pinctrl: meson: meson: Add of_node_put() before return

Each iteration of for_each_child_of_node puts the previous node, but in
the case of a return from the middle of the loop, there is no put, thus
causing a memory leak. Hence add an of_node_put before the return.
Issue found with Coccinelle.

Signed-off-by: Nishka Dasgupta <nishkadg.linux@gmail.com>
Link: https://lore.kernel.org/r/20190815060718.3286-1-nishkadg.linux@gmail.com
Reviewed-by: Neil Armstrong <narmstrong@baylibre.com>
Signed-off-by: Linus Walleij <linus.walleij@linaro.org>

diff --git a/drivers/pinctrl/meson/pinctrl-meson.c b/drivers/pinctrl/meson/pinctrl-meson.c
index 5967869..8bba9d0 100644 (file)
--- a/drivers/pinctrl/meson/pinctrl-meson.c
+++ b/drivers/pinctrl/meson/pinctrl-meson.c
@@ -651,6 +651,7 @@ static int meson_pinctrl_parse_dt(struct meson_pinctrl *pc,
                        continue;
                if (gpio_np) {
                        dev_err(pc->dev, "multiple gpio nodes\n");
+                       of_node_put(np);
                        return -EINVAL;
                }
                gpio_np = np;