module: correctly exit module_kallsyms_on_each_symbol when fn() != 0
authorJon Mediero <jmdr@disroot.org>
Thu, 20 May 2021 12:23:26 +0000 (14:23 +0200)
committerJessica Yu <jeyu@kernel.org>
Wed, 26 May 2021 12:55:45 +0000 (14:55 +0200)
Commit 013c1667cf78 ("kallsyms: refactor
{,module_}kallsyms_on_each_symbol") replaced the return inside the
nested loop with a break, changing the semantics of the function: the
break only exits the innermost loop, so the code continues iterating the
symbols of the next module instead of exiting.

Fixes: 013c1667cf78 ("kallsyms: refactor {,module_}kallsyms_on_each_symbol")
Reviewed-by: Petr Mladek <pmladek@suse.com>
Reviewed-by: Miroslav Benes <mbenes@suse.cz>
Signed-off-by: Jon Mediero <jmdr@disroot.org>
Signed-off-by: Jessica Yu <jeyu@kernel.org>
kernel/module.c

index faf9114..fdd6047 100644 (file)
@@ -4415,9 +4415,10 @@ int module_kallsyms_on_each_symbol(int (*fn)(void *, const char *,
                        ret = fn(data, kallsyms_symbol_name(kallsyms, i),
                                 mod, kallsyms_symbol_value(sym));
                        if (ret != 0)
-                               break;
+                               goto out;
                }
        }
+out:
        mutex_unlock(&module_mutex);
        return ret;
 }