Some functions can end up non-externally visible despite not being
declared "static" or in an unnamed namespace in C++ - such as by having
parameters that are of non-external types.
Such functions aren't mistakenly intended to be defining some function
that needs a declaration. They could be maybe more legible (except for
the `operator new` example) with an explicit static, but that's a
stylistic thing outside what should be addressed by a warning.
if (!FD->isGlobal())
return false;
+ if (!FD->isExternallyVisible())
+ return false;
+
// Don't warn about C++ member functions.
if (isa<CXXMethodDecl>(FD))
return false;
extern void k() {} // expected-warning {{no previous prototype for function 'k'}}
// expected-note@-1{{declare 'static' if the function is not intended to be used outside of this translation unit}}
// CHECK-NOT: fix-it:"{{.*}}":{[[@LINE-2]]:{{.*}}-[[@LINE-2]]:{{.*}}}:"{{.*}}"
+
+namespace {
+struct anon { };
+}
+
+// No warning because this has internal linkage despite not being declared
+// explicitly 'static', owing to the internal linkage parameter.
+void l(anon) {
+}
+
+void *operator new(decltype(sizeof(3)) size, const anon &) throw() {
+ return nullptr;
+}