Summary:
Code that used to be formatted as `if (! + object) {` is now formatted as `if (!+object) {`
(we have a particular object in our codebase where unary `operator+` is overloaded to return the underlying value, which in this case is a `bool`)
We still preserve the TypeScript behavior where `!` is a trailing non-null operator. (This is already tested by an existing unit test in `FormatTestJS.cpp`)
It doesn't appear like handling of consecutive unary operators are tested in general, so I added another test for completeness
Patch contributed by @kevinl!
Reviewers: krasimir
Reviewed By: krasimir
Subscribers: klimek, cfe-commits
Differential Revision: https://reviews.llvm.org/D43312
llvm-svn: 326792
if (!PrevToken)
return TT_UnaryOperator;
- if (PrevToken->isOneOf(TT_CastRParen, TT_UnaryOperator) &&
- !PrevToken->is(tok::exclaim))
- // There aren't any trailing unary operators except for TypeScript's
- // non-null operator (!). Thus, this must be squence of leading operators.
+ if (PrevToken->isOneOf(TT_CastRParen, TT_UnaryOperator))
+ // This must be a sequence of leading unary operators.
return TT_UnaryOperator;
// Use heuristics to recognize unary operators.
verifyFormat("(a->f())++;");
verifyFormat("a[42]++;");
verifyFormat("if (!(a->f())) {\n}");
+ verifyFormat("if (!+i) {\n}");
+ verifyFormat("~&a;");
verifyFormat("a-- > b;");
verifyFormat("b ? -a : c;");
verifyFormat("let x = foo!.bar();\n");
verifyFormat("let x = foo ? bar! : baz;\n");
verifyFormat("let x = !foo;\n");
+ verifyFormat("if (!+a) {\n}");
verifyFormat("let x = foo[0]!;\n");
verifyFormat("let x = (foo)!;\n");
verifyFormat("let x = x(foo!);\n");