bpf: fixup error message from gpl helpers on license mismatch
authorDaniel Borkmann <daniel@iogearbox.net>
Sat, 2 Jun 2018 21:06:33 +0000 (23:06 +0200)
committerAlexei Starovoitov <ast@kernel.org>
Sun, 3 Jun 2018 14:42:06 +0000 (07:42 -0700)
Stating 'proprietary program' in the error is just silly since it
can also be a different open source license than that which is just
not compatible.

Reference: https://twitter.com/majek04/status/998531268039102465
Signed-off-by: Daniel Borkmann <daniel@iogearbox.net>
Acked-by: Alexei Starovoitov <ast@kernel.org>
Acked-by: Jesper Dangaard Brouer <brouer@redhat.com>
Acked-by: Song Liu <songliubraving@fb.com>
Signed-off-by: Alexei Starovoitov <ast@kernel.org>
kernel/bpf/verifier.c

index 1fd9667b29f1a93998d808bcb6a307ff1412b1d7..4f4786ea2296ed794fe929b4037376d996945fd6 100644 (file)
@@ -2462,7 +2462,7 @@ static int check_helper_call(struct bpf_verifier_env *env, int func_id, int insn
 
        /* eBPF programs must be GPL compatible to use GPL-ed functions */
        if (!env->prog->gpl_compatible && fn->gpl_only) {
-               verbose(env, "cannot call GPL only function from proprietary program\n");
+               verbose(env, "cannot call GPL-restricted function from non-GPL compatible program\n");
                return -EINVAL;
        }