When using the device memory allocation API the user ought to know what
is the default allocation page size.
Signed-off-by: Ohad Sharabi <osharabi@habana.ai>
Reviewed-by: Oded Gabbay <ogabbay@kernel.org>
Signed-off-by: Oded Gabbay <ogabbay@kernel.org>
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
if (hw_ip.dram_size > PAGE_SIZE)
hw_ip.dram_enabled = 1;
hw_ip.dram_page_size = prop->dram_page_size;
+ hw_ip.device_mem_alloc_default_page_size = prop->device_mem_alloc_default_page_size;
hw_ip.num_of_events = prop->num_of_events;
memcpy(hw_ip.cpucp_version, prop->cpucp_info.cpucp_version,
* @dram_page_size: The DRAM physical page size.
* @number_of_user_interrupts: The number of interrupts that are available to the userspace
* application to use. Relevant for Gaudi2 and later.
+ * @device_mem_alloc_default_page_size: default page size used in device memory allocation.
*/
struct hl_info_hw_ip_info {
__u64 sram_base_address;
__u32 reserved3;
__u16 number_of_user_interrupts;
__u16 pad2;
+ __u64 reserved4;
+ __u64 device_mem_alloc_default_page_size;
};
struct hl_info_dram_usage {