One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:
struct foo {
int stuff;
struct boo entry[];
};
size = sizeof(struct foo) + count * sizeof(struct boo);
instance = kzalloc(size, GFP_KERNEL);
Instead of leaving these open-coded and prone to type mistakes, we can
now use the new struct_size() helper:
instance = kzalloc(struct_size(instance, entry, count), GFP_KERNEL);
Notice that, in this case, variable siz is not necessary, hence
it is removed.
This code was detected with the help of Coccinelle.
Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com>
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
struct hpet_dev *devp;
u32 i, ntimer;
struct hpets *hpetp;
- size_t siz;
struct hpet __iomem *hpet;
static struct hpets *last;
unsigned long period;
return 0;
}
- siz = sizeof(struct hpets) + ((hdp->hd_nirqs - 1) *
- sizeof(struct hpet_dev));
-
- hpetp = kzalloc(siz, GFP_KERNEL);
+ hpetp = kzalloc(struct_size(hpetp, hp_dev, hdp->hd_nirqs - 1),
+ GFP_KERNEL);
if (!hpetp)
return -ENOMEM;