"set1 in set2" doesn't do what you'd expect, and if it did do a subset test
that's not the logic required by contains_any().
Instead get the intersection of checkvalues and val and check if the resulting
set is empty or not (by evaluating it in a boolean context), which tells us if
there are any elements in common.
Based on a patch by Valentin Popa <valentin.popa@intel.com>.
(Bitbake rev:
2e742c03e8dfdfa67899e7f5d579ed14bd87e139)
Signed-off-by: Ross Burton <ross.burton@intel.com>
Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>
checkvalues = set(checkvalues.split())
else:
checkvalues = set(checkvalues)
- if checkvalues in val:
+ if checkvalues & val:
return truevalue
return falsevalue