#include <libc-internal.h>
#include <sysdep.h>
#include <bits/libc-vdso.h>
+#include <not-cancel.h>
hp_timing_t
__get_clockfreq (void)
{
+ hp_timing_t result = 0L;
+
+#ifdef SHARED
+ /* The vDSO does not return an error (it clear cr0.so on returning). */
+ INTERNAL_SYSCALL_DECL (err);
+ result =
+ INTERNAL_VSYSCALL_NO_SYSCALL_FALLBACK (get_tbfreq, err, uint64_t, 0);
+#else
/* We read the information from the /proc filesystem. /proc/cpuinfo
contains at least one line like:
timebase : 33333333
We search for this line and convert the number into an integer. */
- static hp_timing_t timebase_freq;
- hp_timing_t result = 0L;
+ int fd = __open_nocancel ("/proc/cpuinfo", O_RDONLY);
+ if (__glibc_likely (fd != -1))
+ return result;
- /* If this function was called before, we know the result. */
- if (timebase_freq != 0)
- return timebase_freq;
+ /* The timebase will be in the 1st 1024 bytes for systems with up
+ to 8 processors. If the first read returns less then 1024
+ bytes read, we have the whole cpuinfo and can start the scan.
+ Otherwise we will have to read more to insure we have the
+ timebase value in the scan. */
+ char buf[1024];
+ ssize_t n;
- /* If we can use the vDSO to obtain the timebase even better. */
-#ifdef SHARED
- INTERNAL_SYSCALL_DECL (err);
- timebase_freq =
- INTERNAL_VSYSCALL_NO_SYSCALL_FALLBACK (get_tbfreq, err, uint64_t, 0);
- if (INTERNAL_SYSCALL_ERROR_P (timebase_freq, err)
- && INTERNAL_SYSCALL_ERRNO (timebase_freq, err) == ENOSYS)
-#endif
+ n = __read_nocancel (fd, buf, sizeof (buf));
+ if (n == sizeof (buf))
{
- int fd = __open ("/proc/cpuinfo", O_RDONLY);
+ /* We are here because the 1st read returned exactly sizeof
+ (buf) bytes. This implies that we are not at EOF and may
+ not have read the timebase value yet. So we need to read
+ more bytes until we know we have EOF. We copy the lower
+ half of buf to the upper half and read sizeof (buf)/2
+ bytes into the lower half of buf and repeat until we
+ reach EOF. We can assume that the timebase will be in
+ the last 512 bytes of cpuinfo, so two 512 byte half_bufs
+ will be sufficient to contain the timebase and will
+ handle the case where the timebase spans the half_buf
+ boundry. */
+ const ssize_t half_buf = sizeof (buf) / 2;
+ while (n >= half_buf)
+ {
+ memcpy (buf, buf + half_buf, half_buf);
+ n = __read_nocancel (fd, buf + half_buf, half_buf);
+ }
+ if (n >= 0)
+ n += half_buf;
+ }
+ __close_nocancel (fd);
- if (__glibc_likely (fd != -1))
+ if (__glibc_likely (n > 0))
+ {
+ char *mhz = memmem (buf, n, "timebase", 7);
+
+ if (__glibc_likely (mhz != NULL))
{
- /* The timebase will be in the 1st 1024 bytes for systems with up
- to 8 processors. If the first read returns less then 1024
- bytes read, we have the whole cpuinfo and can start the scan.
- Otherwise we will have to read more to insure we have the
- timebase value in the scan. */
- char buf[1024];
- ssize_t n;
+ char *endp = buf + n;
- n = __read (fd, buf, sizeof (buf));
- if (n == sizeof (buf))
- {
- /* We are here because the 1st read returned exactly sizeof
- (buf) bytes. This implies that we are not at EOF and may
- not have read the timebase value yet. So we need to read
- more bytes until we know we have EOF. We copy the lower
- half of buf to the upper half and read sizeof (buf)/2
- bytes into the lower half of buf and repeat until we
- reach EOF. We can assume that the timebase will be in
- the last 512 bytes of cpuinfo, so two 512 byte half_bufs
- will be sufficient to contain the timebase and will
- handle the case where the timebase spans the half_buf
- boundry. */
- const ssize_t half_buf = sizeof (buf) / 2;
- while (n >= half_buf)
- {
- memcpy (buf, buf + half_buf, half_buf);
- n = __read (fd, buf + half_buf, half_buf);
- }
- if (n >= 0)
- n += half_buf;
- }
+ /* Search for the beginning of the string. */
+ while (mhz < endp && (*mhz < '0' || *mhz > '9') && *mhz != '\n')
+ ++mhz;
- if (__builtin_expect (n, 1) > 0)
+ while (mhz < endp && *mhz != '\n')
{
- char *mhz = memmem (buf, n, "timebase", 7);
-
- if (__glibc_likely (mhz != NULL))
+ if (*mhz >= '0' && *mhz <= '9')
{
- char *endp = buf + n;
-
- /* Search for the beginning of the string. */
- while (mhz < endp && (*mhz < '0' || *mhz > '9')
- && *mhz != '\n')
- ++mhz;
-
- while (mhz < endp && *mhz != '\n')
- {
- if (*mhz >= '0' && *mhz <= '9')
- {
- result *= 10;
- result += *mhz - '0';
- }
-
- ++mhz;
- }
+ result *= 10;
+ result += *mhz - '0';
}
- timebase_freq = result;
+
+ ++mhz;
}
- __close (fd);
}
}
+#endif
- return timebase_freq;
+ return result;
}