isl_int_set_si(bmap->div[div][1+1+last_var], 0);
isl_int_set(bmap->div[div][0],
bmap->eq[done][1+last_var]);
+ if (progress)
+ *progress = 1;
ISL_F_CLR(bmap, ISL_BASIC_MAP_NORMALIZED);
}
}
unsigned total;
struct isl_ctx *ctx;
+ bmap = isl_basic_map_order_divs(bmap);
if (!bmap || bmap->n_div <= 1)
return bmap;
k = elim_for[l] - 1;
isl_int_set_si(eq.data[1+total_var+k], -1);
isl_int_set_si(eq.data[1+total_var+l], 1);
- eliminate_div(bmap, eq.data, l, 0);
+ eliminate_div(bmap, eq.data, l, 1);
isl_int_set_si(eq.data[1+total_var+k], 0);
isl_int_set_si(eq.data[1+total_var+l], 0);
}
return NULL;
}
+/* Return a map that has the same intersection with "context" as "map"
+ * and that as "simple" as possible.
+ *
+ * If "map" is already the universe, then we cannot make it any simpler.
+ * Similarly, if "context" is the universe, then we cannot exploit it
+ * to simplify "map"
+ * If "map" and "context" are identical to each other, then we can
+ * return the corresponding universe.
+ *
+ * If none of these cases apply, we have to work a bit harder.
+ */
static __isl_give isl_map *map_gist(__isl_take isl_map *map,
__isl_take isl_map *context)
{
+ int equal;
+ int is_universe;
+
+ is_universe = isl_map_plain_is_universe(map);
+ if (is_universe >= 0 && !is_universe)
+ is_universe = isl_map_plain_is_universe(context);
+ if (is_universe < 0)
+ goto error;
+ if (is_universe) {
+ isl_map_free(context);
+ return map;
+ }
+
+ equal = isl_map_plain_is_equal(map, context);
+ if (equal < 0)
+ goto error;
+ if (equal) {
+ isl_map *res = isl_map_universe(isl_map_get_space(map));
+ isl_map_free(map);
+ isl_map_free(context);
+ return res;
+ }
+
context = isl_map_compute_divs(context);
return isl_map_gist_basic_map(map, isl_map_simple_hull(context));
+error:
+ isl_map_free(map);
+ isl_map_free(context);
+ return NULL;
}
__isl_give isl_map *isl_map_gist(__isl_take isl_map *map,
__isl_keep isl_map *map2)
{
int i, j;
+ int disjoint;
+ int intersect;
if (!map1 || !map2)
return -1;
- if (isl_map_plain_is_equal(map1, map2))
- return 0;
+ disjoint = isl_map_plain_is_empty(map1);
+ if (disjoint < 0 || disjoint)
+ return disjoint;
+
+ disjoint = isl_map_plain_is_empty(map2);
+ if (disjoint < 0 || disjoint)
+ return disjoint;
+
+ intersect = isl_map_plain_is_equal(map1, map2);
+ if (intersect < 0 || intersect)
+ return intersect < 0 ? -1 : 0;
for (i = 0; i < map1->n; ++i) {
for (j = 0; j < map2->n; ++j) {
return 1;
}
+/* Are "map1" and "map2" disjoint?
+ *
+ * They are disjoint if they are "obviously disjoint" or if one of them
+ * is empty. Otherwise, they are not disjoint if one of them is universal.
+ * If none of these cases apply, we compute the intersection and see if
+ * the result is empty.
+ */
+int isl_map_is_disjoint(__isl_keep isl_map *map1, __isl_keep isl_map *map2)
+{
+ int disjoint;
+ int intersect;
+ isl_map *test;
+
+ disjoint = isl_map_plain_is_disjoint(map1, map2);
+ if (disjoint < 0 || disjoint)
+ return disjoint;
+
+ disjoint = isl_map_is_empty(map1);
+ if (disjoint < 0 || disjoint)
+ return disjoint;
+
+ disjoint = isl_map_is_empty(map2);
+ if (disjoint < 0 || disjoint)
+ return disjoint;
+
+ intersect = isl_map_plain_is_universe(map1);
+ if (intersect < 0 || intersect)
+ return intersect < 0 ? -1 : 0;
+
+ intersect = isl_map_plain_is_universe(map2);
+ if (intersect < 0 || intersect)
+ return intersect < 0 ? -1 : 0;
+
+ test = isl_map_intersect(isl_map_copy(map1), isl_map_copy(map2));
+ disjoint = isl_map_is_empty(test);
+ isl_map_free(test);
+
+ return disjoint;
+}
+
int isl_set_plain_is_disjoint(__isl_keep isl_set *set1,
__isl_keep isl_set *set2)
{
(struct isl_map *)set2);
}
+/* Are "set1" and "set2" disjoint?
+ */
+int isl_set_is_disjoint(__isl_keep isl_set *set1, __isl_keep isl_set *set2)
+{
+ return isl_map_is_disjoint(set1, set2);
+}
+
int isl_set_fast_is_disjoint(__isl_keep isl_set *set1, __isl_keep isl_set *set2)
{
return isl_set_plain_is_disjoint(set1, set2);
/* Remove divs that are not strictly needed.
* In particular, if a div only occurs positively (or negatively)
* in constraints, then it can simply be dropped.
- * Also, if a div occurs only occurs in two constraints and if moreover
+ * Also, if a div occurs in only two constraints and if moreover
* those two constraints are opposite to each other, except for the constant
* term and if the sum of the constant terms is such that for any value
* of the other values, there is always at least one integer value of the
* the (absolute value) of the coefficent of the div in the constraints,
* then we can also simply drop the div.
*
+ * We skip divs that appear in equalities or in the definition of other divs.
+ * Divs that appear in the definition of other divs usually occur in at least
+ * 4 constraints, but the constraints may have been simplified.
+ *
* If any divs are left after these simple checks then we move on
* to more complicated cases in drop_more_redundant_divs.
*/
int defined;
defined = !isl_int_is_zero(bmap->div[i][0]);
+ for (j = i; j < bmap->n_div; ++j)
+ if (!isl_int_is_zero(bmap->div[j][1 + 1 + off + i]))
+ break;
+ if (j < bmap->n_div)
+ continue;
for (j = 0; j < bmap->n_eq; ++j)
if (!isl_int_is_zero(bmap->eq[j][1 + off + i]))
break;
projects / platform / upstream / isl.git / blobdiff