- n = __read (fd, buf, sizeof (buf));
- if (n == sizeof (buf))
- {
- /* We are here because the 1st read returned exactly sizeof
- (buf) bytes. This implies that we are not at EOF and may
- not have read the timebase value yet. So we need to read
- more bytes until we know we have EOF. We copy the lower
- half of buf to the upper half and read sizeof (buf)/2
- bytes into the lower half of buf and repeat until we
- reach EOF. We can assume that the timebase will be in
- the last 512 bytes of cpuinfo, so two 512 byte half_bufs
- will be sufficient to contain the timebase and will
- handle the case where the timebase spans the half_buf
- boundry. */
- const ssize_t half_buf = sizeof (buf) / 2;
- while (n >= half_buf)
- {
- memcpy (buf, buf + half_buf, half_buf);
- n = __read (fd, buf + half_buf, half_buf);
- }
- if (n >= 0)
- n += half_buf;
- }
+ /* Search for the beginning of the string. */
+ while (mhz < endp && (*mhz < '0' || *mhz > '9') && *mhz != '\n')
+ ++mhz;