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sched: Don't initialize alloc_state in build_sched_domains()
author
Viresh Kumar
<viresh.kumar@linaro.org>
Mon, 10 Jun 2013 10:57:18 +0000
(16:27 +0530)
committer
Ingo Molnar
<mingo@kernel.org>
Wed, 19 Jun 2013 10:58:44 +0000
(12:58 +0200)
alloc_state will be overwritten by __visit_domain_allocation_hell() and so we
don't actually need to initialize alloc_state.
Signed-off-by: Viresh Kumar <viresh.kumar@linaro.org>
Signed-off-by: Peter Zijlstra <peterz@infradead.org>
Link:
http://lkml.kernel.org/r/df57734a075cc5ad130e1ae498702e24f2529ab8.1370861520.git.viresh.kumar@linaro.org
Signed-off-by: Ingo Molnar <mingo@kernel.org>
kernel/sched/core.c
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diff --git
a/kernel/sched/core.c
b/kernel/sched/core.c
index
137dcc0
..
3de6264
100644
(file)
--- a/
kernel/sched/core.c
+++ b/
kernel/sched/core.c
@@
-5969,7
+5969,7
@@
struct sched_domain *build_sched_domain(struct sched_domain_topology_level *tl,
static int build_sched_domains(const struct cpumask *cpu_map,
struct sched_domain_attr *attr)
{
- enum s_alloc alloc_state
= sa_none
;
+ enum s_alloc alloc_state;
struct sched_domain *sd;
struct s_data d;
int i, ret = -ENOMEM;