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Fix: bracket expression matches a character at gawk
author
Geunsik Lim
<geunsik.lim@samsung.com>
Sat, 26 Mar 2016 10:04:31 +0000
(19:04 +0900)
committer
Geunsik Lim
<geunsik.lim@samsung.com>
Sat, 26 Mar 2016 10:04:31 +0000
(19:04 +0900)
This is a trivial patch. However, It's must be modified by gawk.
Check it exactly as a plain character (e.g., space, alnum)
within the bracket expression at ./coreclr/generateversionscript.awk
Signed-off-by: Geunsik Lim <geunsik.lim@samsung.com>
generateversionscript.awk
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diff --git
a/generateversionscript.awk
b/generateversionscript.awk
index
d1c294b
..
168d398
100644
(file)
--- a/
generateversionscript.awk
+++ b/
generateversionscript.awk
@@
-8,7
+8,7
@@
BEGIN {
gsub(/\r/,"", $0);
# Skip empty lines and comment lines starting with semicolon
- if (NF && !match($0, /^[
:space:
]*;/))
+ if (NF && !match($0, /^[
[:space:]
]*;/))
{
print " " $0 ";";
}