[ Upstream commit
d57378d3aa4d864d9e590482602068af1b20c0c5 ]
Currently ima_lsm_copy_rule() set the arg_p field of the source rule to
NULL, so that the source rule could be freed afterward. It does not make
sense for this behavior to be inside a "copy" function. So move it
outside and let the caller handle this field.
ima_lsm_copy_rule() now produce a shallow copy of the original entry
including args_p field. Meaning only the lsm.rule and the rule itself
should be freed for the original rule. Thus, instead of calling
ima_lsm_free_rule() which frees lsm.rule as well as args_p field, free
the lsm.rule directly.
Signed-off-by: GUO Zihua <guozihua@huawei.com>
Reviewed-by: Roberto Sassu <roberto.sassu@huawei.com>
Signed-off-by: Mimi Zohar <zohar@linux.ibm.com>
Signed-off-by: Sasha Levin <sashal@kernel.org>
nentry->lsm[i].type = entry->lsm[i].type;
nentry->lsm[i].args_p = entry->lsm[i].args_p;
- /*
- * Remove the reference from entry so that the associated
- * memory will not be freed during a later call to
- * ima_lsm_free_rule(entry).
- */
- entry->lsm[i].args_p = NULL;
ima_filter_rule_init(nentry->lsm[i].type, Audit_equal,
nentry->lsm[i].args_p,
static int ima_lsm_update_rule(struct ima_rule_entry *entry)
{
+ int i;
struct ima_rule_entry *nentry;
nentry = ima_lsm_copy_rule(entry);
* references and the entry itself. All other memory references will now
* be owned by nentry.
*/
- ima_lsm_free_rule(entry);
+ for (i = 0; i < MAX_LSM_RULES; i++)
+ ima_filter_rule_free(entry->lsm[i].rule);
kfree(entry);
return 0;