To help the compiler figure out that efi_printk() will not modify
the string it is given, make the input argument type const char*.
While at it, simplify the implementation as well.
Suggested-by: Joe Perches <joe@perches.com>
Signed-off-by: Ard Biesheuvel <ardb@kernel.org>
return !efi_nosoftreserve;
}
-void efi_printk(char *str)
+void efi_printk(const char *str)
{
- char *s8;
-
- for (s8 = str; *s8; s8++) {
- efi_char16_t ch[2] = { 0 };
-
- ch[0] = *s8;
- if (*s8 == '\n') {
- efi_char16_t nl[2] = { '\r', 0 };
- efi_char16_printk(nl);
- }
+ while (*str) {
+ efi_char16_t ch[] = { *str++, L'\0' };
- efi_char16_printk(ch);
+ if (ch[0] == L'\n')
+ efi_char16_printk(L"\r\n");
+ else
+ efi_char16_printk(ch);
}
}
void *get_efi_config_table(efi_guid_t guid);
-void efi_printk(char *str);
+void efi_printk(const char *str);
void efi_free(unsigned long size, unsigned long addr);