glsl: Pick ast_conditional branch regardless of op1/2 being constant.

If the ?: operator's condition is a constant value, and both branches
were pure expressions, we can just make the resulting value one or the
other.

Previously, we only did this if op[1] and op[2] were also constant
values - but there's no actual reason for that restriction.

No changes in shader-db, probably because we usually optimize this later
anyway.  But it does make us generate less stupid code up front.

Signed-off-by: Kenneth Graunke <kenneth@whitecape.org>
Reviewed-by: Matt Turner <mattst88@gmail.com>

diff --git a/src/glsl/ast_to_hir.cpp b/src/glsl/ast_to_hir.cpp
index 1ba29f7..4d28069 100644 (file)
--- a/src/glsl/ast_to_hir.cpp
+++ b/src/glsl/ast_to_hir.cpp
@@ -1597,13 +1597,11 @@ ast_expression::do_hir(exec_list *instructions,
       }
 
       ir_constant *cond_val = op[0]->constant_expression_value();
-      ir_constant *then_val = op[1]->constant_expression_value();
-      ir_constant *else_val = op[2]->constant_expression_value();
 
       if (then_instructions.is_empty()
           && else_instructions.is_empty()
-          && (cond_val != NULL) && (then_val != NULL) && (else_val != NULL)) {
-         result = (cond_val->value.b[0]) ? then_val : else_val;
+          && cond_val != NULL) {
+         result = cond_val->value.b[0] ? op[1] : op[2];
       } else {
          ir_variable *const tmp =
             new(ctx) ir_variable(type, "conditional_tmp", ir_var_temporary);