kvm_debug("MISR = %08x\n", vgic_cpu->vgic_misr);
- /*
- * We do not need to take the distributor lock here, since the only
- * action we perform is clearing the irq_active_bit for an EOIed
- * level interrupt. There is a potential race with
- * the queuing of an interrupt in __kvm_vgic_flush_hwstate(), where we
- * check if the interrupt is already active. Two possibilities:
- *
- * - The queuing is occurring on the same vcpu: cannot happen,
- * as we're already in the context of this vcpu, and
- * executing the handler
- * - The interrupt has been migrated to another vcpu, and we
- * ignore this interrupt for this run. Big deal. It is still
- * pending though, and will get considered when this vcpu
- * exits.
- */
if (vgic_cpu->vgic_misr & GICH_MISR_EOI) {
/*
* Some level interrupts have been EOIed. Clear their
}
/*
- * Sync back the VGIC state after a guest run. We do not really touch
- * the distributor here (the irq_pending_on_cpu bit is safe to set),
- * so there is no need for taking its lock.
+ * Sync back the VGIC state after a guest run. The distributor lock is
+ * needed so we don't get preempted in the middle of the state processing.
*/
static void __kvm_vgic_sync_hwstate(struct kvm_vcpu *vcpu)
{
void kvm_vgic_sync_hwstate(struct kvm_vcpu *vcpu)
{
+ struct vgic_dist *dist = &vcpu->kvm->arch.vgic;
+
if (!irqchip_in_kernel(vcpu->kvm))
return;
+ spin_lock(&dist->lock);
__kvm_vgic_sync_hwstate(vcpu);
+ spin_unlock(&dist->lock);
}
int kvm_vgic_vcpu_pending_irq(struct kvm_vcpu *vcpu)