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41 File Name: 15.8.2.15.js
42 ECMA Section: 15.8.2.15 Math.round(x)
43 Description: return the greatest number value that is closest to the
44 argument and is an integer. if two integers are equally
45 close to the argument. then the result is the number value
46 that is closer to Infinity. if the argument is an integer,
49 - if x is NaN return NaN
52 - if x = Infinity return Infinity
53 - if x = -Infinity return -Infinity
54 - if 0 < x < 0.5 return 0
55 - if -0.5 <= x < 0 return -0
57 Math.round( 3.5 ) == 4
58 Math.round( -3.5 ) == 3
60 - Math.round(x) == Math.floor( x + 0.5 )
61 except if x = -0. in that case, Math.round(x) = -0
63 and Math.floor( x+0.5 ) = +0
66 Author: christine@netscape.com
70 var SECTION = "15.8.2.15";
71 var VERSION = "ECMA_1";
72 var TITLE = "Math.round(x)";
73 var BUGNUMBER="331411";
79 writeHeaderToLog( SECTION + " "+ TITLE);
81 new TestCase( SECTION,
86 new TestCase( SECTION,
91 new TestCase( SECTION,
96 new TestCase( SECTION,
101 new TestCase( SECTION,
106 new TestCase( SECTION,
111 new TestCase( SECTION,
112 "Math.round('.99999')",
114 Math.round('.99999') );
116 new TestCase( SECTION,
117 "Math.round('12345e-2')",
119 Math.round('12345e-2') );
121 new TestCase( SECTION,
124 Math.round(Number.NaN) );
126 new TestCase( SECTION,
131 new TestCase( SECTION,
136 new TestCase( SECTION,
137 "Infinity/Math.round(-0)",
139 Infinity/Math.round(-0) );
141 new TestCase( SECTION,
142 "Math.round(Infinity)",
143 Number.POSITIVE_INFINITY,
144 Math.round(Number.POSITIVE_INFINITY));
146 new TestCase( SECTION,
147 "Math.round(-Infinity)",
148 Number.NEGATIVE_INFINITY,
149 Math.round(Number.NEGATIVE_INFINITY));
151 new TestCase( SECTION,
156 new TestCase( SECTION,
161 new TestCase( SECTION,
166 new TestCase( SECTION,
171 new TestCase( SECTION,
176 new TestCase( SECTION,
177 "Infinity/Math.round(-0.49)",
179 Infinity/Math.round(-0.49));
181 new TestCase( SECTION,
182 "Infinity/Math.round(-0.5)",
184 Infinity/Math.round(-0.5));
186 new TestCase( SECTION,
191 new TestCase( SECTION,
196 new TestCase( SECTION,