The current shift of st->rx[2] left shifts a u8 24 bits left,
promotes the integer to a an int and then to a unsigned u64. If
the top bit of st->rx[2] is set then we end up with all the upper
bits being set to 1. Fix this by casting st->rx[2] to a u64 before
the 24 bit left shift.
Detected by CoverityScan CID#144940 ("Unintended sign extension")
Fixes:
2919fa54ef64 ("staging: iio: meter: new driver for ADE7759 devices")
Signed-off-by: Colin Ian King <colin.king@canonical.com>
Signed-off-by: Jonathan Cameron <Jonathan.Cameron@huawei.com>
reg_address);
goto error_ret;
}
- *val = ((u64)st->rx[1] << 32) | (st->rx[2] << 24) |
+ *val = ((u64)st->rx[1] << 32) | ((u64)st->rx[2] << 24) |
(st->rx[3] << 16) | (st->rx[4] << 8) | st->rx[5];
error_ret: