Alyssa noticed that when building the kernel with CFI_CLANG+IBT and
booting on IBT enabled hardware to obtain FineIBT, the indirect
functions look like:
__cfi_foo:
endbr64
subl $hash, %r10d
jz 1f
ud2
nop
1:
foo:
endbr64
This is because the compiler generates code for kCFI+IBT. In that case
the caller does the hash check and will jump to +0, so there must be
an ENDBR there. The compiler doesn't know about FineIBT at all; also
it is possible to actually use kCFI+IBT when booting with 'cfi=kcfi'
on IBT enabled hardware.
Having this second ENDBR however makes it possible to elide the CFI
check. Therefore, we should poison this second ENDBR when switching to
FineIBT mode.
Fixes:
931ab63664f0 ("x86/ibt: Implement FineIBT")
Reported-by: "Milburn, Alyssa" <alyssa.milburn@intel.com>
Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org>
Reviewed-by: Kees Cook <keescook@chromium.org>
Reviewed-by: Sami Tolvanen <samitolvanen@google.com>
Link: https://lore.kernel.org/r/20230615193722.194131053@infradead.org
return 0;
}
+static void cfi_rewrite_endbr(s32 *start, s32 *end)
+{
+ s32 *s;
+
+ for (s = start; s < end; s++) {
+ void *addr = (void *)s + *s;
+
+ poison_endbr(addr+16, false);
+ }
+}
+
/* .retpoline_sites */
static int cfi_rand_callers(s32 *start, s32 *end)
{
return;
case CFI_FINEIBT:
+ /* place the FineIBT preamble at func()-16 */
ret = cfi_rewrite_preamble(start_cfi, end_cfi);
if (ret)
goto err;
+ /* rewrite the callers to target func()-16 */
ret = cfi_rewrite_callers(start_retpoline, end_retpoline);
if (ret)
goto err;
+ /* now that nobody targets func()+0, remove ENDBR there */
+ cfi_rewrite_endbr(start_cfi, end_cfi);
+
if (builtin)
pr_info("Using FineIBT CFI\n");
return;