cc: stable@vger.kernel.org
Signed-off-by: Jann Horn <jannh@google.com>
Signed-off-by: Miklos Szeredi <mszeredi@redhat.com>
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
fs/fuse/dev.c

index f7280c4..b298618 100644 (file)
@@ -2024,8 +2024,10 @@ static ssize_t fuse_dev_splice_write(struct pipe_inode_info *pipe,
 
        ret = fuse_dev_do_write(fud, &cs, len);
 
+       pipe_lock(pipe);
        for (idx = 0; idx < nbuf; idx++)
                pipe_buf_release(pipe, &bufs[idx]);
+       pipe_unlock(pipe);
 
 out:
        kfree(bufs);