1 # Frequently Asked Questions Cryptsetup/LUKS
4 [1. General Questions](#1-general-questions)
6 [3. Common Problems](#3-common-problems)
7 [4. Troubleshooting](#4-troubleshooting)
8 [5. Security Aspects](#5-security-aspects)
9 [6. Backup and Data Recovery](#6-backup-and-data-recovery)
10 [7. Interoperability with other Disk Encryption Tools](#7-interoperability-with-other-disk-encryption-tools)
11 [8. Issues with Specific Versions of cryptsetup](#8-issues-with-specific-versions-of-cryptsetup)
12 [9. The Initrd question](#9-the-initrd-question)
13 [10. LUKS2 Questions](#10-luks2-questions)
14 [11. References and Further Reading](#11-references-and-further-reading)
15 [A. Contributors](#a-contributors)
17 # 1. General Questions
20 * **1.1 What is this?**
22 This is the FAQ (Frequently Asked Questions) for cryptsetup. It covers
23 Linux disk encryption with plain dm-crypt (one passphrase, no
24 management, no metadata on disk) and LUKS (multiple user keys with one
25 volume key, anti-forensic features, metadata block at start of device,
26 ...). The latest version of this FAQ should usually be available at
27 https://gitlab.com/cryptsetup/cryptsetup/wikis/FrequentlyAskedQuestions
32 LUKS2 COMPATIBILITY: This FAQ was originally written for LUKS1, not
33 LUKS2. Hence regarding LUKS2, some of the answers found here may not
34 apply. Updates for LUKS2 have been done and anything not applying to
35 LUKS2 should clearly say LUKS1. However, this is a Frequently Asked
36 Questions, and questions for LUKS2 are limited at this time or at least
37 those that have reached me are. In the following, "LUKS" refers to both
40 The LUKS1 on-disk format specification is at
41 https://www.kernel.org/pub/linux/utils/cryptsetup/LUKS_docs/on-disk-format.pdf
42 The LUKS2 on-disk format specification is at
43 https://gitlab.com/cryptsetup/LUKS2-docs
45 ATTENTION: If you are going to read just one thing, make it the section
46 on Backup and Data Recovery. By far the most questions on the
47 cryptsetup mailing list are from people that managed to damage the start
48 of their LUKS partitions, i.e. the LUKS header. In most cases, there
49 is nothing that can be done to help these poor souls recover their data.
50 Make sure you understand the problem and limitations imposed by the LUKS
51 security model BEFORE you face such a disaster! In particular, make
52 sure you have a current header backup before doing any potentially
53 dangerous operations. The LUKS2 header should be a bit more resilient
54 as critical data starts later and is stored twice, but you can decidedly
55 still destroy it or a keyslot permanently by accident.
57 DEBUG COMMANDS: While the --debug and --debug-json options should not
58 leak secret data, "strace" and the like can leak your full passphrase.
59 Do not post an strace output with the correct passphrase to a
60 mailing-list or online! See Item 4.5 for more explanation.
62 SSDs/FLASH DRIVES: SSDs and Flash are different. Currently it is
63 unclear how to get LUKS or plain dm-crypt to run on them with the full
64 set of security assurances intact. This may or may not be a problem,
65 depending on the attacker model. See Section 5.19.
67 BACKUP: Yes, encrypted disks die, just as normal ones do. A full backup
68 is mandatory, see Section "6. Backup and Data Recovery" on options for
69 doing encrypted backup.
71 CLONING/IMAGING: If you clone or image a LUKS container, you make a copy
72 of the LUKS header and the volume key will stay the same! That means
73 that if you distribute an image to several machines, the same volume key
74 will be used on all of them, regardless of whether you change the
75 passphrases. Do NOT do this! If you do, a root-user on any of the
76 machines with a mapped (decrypted) container or a passphrase on that
77 machine can decrypt all other copies, breaking security. See also Item
80 DISTRIBUTION INSTALLERS: Some distribution installers offer to create
81 LUKS containers in a way that can be mistaken as activation of an
82 existing container. Creating a new LUKS container on top of an existing
83 one leads to permanent, complete and irreversible data loss. It is
84 strongly recommended to only use distribution installers after a
85 complete backup of all LUKS containers has been made.
87 UBUNTU INSTALLER: In particular the Ubuntu installer seems to be quite
88 willing to kill LUKS containers in several different ways. Those
89 responsible at Ubuntu seem not to care very much (it is very easy to
90 recognize a LUKS container), so treat the process of installing Ubuntu
91 as a severe hazard to any LUKS container you may have.
93 NO WARNING ON NON-INTERACTIVE FORMAT: If you feed cryptsetup from STDIN
94 (e.g. via GnuPG) on LUKS format, it does not give you the warning that
95 you are about to format (and e.g. will lose any pre-existing LUKS
96 container on the target), as it assumes it is used from a script. In
97 this scenario, the responsibility for warning the user and possibly
98 checking for an existing LUKS header is shifted to the script. This is
99 a more general form of the previous item.
101 LUKS PASSPHRASE IS NOT THE VOLUME KEY: The LUKS passphrase is not used
102 in deriving the volume key. It is used in decrypting a volume key that
103 is randomly selected on header creation. This means that if you create
104 a new LUKS header on top of an old one with exactly the same parameters
105 and exactly the same passphrase as the old one, it will still have a
106 different volume key and your data will be permanently lost.
108 PASSPHRASE CHARACTER SET: Some people have had difficulties with this
109 when upgrading distributions. It is highly advisable to only use the 95
110 printable characters from the first 128 characters of the ASCII table,
111 as they will always have the same binary representation. Other
112 characters may have different encoding depending on system configuration
113 and your passphrase will not work with a different encoding. A table of
114 the standardized first 128 ASCII characters can, e.g. be found on
115 https://en.wikipedia.org/wiki/ASCII
117 KEYBOARD NUM-PAD: Apparently some pre-boot authentication environments
118 (these are done by the distro, not by cryptsetup, so complain there)
119 treat digits entered on the num-pad and ones entered regularly
120 different. This may be because the BIOS USB keyboard driver is used and
121 that one may have bugs on some computers. If you cannot open your
122 device in pre-boot, try entering the digits over the regular digit keys.
125 * **1.3 System specific warnings**
127 - The Ubuntu Natty uinstaller has a "won't fix" defect that may destroy
128 LUKS containers. This is quite old an not relevant for most people.
130 https://bugs.launchpad.net/ubuntu/+source/partman-crypto/+bug/420080
133 * **1.4 My LUKS-device is broken! Help!**
135 First: Do not panic! In many cases the data is still recoverable.
136 Do not do anything hasty! Steps:
138 - Take some deep breaths. Maybe add some relaxing music. This may
139 sound funny, but I am completely serious. Often, critical damage is
140 done only after the initial problem.
142 - Do not reboot. The keys may still be in the kernel if the device is
145 - Make sure others do not reboot the system.
147 - Do not write to your disk without a clear understanding why this will
148 not make matters worse. Do a sector-level backup before any writes.
149 Often you do not need to write at all to get enough access to make a
154 - Read section 6 of this FAQ.
156 - Ask on the mailing-list if you need more help.
159 * **1.5 Who wrote this?**
161 Current FAQ maintainer is Arno Wagner <arno@wagner.name>. If you want
162 to send me encrypted email, my current PGP key is DSA key CB5D9718,
163 fingerprint 12D6 C03B 1B30 33BB 13CF B774 E35C 5FA1 CB5D 9718.
165 Other contributors are listed at the end. If you want to contribute,
166 send your article, including a descriptive headline, to the maintainer,
167 or the dm-crypt mailing list with something like "FAQ ..."
168 in the subject. You can also send more raw information and have
169 me write the section. Please note that by contributing to this FAQ,
170 you accept the license described below.
172 This work is under the "Attribution-Share Alike 3.0 Unported" license,
173 which means distribution is unlimited, you may create derived works, but
174 attributions to original authors and this license statement must be
175 retained and the derived work must be under the same license. See
176 https://creativecommons.org/licenses/by-sa/3.0/ for more details of the
179 Side note: I did text license research some time ago and I think this
180 license is best suited for the purpose at hand and creates the least
184 * **1.6 Where is the project website?**
186 There is the project website at
187 https://gitlab.com/cryptsetup/cryptsetup/ Please do not post
188 questions there, nobody will read them. Use the mailing-list
192 * **1.7 Is there a mailing-list?**
194 Instructions on how to subscribe to the mailing-list are on the
195 project website. People are generally helpful and friendly on the
198 The question of how to unsubscribe from the list does crop up sometimes.
199 For this you need your list management URL
200 https://subspace.kernel.org/lists.linux.dev.html. Go to the URL mentioned
201 in the email and select "unsubscribe".
203 Alternatively, you can send an empty Email to cryptsetup+help@lists.linux.dev.
204 Make sure to send it from your list address.
206 The mailing list archive is here:
207 https://lore.kernel.org/cryptsetup/
209 The legacy dm-crypt mailing list archive is here:
210 https://lore.kernel.org/dm-crypt/
213 * **1.8 Unsubscribe from the mailing-list**
215 Send mail to cryptsetup+unsubscribe@lists.linux.dev from the subscribed account.
216 You will get an email with instructions.
218 Basically, you just have to respond to it unmodified to get
219 unsubscribed. The listserver admin functions are not very fast. It can
220 take 15 minutes or longer for a reply to arrive (I suspect greylisting
221 is in use), so be patient.
223 Also note that nobody on the list can unsubscribe you, sending demands
224 to be unsubscribed to the list just annoys people that are entirely
225 blameless for you being subscribed.
227 If you are subscribed, a subscription confirmation email was sent to
228 your email account and it had to be answered before the subscription
229 went active. The confirmation emails from the listserver have subjects
230 like these (with other numbers):
232 Subject: Confirm subscription to cryptsetup@lists.linux.dev
234 and are sent from cryptsetup+help@lists.linux.dev. You should check whether
235 you have anything like it in your sent email folder. If you find
236 nothing and are sure you did not confirm, then you should look into a
237 possible compromise of your email account.
239 * **1.9 What can I do if cryptsetup is running out of memory?**
241 Memory issues are generally related to the key derivation function. You may
242 be able to tune usage with the options --pbkdf-memory or --pbkdf pbkdf2.
245 * **1.10 Can cryptsetup be run without root access?**
247 Elevated privileges are required to use cryptsetup and LUKS. Some operations
248 require root access. There are a few features which will work without root
249 access with the right switches but there are caveats.
252 * **1.11 What are the problems with running as non root?**
254 The first issue is one of permissions to devices. Generally, root or a group
255 such as disk has ownership of the storage devices. The non root user will
256 need write access to the block device used for LUKS.
258 Next, file locking is managed in /run/cryptsetup. You may use
259 --disable-locks but cryptsetup will no longer protect you from race
260 conditions and problems with concurrent access to the same devices.
262 Also, device mapper requires root access. cryptsetup uses device mapper to
263 manage the decrypted container.
265 * **1.12 How can I report an issue in the cryptsetup project?**
267 Before reporting any issue, please be sure you are using the latest
268 upstream version and that you read the documentation (and this FAQ).
270 If you think you have discovered an issue, please report it through
271 the project issue tracker [New issue](https://gitlab.com/cryptsetup/cryptsetup/issues).
272 For a possible security issue, please use the confidential checkbox.
274 Please fill in all information requested in the report template
275 (specifically add debug output with all run environment data).
276 Do not trim the output; debug output does not include private data.
281 * **2.1 LUKS Container Setup mini-HOWTO**
283 This item tries to give you a very brief list of all the steps you
284 should go through when creating a new LUKS encrypted container, i.e.
285 encrypted disk, partition or loop-file.
287 01) All data will be lost, if there is data on the target, make a
290 02) Make very sure you use the right target disk, partition or
293 03) If the target was in use previously, it is a good idea to wipe it
294 before creating the LUKS container in order to remove any trace of old
295 file systems and data. For example, some users have managed to run
296 e2fsck on a partition containing a LUKS container, possibly because of
297 residual ext2 superblocks from an earlier use. This can do arbitrary
298 damage up to complete and permanent loss of all data in the LUKS
301 To just quickly wipe file systems (old data may remain), use
303 wipefs -a <target device>
305 To wipe file system and data, use something like
307 cat /dev/zero > <target device>
309 This can take a while. To get a progress indicator, you can use the
310 tool dd_rescue (->google) instead or use my stream meter "wcs" (source
311 here: https://www.tansi.org/tools/index.html) in the following fashion:
313 cat /dev/zero | wcs > <target device>
315 Plain "dd" also gives you the progress on a SIGUSR1, see its man-page.
316 The GNU "dd" command supports the "status=progress" operand that gives you
317 the progress without having to send it any signal.
319 Be very sure you have the right target, all data will be lost!
321 Note that automatic wiping is on the TODO list for cryptsetup, so at
322 some time in the future this will become unnecessary.
324 Alternatively, plain dm-crypt can be used for a very fast wipe with
325 crypto-grade randomness, see Item 2.19
327 04) Create the LUKS container.
331 cryptsetup luksFormat --type luks1 <target device>
335 cryptsetup luksFormat --type luks2 <target device>
338 Just follow the on-screen instructions.
340 Note: Passphrase iteration count is based on time and hence security
341 level depends on CPU power of the system the LUKS container is created
342 on. For example on a Raspberry Pi and LUKS1, I found some time ago that
343 the iteration count is 15 times lower than for a regular PC (well, for
344 my old one). Depending on security requirements, this may need
345 adjustment. For LUKS1, you can just look at the iteration count on
346 different systems and select one you like. You can also change the
347 benchmark time with the -i parameter to create a header for a slower
350 For LUKS2, the parameters are more complex. ARGON2 has iteration,
351 parallelism and memory parameter. cryptsetup actually may adjust the
352 memory parameter for time scaling. Hence to use -i is the easiest way
353 to get slower or faster opening (default: 2000 = 2sec). Just make sure
354 to not drop this too low or you may get a memory parameter that is to
355 small to be secure. The luksDump command lists the memory parameter of
356 a created LUKS2 keyslot in kB. That parameter should probably be not
357 much lower than 100000, i.e. 100MB, but don't take my word for it.
359 05) Map the container. Here it will be mapped to /dev/mapper/c1:
361 cryptsetup luksOpen <target device> c1
363 06) (Optionally) wipe the container (make sure you have the right
366 cat /dev/zero > /dev/mapper/c1
368 This will take a while. Note that this creates a small information
369 leak, as an attacker can determine whether a 512 byte block is zero if
370 the attacker has access to the encrypted container multiple times.
371 Typically a competent attacker that has access multiple times can
372 install a passphrase sniffer anyways, so this leakage is not very
373 significant. For getting a progress indicator, see step 03.
375 07) Create a file system in the mapped container, for example an
376 ext3 file system (any other file system is possible):
378 mke2fs -j /dev/mapper/c1
380 08) Mount your encrypted file system, here on /mnt:
382 mount /dev/mapper/c1 /mnt
384 09) Make a LUKS header backup and plan for a container backup.
385 See Section 6 for details.
387 Done. You can now use the encrypted file system to store data. Be sure
388 to read through the rest of the FAQ, these are just the very basics. In
389 particular, there are a number of mistakes that are easy to make, but
390 will compromise your security.
393 * **2.2 LUKS on partitions or raw disks? What about RAID?**
396 This is a complicated question, and made more so by the availability of
397 RAID and LVM. I will try to give some scenarios and discuss advantages
398 and disadvantages. Note that I say LUKS for simplicity, but you can do
399 all the things described with plain dm-crypt as well. Also note that
400 your specific scenario may be so special that most or even all things I
401 say below do not apply.
403 Be aware that if you add LVM into the mix, things can get very
404 complicated. Same with RAID but less so. In particular, data recovery
405 can get exceedingly difficult. Only add LVM if you have a really good
406 reason and always remember KISS is what separates an engineer from an
407 amateur. Of course, if you really need the added complexity, KISS is
408 satisfied. But be very sure as there is a price to pay for it. In
409 engineering, complexity is always the enemy and needs to be fought
410 without mercy when encountered.
412 Also consider using RAID instead of LVM, as at least with the old
413 superblock format 0.90, the RAID superblock is in the place (end of
414 disk) where the risk of it damaging the LUKS header is smallest and you
415 can have your array assembled by the RAID controller (i.e. the kernel),
416 as it should be. Use partition type 0xfd for that. I recommend staying
417 away from superblock formats 1.0, 1.1 and 1.2 unless you really need
422 (1) Encrypted partition: Just make a partition to your liking, and put
423 LUKS on top of it and a filesystem into the LUKS container. This gives
424 you isolation of differently-tasked data areas, just as ordinary
425 partitioning does. You can have confidential data, non-confidential
426 data, data for some specific applications, user-homes, root, etc.
427 Advantages are simplicity as there is a 1:1 mapping between partitions
428 and filesystems, clear security functionality and the ability to
429 separate data into different, independent (!) containers.
431 Note that you cannot do this for encrypted root, that requires an
432 initrd. On the other hand, an initrd is about as vulnerable to a
433 competent attacker as a non-encrypted root, so there really is no
434 security advantage to doing it that way. An attacker that wants to
435 compromise your system will just compromise the initrd or the kernel
436 itself. The better way to deal with this is to make sure the root
437 partition does not store any critical data and to move that to
438 additional encrypted partitions. If you really are concerned your root
439 partition may be sabotaged by somebody with physical access (who would
440 however strangely not, say, sabotage your BIOS, keyboard, etc.), protect
441 it in some other way. The PC is just not set-up for a really secure
442 boot-chain (whatever some people may claim).
444 That said, if you want an encrypted root partition, you have to store
445 an initrd with cryptsetup somewhere else. The traditional approach is
446 to have a separate partition under /boot for that. You can also put that
447 initrd on a bootable memory stick, bootable CD or bootable external
448 drive as well. The kernel and Grub typically go to the same location
449 as that initrd. A minimal example what such an initrd can look like is
452 (2) Fully encrypted raw block device: For this, put LUKS on the raw
453 device (e.g. /dev/sdb) and put a filesystem into the LUKS container, no
454 partitioning whatsoever involved. This is very suitable for things like
455 external USB disks used for backups or offline data-storage.
457 (3) Encrypted RAID: Create your RAID from partitions and/or full
458 devices. Put LUKS on top of the RAID device, just if it were an
459 ordinary block device. Applications are just the same as above, but you
460 get redundancy. (Side note as many people seem to be unaware of it: You
461 can do RAID1 with an arbitrary number of components in Linux.) See also
464 (4) Now, some people advocate doing the encryption below the RAID layer.
465 That has several serious problems. One is that suddenly debugging RAID
466 issues becomes much harder. You cannot do automatic RAID assembly
467 anymore. You need to keep the encryption keys for the different RAID
468 components in sync or manage them somehow. The only possible advantage
469 is that things may run a little faster as more CPUs do the encryption,
470 but if speed is a priority over security and simplicity, you are doing
471 this wrong anyways. A good way to mitigate a speed issue is to get a
472 CPU that does hardware AES as most do today.
475 * **2.3 How do I set up encrypted swap?**
477 As things that are confidential can end up in swap (keys, passphrases,
478 etc. are usually protected against being swapped to disk, but other
479 things may not be), it may be advisable to do something about the issue.
480 One option is to run without swap, which generally works well in a
481 desktop-context. It may cause problems in a server-setting or under
482 special circumstances. The solution to that is to encrypt swap with a
483 random key at boot-time.
485 NOTE: This is for Debian, and should work for Debian-derived
486 distributions. For others you may have to write your own startup script
487 or use other mechanisms.
489 01) Add the swap partition to /etc/crypttab. A line like the
490 following should do it:
492 swap /dev/<partition> /dev/urandom swap,noearly
494 Warning: While Debian refuses to overwrite partitions with a filesystem
495 or RAID signature on it, as your disk IDs may change (adding or removing
496 disks, failure of disk during boot, etc.), you may want to take
497 additional precautions. Yes, this means that your kernel device names
498 like sda, sdb, ... can change between reboots! This is not a concern
499 if you have only one disk. One possibility is to make sure the
500 partition number is not present on additional disks or also swap there.
501 Another is to encapsulate the swap partition (by making it a 1-partition
502 RAID1 or by using LVM), as that gets a persistent identifier.
503 Specifying it directly by UUID does not work, unfortunately, as the UUID
504 is part of the swap signature and that is not visible from the outside
505 due to the encryption and in addition changes on each reboot with this
508 Note: Use /dev/random if you are paranoid or in a potential low-entropy
509 situation (embedded system, etc.). This may cause the operation to take
510 a long time during boot however. If you are in a "no entropy"
511 situation, you cannot encrypt swap securely. In this situation you
512 should find some entropy, also because nothing else using crypto will be
513 secure, like ssh, ssl or GnuPG.
515 Note: The "noearly" option makes sure things like LVM, RAID, etc. are
516 running. As swap is non-critical for boot, it is fine to start it late.
518 02) Add the swap partition to /etc/fstab. A line like the following
521 /dev/mapper/swap none swap sw 0 0
523 That is it. Reboot or start it manually to activate encrypted swap.
524 Manual start would look like this:
526 /etc/init.d/cryptdisks start
527 swapon /dev/mapper/swap
530 * **2.4 What is the difference between "plain" and LUKS format?**
532 First, unless you happen to understand the cryptographic background
533 well, you should use LUKS. It does protect the user from a lot of
534 common mistakes. Plain dm-crypt is for experts.
536 Plain format is just that: It has no metadata on disk, reads all
537 parameters from the commandline (or the defaults), derives a volume-key
538 from the passphrase and then uses that to de-/encrypt the sectors of the
539 device, with a direct 1:1 mapping between encrypted and decrypted
542 Primary advantage is high resilience to damage, as one damaged encrypted
543 sector results in exactly one damaged decrypted sector. Also, it is not
544 readily apparent that there even is encrypted data on the device, as an
545 overwrite with crypto-grade randomness (e.g. from
546 /dev/urandom) looks exactly the same on disk.
548 Side-note: That has limited value against the authorities. In civilized
549 countries, they cannot force you to give up a crypto-key anyways. In
550 quite a few countries around the world, they can force you to give up
551 the keys (using imprisonment or worse to pressure you, sometimes without
552 due process), and in the worst case, they only need a nebulous
553 "suspicion" about the presence of encrypted data. Sometimes this
554 applies to everybody, sometimes only when you are suspected of having
555 "illicit data" (definition subject to change) and sometimes specifically
556 when crossing a border. Note that this is going on in countries like
557 the US and the UK to different degrees and sometimes with courts
558 restricting what the authorities can actually demand.
560 My advice is to either be ready to give up the keys or to not have
561 encrypted data when traveling to those countries, especially when
562 crossing the borders. The latter also means not having any high-entropy
563 (random) data areas on your disk, unless you can explain them and
564 demonstrate that explanation. Hence doing a zero-wipe of all free
565 space, including unused space, may be a good idea.
567 Disadvantages are that you do not have all the nice features that the
568 LUKS metadata offers, like multiple passphrases that can be changed, the
569 cipher being stored in the metadata, anti-forensic properties like
570 key-slot diffusion and salts, etc..
572 LUKS format uses a metadata header and 8 key-slot areas that are being
573 placed at the beginning of the disk, see below under "What does the LUKS
574 on-disk format looks like?". The passphrases are used to decrypt a
575 single volume key that is stored in the anti-forensic stripes. LUKS2
576 adds some more flexibility.
578 Advantages are a higher usability, automatic configuration of
579 non-default crypto parameters, defenses against low-entropy passphrases
580 like salting and iterated PBKDF2 or ARGON 2 passphrase hashing, the
581 ability to change passphrases, and others.
583 Disadvantages are that it is readily obvious there is encrypted data on
584 disk (but see side note above) and that damage to the header or
585 key-slots usually results in permanent data-loss. See below under "6.
586 Backup and Data Recovery" on how to reduce that risk. Also the sector
587 numbers get shifted by the length of the header and key-slots and there
588 is a loss of that size in capacity. Unless you have a specific need,
592 * **2.5 Can I encrypt an existing, non-empty partition to use LUKS?**
594 There is no converter, and it is not really needed. The way to do this
595 is to make a backup of the device in question, securely wipe the device
596 (as LUKS device initialization does not clear away old data), do a
597 luksFormat, optionally overwrite the encrypted device, create a new
598 filesystem and restore your backup on the now encrypted device. Also
599 refer to sections "Security Aspects" and "Backup and Data Recovery".
601 For backup, plain GNU tar works well and backs up anything likely to be
605 * **2.6 How do I use LUKS with a loop-device?**
607 This can be very handy for experiments. Setup is just the same as with
608 any block device. If you want, for example, to use a 100MiB file as
609 LUKS container, do something like this:
611 head -c 100M /dev/zero > luksfile # create empty file
612 losetup /dev/loop0 luksfile # map file to /dev/loop0
613 cryptsetup luksFormat --type luks2 /dev/loop0 # create LUKS2 container
615 Afterwards just use /dev/loop0 as a you would use a LUKS partition.
616 To unmap the file when done, use "losetup -d /dev/loop0".
619 * **2.7 When I add a new key-slot to LUKS, it asks for a passphrase but then complains about there not being a key-slot with that passphrase?**
621 That is as intended. You are asked a passphrase of an existing key-slot
622 first, before you can enter the passphrase for the new key-slot.
623 Otherwise you could break the encryption by just adding a new key-slot.
624 This way, you have to know the passphrase of one of the already
625 configured key-slots in order to be able to configure a new key-slot.
628 * **2.8 Encryption on top of RAID or the other way round?**
631 Unless you have special needs, place encryption between RAID and
632 filesystem, i.e. encryption on top of RAID. You can do it the other
633 way round, but you have to be aware that you then need to give the
634 passphrase for each individual disk and RAID auto-detection will not
635 work anymore. Therefore it is better to encrypt the RAID device, e.g.
638 This means that the typical layering looks like this:
646 Raw partitions (optional)
650 The big advantage of this is that you can manage the RAID container just
651 like any other regular RAID container, it does not care that its content
652 is encrypted. This strongly cuts down on complexity, something very
653 valuable with storage encryption.
655 Try to avoid so-called fake RAID (RAID configured from BIOS but handled
656 by proprietary drivers). Note that some fake RAID firmware automatically
657 writes signature on disks if enabled. This causes corruption of LUKS
658 metadata. Be sure to switch the RAID option off in BIOS if you do not
661 Another data corruption can happen if you resize (enlarge) the underlying
662 device and some remnant metadata appear near the end of the resized device
663 (like a secondary copy of the GPT table). You can use wipefs command to
664 detect and wipe such signatures.
667 * **2.9 How do I read a dm-crypt key from file?**
669 Use the --key-file option, like this:
671 cryptsetup create --key-file keyfile e1 /dev/loop0
673 This will read the binary key from file, i.e. no hashing or
674 transformation will be applied to the keyfile before its bits are used
675 as key. Extra bits (beyond the length of the key) at the end are
676 ignored. Note that if you read from STDIN, the data will be hashed,
677 just as a key read interactively from the terminal. See the man-page
678 sections "NOTES ON PASSPHRASE PROCESSING..." for more detail.
681 * **2.10 How do I read a LUKS slot key from file?**
683 What you really do here is to read a passphrase from file, just as you
684 would with manual entry of a passphrase for a key-slot. You can add a
685 new passphrase to a free key-slot, set the passphrase of an specific
686 key-slot or put an already configured passphrase into a file. Make sure
687 no trailing newline (0x0a) is contained in the input key file, or the
688 passphrase will not work because the whole file is used as input.
690 To add a new passphrase to a free key slot from file, use something
693 cryptsetup luksAddKey /dev/loop0 keyfile
695 To add a new passphrase to a specific key-slot, use something
698 cryptsetup luksAddKey --key-slot 7 /dev/loop0 keyfile
700 To supply a key from file to any LUKS command, use the --key-file
701 option, e.g. like this:
703 cryptsetup luksOpen --key-file keyfile /dev/loop0 e1
707 * **2.11 How do I read the LUKS volume key from file?**
709 The question you should ask yourself first is why you would want to do
710 this. The only legitimate reason I can think of is if you want to have
711 two LUKS devices with the same volume key. Even then, I think it would
712 be preferable to just use key-slots with the same passphrase, or to use
713 plain dm-crypt instead. If you really have a good reason, please tell
714 me. If I am convinced, I will add how to do this here.
717 * **2.12 What are the security requirements for a key read from file?**
719 A file-stored key or passphrase has the same security requirements as
720 one entered interactively, however you can use random bytes and thereby
721 use bytes you cannot type on the keyboard. You can use any file you
722 like as key file, for example a plain text file with a human readable
723 passphrase. To generate a file with random bytes, use something like
726 head -c 256 /dev/random > keyfile
730 * **2.13 If I map a journaled file system using dm-crypt/LUKS, does it still provide its usual transactional guarantees?**
732 Yes, it does, unless a very old kernel is used. The required flags come
733 from the filesystem layer and are processed and passed onward by
734 dm-crypt (regardless of direct key management or LUKS key management).
735 A bit more information on the process by which transactional guarantees
736 are implemented can be found here:
738 https://lwn.net/Articles/400541/
740 Please note that these "guarantees" are weaker than they appear to be.
741 One problem is that quite a few disks lie to the OS about having flushed
742 their buffers. This is likely still true with SSDs. Some other things
743 can go wrong as well. The filesystem developers are aware of these
744 problems and typically can make it work anyways. That said,
745 dm-crypt/LUKS will not make things worse.
747 One specific problem you can run into is that you can get short freezes
748 and other slowdowns due to the encryption layer. Encryption takes time
749 and forced flushes will block for that time. For example, I did run
750 into frequent small freezes (1-2 sec) when putting a vmware image on
751 ext3 over dm-crypt. When I went back to ext2, the problem went away.
752 This seems to have gotten better with kernel 2.6.36 and the reworking of
753 filesystem flush locking mechanism (less blocking of CPU activity during
754 flushes). This should improve further and eventually the problem should
758 * **2.14 Can I use LUKS or cryptsetup with a more secure (external) medium for key storage, e.g. TPM or a smartcard?**
760 Yes, see the answers on using a file-supplied key. You do have to write
761 the glue-logic yourself though. Basically you can have cryptsetup read
762 the key from STDIN and write it there with your own tool that in turn
763 gets the key from the more secure key storage.
766 * **2.15 Can I resize a dm-crypt or LUKS container?**
768 Yes, you can, as neither dm-crypt nor LUKS1 stores partition size and
769 LUKS2 uses a generic "whole device" size as default. Note that LUKS2
770 can use specified data-area sizes as a non-standard case and that these
771 may cause issues when resizing a LUKS2 container if set to a specific
774 Whether you should do this is a different question. Personally I
775 recommend backup, recreation of the dm-crypt or LUKS container with new
776 size, recreation of the filesystem and restore. This gets around the
777 tricky business of resizing the filesystem. Resizing a dm-crypt or LUKS
778 container does not resize the filesystem in it. A backup is really
779 non-optional here, as a lot can go wrong, resulting in partial or
780 complete data loss. But if you have that backup, you can also just
783 You also need to be aware of size-based limitations. The one currently
784 relevant is that aes-xts-plain should not be used for encrypted
785 container sizes larger than 2TiB. Use aes-xts-plain64 for that.
788 * **2.16 How do I Benchmark the Ciphers, Hashes and Modes?**
790 Since version 1.60 cryptsetup supports the "benchmark" command.
795 You can get more than the default benchmarks, see the man-page for the
796 relevant parameters. Note that XTS mode takes two keys, hence the
797 listed key sizes are double that for other modes and half of it is the
798 cipher key, the other half is the XTS key.
801 * **2.17 How do I Verify I have an Authentic cryptsetup Source Package?**
803 Current maintainer is Milan Broz and he signs the release packages with
804 his PGP key. The key he currently uses is the "RSA key ID D93E98FC",
805 fingerprint 2A29 1824 3FDE 4664 8D06 86F9 D9B0 577B D93E 98FC. While I
806 have every confidence this really is his key and that he is who he
807 claims to be, don't depend on it if your life is at stake. For that
808 matter, if your life is at stake, don't depend on me being who I claim
811 That said, as cryptsetup is under good version control and a malicious
812 change should be noticed sooner or later, but it may take a while.
813 Also, the attacker model makes compromising the sources in a non-obvious
814 way pretty hard. Sure, you could put the volume-key somewhere on disk,
815 but that is rather obvious as soon as somebody looks as there would be
816 data in an empty LUKS container in a place it should not be. Doing this
817 in a more nefarious way, for example hiding the volume-key in the salts,
818 would need a look at the sources to be discovered, but I think that
819 somebody would find that sooner or later as well.
821 That said, this discussion is really a lot more complicated and longer
822 as an FAQ can sustain. If in doubt, ask on the mailing list.
825 * **2.18 Is there a concern with 4k Sectors?**
827 Not from dm-crypt itself. Encryption will be done in 512B blocks, but
828 if the partition and filesystem are aligned correctly and the filesystem
829 uses multiples of 4kiB as block size, the dm-crypt layer will just
830 process 8 x 512B = 4096B at a time with negligible overhead. LUKS does
831 place data at an offset, which is 2MiB per default and will not break
832 alignment. See also Item 6.12 of this FAQ for more details. Note that
833 if your partition or filesystem is misaligned, dm-crypt can make the
834 effect worse though. Also note that SSDs typically have much larger
835 blocks internally (e.g. 128kB or even larger).
838 * **2.19 How can I wipe a device with crypto-grade randomness?**
840 The conventional recommendation if you want to do more than just a
841 zero-wipe is to use something like
843 cat /dev/urandom > <target-device>
845 That used to very slow and painful at 10-20MB/s on a fast computer, but
846 newer kernels can give you > 200MB/s (depending on hardware). An
847 alternative is using cryptsetup and a plain dm-crypt device with a
848 random key, which is fast and on the same level of security. The
849 defaults are quite enough.
851 For device set-up, do the following:
853 cryptsetup open --type plain -d /dev/urandom /dev/<device> target
855 This maps the container as plain under /dev/mapper/target with a random
856 password. For the actual wipe you have several options. Basically, you
857 pipe zeroes into the opened container that then get encrypted. Simple
858 wipe without progress-indicator:
860 cat /dev/zero > /dev/mapper/to_be_wiped
862 Progress-indicator by dd_rescue:
864 dd_rescue -w /dev/zero /dev/mapper/to_be_wiped
866 Progress-indicator by my "wcs" stream meter (available from
867 https://www.tansi.org/tools/index.html ):
869 cat /dev/zero | wcs > /dev/mapper/to_be_wiped
871 Or use plain "dd", which gives you the progress when sent a SIGUSR1, see
872 the dd man page. The GNU "dd" command supports the "status=progress"
873 operand that gives you the progress without having to send it any signal.
875 Remove the mapping at the end and you are done.
878 * **2.20 How do I wipe only the LUKS header?**
880 This does _not_ describe an emergency wipe procedure, see Item 5.4 for
881 that. This procedure here is intended to be used when the data should
882 stay intact, e.g. when you change your LUKS container to use a detached
883 header and want to remove the old one. Please only do this if you have
887 01) Determine header size in 512 Byte sectors with luksDump:
889 cryptsetup luksDump <device with LUKS container>
892 Payload offset: <number> [of 512 byte sectors]
895 02) Take the result number, multiply by 512 zeros and write to
896 the start of the device, e.g. using one of the following alternatives:
898 dd bs=512 count=<number> if=/dev/zero of=<device>
901 head -c <number * 512> /dev/zero > /dev/<device>
905 (warning, untested! Remember that backup?) This assumes the
906 LUKS2 container uses the defaults, in particular there is only one data
908 01) Determine the data-segment offset using luksDump, same
911 cryptsetup luksDump <device with LUKS container>
915 offset: <number> [bytes]
918 02) Overwrite the stated number of bytes from the start of the device.
919 Just to give yet another way to get a defined number of zeros:
921 head -c <number> /dev/zero > /dev/<device>
927 * **3.1 My dm-crypt/LUKS mapping does not work! What general steps are there to investigate the problem?**
929 If you get a specific error message, investigate what it claims first.
930 If not, you may want to check the following things.
932 - Check that "/dev", including "/dev/mapper/control" is there. If it is
933 missing, you may have a problem with the "/dev" tree itself or you may
934 have broken udev rules.
936 - Check that you have the device mapper and the crypt target in your
937 kernel. The output of "dmsetup targets" should list a "crypt" target.
938 If it is not there or the command fails, add device mapper and
939 crypt-target to the kernel.
941 - Check that the hash-functions and ciphers you want to use are in the
942 kernel. The output of "cat /proc/crypto" needs to list them.
945 * **3.2 My dm-crypt mapping suddenly stopped when upgrading cryptsetup.**
947 The default cipher, hash or mode may have changed (the mode changed from
948 1.0.x to 1.1.x). See under "Issues With Specific Versions of
952 * **3.3 When I call cryptsetup from cron/CGI, I get errors about unknown features?**
954 If you get errors about unknown parameters or the like that are not
955 present when cryptsetup is called from the shell, make sure you have no
956 older version of cryptsetup on your system that then gets called by
957 cron/CGI. For example some distributions install cryptsetup into
958 /usr/sbin, while a manual install could go to /usr/local/sbin. As a
959 debugging aid, call "cryptsetup --version" from cron/CGI or the
960 non-shell mechanism to be sure the right version gets called.
963 * **3.4 Unlocking a LUKS device takes very long. Why?**
965 The unlock time for a key-slot (see Section 5 for an explanation what
966 iteration does) is calculated when setting a passphrase. By default it
967 is 1 second (2 seconds for LUKS2). If you set a passphrase on a fast
968 machine and then unlock it on a slow machine, the unlocking time can be
969 much longer. Also take into account that up to 8 key-slots (LUKS2: up
970 to 32 key-slots) have to be tried in order to find the right one.
972 If this is the problem, you can add another key-slot using the slow
973 machine with the same passphrase and then remove the old key-slot. The
974 new key-slot will have the unlock time adjusted to the slow machine.
975 Use luksKeyAdd and then luksKillSlot or luksRemoveKey. You can also use
976 the -i option to reduce iteration time (and security level) when setting
977 a passphrase. Default is 1000 (1 sec) for LUKS1 and 2000 (2sec) for
980 However, this operation will not change volume key iteration count ("MK
981 iterations" for LUKS1, "Iterations" under "Digests" for LUKS2). In
982 order to change that, you will have to backup the data in the LUKS
983 container (i.e. your encrypted data), luksFormat on the slow machine
984 and restore the data. Note that MK iterations are not very security
988 * **3.5 "blkid" sees a LUKS UUID and an ext2/swap UUID on the same device. What is wrong?**
990 Some old versions of cryptsetup have a bug where the header does not get
991 completely wiped during LUKS format and an older ext2/swap signature
992 remains on the device. This confuses blkid.
994 Fix: Wipe the unused header areas by doing a backup and restore of
995 the header with cryptsetup 1.1.x or later:
997 cryptsetup luksHeaderBackup --header-backup-file <file> <device>
998 cryptsetup luksHeaderRestore --header-backup-file <file> <device>
1001 * **3.6 I see a data corruption with the Intel QAT kernel driver; why?**
1003 Intel QAT crypto API drivers have severe bugs that are not fixed for years.
1005 If you see data corruption, please disable the QAT in the BIOS or avoid loading
1006 kernel Intel QAT drivers (switch to software crypto implementation or AES-NI).
1008 For more info, see posts in dm-devel list https://lore.kernel.org/dm-devel/?q=intel+qat
1011 # 4. Troubleshooting
1014 * **4.1 I get the error "LUKS keyslot x is invalid." What does that mean?**
1016 For LUKS1, this means that the given keyslot has an offset that points
1017 outside the valid keyslot area. Typically, the reason is a corrupted
1018 LUKS1 header because something was written to the start of the device
1019 the LUKS1 container is on. For LUKS2, I do not know when this error can
1020 happen, but I expect it will be something similar. Refer to Section
1021 "Backup and Data Recovery" and ask on the mailing list if you have
1022 trouble diagnosing and (if still possible) repairing this.
1025 * **4.2 I cannot unlock my LUKS container! What could be the problem?**
1027 First, make sure you have a correct passphrase. Then make sure you have
1028 the correct key-map and correct keyboard. And then make sure you have
1029 the correct character set and encoding, see also "PASSPHRASE CHARACTER
1030 SET" under Section 1.2.
1032 If you are sure you are entering the passphrase right, there is the
1033 possibility that the respective key-slot has been damaged. There is no
1034 way to recover a damaged key-slot, except from a header backup (see
1035 Section 6). For security reasons, there is also no checksum in the
1036 key-slots that could tell you whether a key-slot has been damaged. The
1037 only checksum present allows recognition of a correct passphrase, but
1038 that only works with that correct passphrase and a respective key-slot
1041 In order to find out whether a key-slot is damaged one has to look for
1042 "non-random looking" data in it. There is a tool that automates this
1043 for LUKS1 in the cryptsetup distribution from version 1.6.0 onwards. It
1044 is located in misc/keyslot_checker/. Instructions how to use and how to
1045 interpret results are in the README file. Note that this tool requires
1046 a libcryptsetup from cryptsetup 1.6.0 or later (which means
1047 libcryptsetup.so.4.5.0 or later). If the tool complains about missing
1048 functions in libcryptsetup, you likely have an earlier version from your
1049 distribution still installed. You can either point the symbolic link(s)
1050 from libcryptsetup.so.4 to the new version manually, or you can
1051 uninstall the distribution version of cryptsetup and re-install that
1052 from cryptsetup >= 1.6.0 again to fix this.
1055 * **4.3 Can a bad RAM module cause problems?**
1057 LUKS and dm-crypt can give the RAM quite a workout, especially when
1058 combined with software RAID. In particular the combination RAID5 +
1059 LUKS1 + XFS seems to uncover RAM problems that do not cause obvious
1060 problems otherwise. Symptoms vary, but often the problem manifests
1061 itself when copying large amounts of data, typically several times
1062 larger than your main memory.
1064 Note: One thing you should always do on large data copying or movements
1065 is to run a verify, for example with the "-d" option of "tar" or by
1066 doing a set of MD5 checksums on the source or target with
1068 find . -type f -exec md5sum \{\} \; > checksum-file
1070 and then a "md5sum -c checksum-file" on the other side. If you get
1071 mismatches here, RAM is the primary suspect. A lesser suspect is an
1072 overclocked CPU. I have found countless hardware problems in verify
1073 runs after copying data or making backups. Bit errors are much more
1074 common than most people think.
1076 Some RAM issues are even worse and corrupt structures in one of the
1077 layers. This typically results in lockups, CPU state dumps in the
1078 system logs, kernel panic or other things. It is quite possible to have
1079 a problem with an encrypted device, but not with an otherwise the same
1080 unencrypted device. The reason for that is that encryption has an error
1081 amplification property: If you flip one bit in an encrypted data block,
1082 the decrypted version has half of its bits flipped. This is actually an
1083 important security property for modern ciphers. With the usual modes in
1084 cryptsetup (CBC, ESSIV, XTS), you can get a completely changed 512 byte
1085 block for a bit error. A corrupt block causes a lot more havoc than the
1086 occasionally flipped single bit and can result in various obscure
1089 Note that a verify run on copying between encrypted or unencrypted
1090 devices will reliably detect corruption, even when the copying itself
1091 did not report any problems. If you find defect RAM, assume all backups
1092 and copied data to be suspect, unless you did a verify.
1095 * **4.4 How do I test RAM?**
1097 First you should know that overclocking often makes memory problems
1098 worse. So if you overclock (which I strongly recommend against in a
1099 system holding data that has any worth), run the tests with the
1100 overclocking active.
1102 There are two good options. One is Memtest86+ and the other is
1103 "memtester" by Charles Cazabon. Memtest86+ requires a reboot and then
1104 takes over the machine, while memtester runs from a root-shell. Both
1105 use different testing methods and I have found problems fast with either
1106 one that the other needed long to find. I recommend running the
1107 following procedure until the first error is found:
1109 - Run Memtest86+ for one cycle
1111 - Run memtester for one cycle (shut down as many other applications
1112 as possible and use the largest memory area you can get)
1114 - Run Memtest86+ for 24h or more
1116 - Run memtester for 24h or more
1118 If all that does not produce error messages, your RAM may be sound,
1119 but I have had one weak bit in the past that Memtest86+ needed around
1120 60 hours to find. If you can reproduce the original problem reliably,
1121 a good additional test may be to remove half of the RAM (if you have
1122 more than one module) and try whether the problem is still there and if
1123 so, try with the other half. If you just have one module, get a
1124 different one and try with that. If you do overclocking, reduce the
1125 settings to the most conservative ones available and try with that.
1128 * **4.5 Is there a risk using debugging tools like strace?**
1130 There most definitely is. A dump from strace and friends can contain
1131 all data entered, including the full passphrase. Example with strace
1132 and passphrase "test":
1134 > strace cryptsetup luksOpen /dev/sda10 c1
1136 read(6, "test\n", 512) = 5
1139 Depending on different factors and the tool used, the passphrase may
1140 also be encoded and not plainly visible. Hence it is never a good idea
1141 to give such a trace from a live container to anybody. Recreate the
1142 problem with a test container or set a temporary passphrase like "test"
1143 and use that for the trace generation. Item 2.6 explains how to create
1144 a loop-file backed LUKS container that may come in handy for this
1147 See also Item 6.10 for another set of data you should not give to
1151 # 5. Security Aspects
1154 * **5.1 How long is a secure passphrase?**
1156 This is just the short answer. For more info and explanation of some of
1157 the terms used in this item, read the rest of Section 5. The actual
1158 recommendation is at the end of this item.
1160 First, passphrase length is not really the right measure, passphrase
1161 entropy is. If your passphrase is 200 times the letter "a", it is long
1162 but has very low entropy and is pretty insecure.
1164 For example, a random lowercase letter (a-z) gives you 4.7 bit of
1165 entropy, one element of a-z0-9 gives you 5.2 bits of entropy, an element
1166 of a-zA-Z0-9 gives you 5.9 bits and a-zA-Z0-9!@#$%\^&:-+ gives you 6.2
1167 bits. On the other hand, a random English word only gives you 0.6...1.3
1168 bits of entropy per character. Using sentences that make sense gives
1169 lower entropy, series of random words gives higher entropy. Do not use
1170 sentences that can be tied to you or found on your computer. This type
1171 of attack is done routinely today.
1173 That said, it does not matter too much what scheme you use, but it does
1174 matter how much entropy your passphrase contains, because an attacker
1175 has to try on average
1177 1/2 * 2^(bits of entropy in passphrase)
1179 different passphrases to guess correctly.
1181 Historically, estimations tended to use computing time estimates, but
1182 more modern approaches try to estimate cost of guessing a passphrase.
1184 As an example, I will try to get an estimate from the numbers in
1185 https://gist.github.com/epixoip/a83d38f412b4737e99bbef804a270c40 This
1186 thing costs 23kUSD and does 68Ghashes/sec for SHA1. This is in 2017.
1188 Incidentally, my older calculation for a machine around 1000 times
1189 slower was off by a factor of about 1000, but in the right direction,
1190 i.e. I estimated the attack to be too easy. Nobody noticed ;-) On the
1191 plus side, the tables are now (2017) pretty much accurate.
1193 More references can be found at the end of this document. Note that
1194 these are estimates from the defender side, so assuming something is
1195 easier than it actually is fine. An attacker may still have
1196 significantly higher cost than estimated here.
1198 LUKS1 used SHA1 (since version 1.7.0 it uses SHA256) for hashing per
1199 default. We will leave aside the check whether a try actually decrypts
1200 a key-slot. I will assume a useful lifetime of the hardware of 2 years.
1201 (This is on the low side.) Disregarding downtime, the machine can then
1204 N = 68*10^9 * 3600 * 24 * 365 * 2 ~ 4*10^18
1206 passphrases for EUR/USD 23k. That is one 62 bit passphrase hashed once
1207 with SHA1 for EUR/USD 23k. This can be parallelized, it can be done
1208 faster than 2 years with several of these machines.
1210 For LUKS2, things look a bit better, as the advantage of using graphics
1211 cards is massively reduced. Using the recommendations below should
1212 hence be fine for LUKS2 as well and give a better security margin.
1214 For plain dm-crypt (no hash iteration) this is it. This gives (with
1215 SHA1, plain dm-crypt default is ripemd160 which seems to be slightly
1218 Passphrase entropy Cost to break
1228 For LUKS1, you have to take into account hash iteration in PBKDF2.
1229 For a current CPU, there are about 100k iterations (as can be queried
1230 with ''cryptsetup luksDump''.
1232 The table above then becomes:
1234 Passphrase entropy Cost to break
1246 To get reasonable security for the next 10 years, it is a good idea
1247 to overestimate by a factor of at least 1000.
1249 Then there is the question of how much the attacker is willing to spend.
1250 That is up to your own security evaluation. For general use, I will
1251 assume the attacker is willing to spend up to 1 million EUR/USD. Then
1252 we get the following recommendations:
1254 Plain dm-crypt: Use > 80 bit. That is e.g. 17 random chars from a-z
1255 or a random English sentence of > 135 characters length.
1257 LUKS1 and LUKS2: Use > 65 bit. That is e.g. 14 random chars from a-z
1258 or a random English sentence of > 108 characters length.
1260 If paranoid, add at least 20 bit. That is roughly four additional
1261 characters for random passphrases and roughly 32 characters for a
1262 random English sentence.
1265 * **5.2 Is LUKS insecure? Everybody can see I have encrypted data!**
1267 In practice it does not really matter. In most civilized countries you
1268 can just refuse to hand over the keys, no harm done. In some countries
1269 they can force you to hand over the keys if they suspect encryption.
1270 The suspicion is enough, they do not have to prove anything. This is
1271 for practical reasons, as even the presence of a header (like the LUKS
1272 header) is not enough to prove that you have any keys. It might have
1273 been an experiment, for example. Or it was used as encrypted swap with
1274 a key from /dev/random. So they make you prove you do not have
1275 encrypted data. Of course, if true, that is impossible and hence the
1276 whole idea is not compatible with fair laws. Note that in this context,
1277 countries like the US or the UK are not civilized and do not have fair
1280 As a side-note, standards for biometrics (fingerprint, retina,
1281 vein-pattern, etc.) are often different and much lower. If you put
1282 your LUKS passphrase into a device that can be unlocked using biometrics,
1283 they may force a biometric sample in many countries where they could not
1284 force you to give them a passphrase you solely have in your memory and
1285 can claim to have forgotten if needed (it happens). If you need protection
1286 on this level, make sure you know what the respective legal situation is,
1287 also while traveling, and make sure you decide beforehand what you
1288 will do if push comes to shove as they will definitely put you under
1289 as much pressure as they can legally apply.
1291 This means that if you have a large set of random-looking data, they can
1292 already lock you up. Hidden containers (encryption hidden within
1293 encryption), as possible with Truecrypt, do not help either. They will
1294 just assume the hidden container is there and unless you hand over the
1295 key, you will stay locked up. Don't have a hidden container? Tough
1296 luck. Anybody could claim that.
1298 Still, if you are concerned about the LUKS header, use plain dm-crypt
1299 with a good passphrase. See also Section 2, "What is the difference
1300 between "plain" and LUKS format?"
1303 * **5.3 Should I initialize (overwrite) a new LUKS/dm-crypt partition?**
1305 If you just create a filesystem on it, most of the old data will still
1306 be there. If the old data is sensitive, you should overwrite it before
1307 encrypting. In any case, not initializing will leave the old data there
1308 until the specific sector gets written. That may enable an attacker to
1309 determine how much and where on the partition data was written. If you
1310 think this is a risk, you can prevent this by overwriting the encrypted
1311 device (here assumed to be named "e1") with zeros like this:
1313 dd_rescue -w /dev/zero /dev/mapper/e1
1315 or alternatively with one of the following more standard commands:
1317 cat /dev/zero > /dev/mapper/e1
1318 dd if=/dev/zero of=/dev/mapper/e1
1322 * **5.4 How do I securely erase a LUKS container?**
1324 For LUKS, if you are in a desperate hurry, overwrite the LUKS header and
1325 key-slot area. For LUKS1 and LUKS2, just be generous and overwrite the
1326 first 100MB. A single overwrite with zeros should be enough. If you
1327 anticipate being in a desperate hurry, prepare the command beforehand.
1328 Example with /dev/sde1 as the LUKS partition and default parameters:
1330 head -c 100000000 /dev/zero > /dev/sde1; sync
1332 A LUKS header backup or full backup will still grant access to most or
1333 all data, so make sure that an attacker does not have access to backups
1334 or destroy them as well.
1336 Also note that SSDs and also some HDDs (SMR and hybrid HDDs, for
1337 example) may not actually overwrite the header and only do that an
1338 unspecified and possibly very long time later. The only way to be sure
1339 there is physical destruction. If the situation permits, do both
1340 overwrite and physical destruction.
1342 If you have time, overwrite the whole drive with a single pass of random
1343 data. This is enough for most HDDs. For SSDs or FLASH (USB sticks) or
1344 SMR or hybrid drives, you may want to overwrite the whole drive several
1345 times to be sure data is not retained. This is possibly still insecure
1346 as the respective technologies are not fully understood in this regard.
1347 Still, due to the anti-forensic properties of the LUKS key-slots, a
1348 single overwrite could be enough. If in doubt, use physical destruction
1349 in addition. Here is a link to some current research results on erasing
1350 SSDs and FLASH drives:
1351 https://www.usenix.org/events/fast11/tech/full_papers/Wei.pdf
1353 Keep in mind to also erase all backups.
1355 Example for a random-overwrite erase of partition sde1 done with
1358 dd_rescue -w /dev/urandom /dev/sde1
1362 * **5.5 How do I securely erase a backup of a LUKS partition or header?**
1364 That depends on the medium it is stored on. For HDD and SSD, use
1365 overwrite with random data. For an SSD, FLASH drive (USB stick) hybrid
1366 HDD or SMR HDD, you may want to overwrite the complete drive several
1367 times and use physical destruction in addition, see last item. For
1368 re-writable CD/DVD, a single overwrite should be enough, due to the
1369 anti-forensic properties of the LUKS keyslots. For write-once media,
1370 use physical destruction. For low security requirements, just cut the
1371 CD/DVD into several parts. For high security needs, shred or burn the
1374 If your backup is on magnetic tape, I advise physical destruction by
1375 shredding or burning, after (!) overwriting. The problem with magnetic
1376 tape is that it has a higher dynamic range than HDDs and older data may
1377 well be recoverable after overwrites. Also write-head alignment issues
1378 can lead to data not actually being deleted during overwrites.
1380 The best option is to actually encrypt the backup, for example with
1381 PGP/GnuPG and then just destroy all copies of the encryption key if
1382 needed. Best keep them on paper, as that has excellent durability and
1383 secure destruction is easy, for example by burning and then crushing the
1384 ashes to a fine powder. A blender and water also works nicely.
1387 * **5.6 What about backup? Does it compromise security?**
1389 That depends. See item 6.7.
1392 * **5.7 Why is all my data permanently gone if I overwrite the LUKS header?**
1394 Overwriting the LUKS header in part or in full is the most common reason
1395 why access to LUKS containers is lost permanently. Overwriting can be
1396 done in a number of fashions, like creating a new filesystem on the raw
1397 LUKS partition, making the raw partition part of a RAID array and just
1398 writing to the raw partition.
1400 The LUKS1 header contains a 256 bit "salt" per key-slot and without that
1401 no decryption is possible. While the salts are not secret, they are
1402 key-grade material and cannot be reconstructed. This is a
1403 cryptographically strong "cannot". From observations on the cryptsetup
1404 mailing-list, people typically go though the usual stages of grief
1405 (Denial, Anger, Bargaining, Depression, Acceptance) when this happens to
1406 them. Observed times vary between 1 day and 2 weeks to complete the
1407 cycle. Seeking help on the mailing-list is fine. Even if we usually
1408 cannot help with getting back your data, most people found the feedback
1411 If your header does not contain an intact key-slot salt, best go
1412 directly to the last stage ("Acceptance") and think about what to do
1413 now. There is one exception that I know of: If your LUKS1 container is
1414 still open, then it may be possible to extract the volume key from the
1415 running system. See Item "How do I recover the volume key from a mapped
1416 LUKS1 container?" in Section "Backup and Data Recovery".
1418 For LUKS2, things are both better and worse. First, the salts are in a
1419 less vulnerable position now. But, on the other hand, the keys of a
1420 mapped (open) container are now stored in the kernel key-store, and
1421 while there probably is some way to get them out of there, I am not sure
1422 how much effort that needs.
1425 * **5.8 What is a "salt"?**
1427 A salt is a random key-grade value added to the passphrase before it is
1428 processed. It is not kept secret. The reason for using salts is as
1429 follows: If an attacker wants to crack the password for a single LUKS
1430 container, then every possible passphrase has to be tried. Typically an
1431 attacker will not try every binary value, but will try words and
1432 sentences from a dictionary.
1434 If an attacker wants to attack several LUKS containers with the same
1435 dictionary, then a different approach makes sense: Compute the resulting
1436 slot-key for each dictionary element and store it on disk. Then the
1437 test for each entry is just the slow unlocking with the slot key (say
1438 0.00001 sec) instead of calculating the slot-key first (1 sec). For a
1439 single attack, this does not help. But if you have more than one
1440 container to attack, this helps tremendously, also because you can
1441 prepare your table before you even have the container to attack! The
1442 calculation is also very simple to parallelize. You could, for example,
1443 use the night-time unused CPU power of your desktop PCs for this.
1445 This is where the salt comes in. If the salt is combined with the
1446 passphrase (in the simplest form, just appended to it), you suddenly
1447 need a separate table for each salt value. With a reasonably-sized salt
1448 value (256 bit, e.g.) this is quite infeasible.
1451 * **5.9 Is LUKS secure with a low-entropy (bad) passphrase?**
1453 Short answer: yes. Do not use a low-entropy passphrase.
1455 Note: For LUKS2, protection for bad passphrases is a bit better
1456 due to the use of Argon2, but that is only a gradual improvement.
1459 This needs a bit of theory. The quality of your passphrase is directly
1460 related to its entropy (information theoretic, not thermodynamic). The
1461 entropy says how many bits of "uncertainty" or "randomness" are in you
1462 passphrase. In other words, that is how difficult guessing the
1465 Example: A random English sentence has about 1 bit of entropy per
1466 character. A random lowercase (or uppercase) character has about 4.7
1469 Now, if n is the number of bits of entropy in your passphrase and t
1470 is the time it takes to process a passphrase in order to open the
1471 LUKS container, then an attacker has to spend at maximum
1473 attack_time_max = 2^n * t
1475 time for a successful attack and on average half that. There is no way
1476 getting around that relationship. However, there is one thing that does
1477 help, namely increasing t, the time it takes to use a passphrase, see
1480 Still, if you want good security, a high-entropy passphrase is the only
1481 option. For example, a low-entropy passphrase can never be considered
1482 secure against a TLA-level (Three Letter Agency level, i.e.
1483 government-level) attacker, no matter what tricks are used in the
1484 key-derivation function. Use at least 64 bits for secret stuff. That
1485 is 64 characters of English text (but only if randomly chosen) or a
1486 combination of 12 truly random letters and digits.
1488 For passphrase generation, do not use lines from very well-known texts
1489 (religious texts, Harry Potter, etc.) as they are too easy to guess.
1490 For example, the total Harry Potter has about 1'500'000 words (my
1491 estimation). Trying every 64 character sequence starting and ending at
1492 a word boundary would take only something like 20 days on a single CPU
1493 and is entirely feasible. To put that into perspective, using a number
1494 of Amazon EC2 High-CPU Extra Large instances (each gives about 8 real
1495 cores), this test costs currently about 50USD/EUR, but can be made to
1496 run arbitrarily fast.
1498 On the other hand, choosing 1.5 lines from, say, the Wheel of Time, is
1499 in itself not more secure, but the book selection adds quite a bit of
1500 entropy. (Now that I have mentioned it here, don't use tWoT either!) If
1501 you add 2 or 3 typos and switch some words around, then this is good
1502 passphrase material.
1505 * **5.10 What is "iteration count" and why is decreasing it a bad idea?**
1508 Iteration count is the number of PBKDF2 iterations a passphrase is put
1509 through before it is used to unlock a key-slot. Iterations are done
1510 with the explicit purpose to increase the time that it takes to unlock a
1511 key-slot. This provides some protection against use of low-entropy
1514 The idea is that an attacker has to try all possible passphrases. Even
1515 if the attacker knows the passphrase is low-entropy (see last item), it
1516 is possible to make each individual try take longer. The way to do this
1517 is to repeatedly hash the passphrase for a certain time. The attacker
1518 then has to spend the same time (given the same computing power) as the
1519 user per try. With LUKS1, the default is 1 second of PBKDF2 hashing.
1521 Example 1: Lets assume we have a really bad passphrase (e.g. a
1522 girlfriends name) with 10 bits of entropy. With the same CPU, an
1523 attacker would need to spend around 500 seconds on average to break that
1524 passphrase. Without iteration, it would be more like 0.0001 seconds on
1527 Example 2: The user did a bit better and has 32 chars of English text.
1528 That would be about 32 bits of entropy. With 1 second iteration, that
1529 means an attacker on the same CPU needs around 136 years. That is
1530 pretty impressive for such a weak passphrase. Without the iterations,
1531 it would be more like 50 days on a modern CPU, and possibly far less.
1533 In addition, the attacker can both parallelize and use special hardware
1534 like GPUs or FPGAs to speed up the attack. The attack can also happen
1535 quite some time after the luksFormat operation and CPUs can have become
1536 faster and cheaper. For that reason you want a bit of extra security.
1537 Anyways, in Example 1 your are screwed. In example 2, not necessarily.
1538 Even if the attack is faster, it still has a certain cost associated
1539 with it, say 10000 EUR/USD with iteration and 1 EUR/USD without
1540 iteration. The first can be prohibitively expensive, while the second
1541 is something you try even without solid proof that the decryption will
1542 yield something useful.
1544 The numbers above are mostly made up, but show the idea. Of course the
1545 best thing is to have a high-entropy passphrase.
1547 Would a 100 sec iteration time be even better? Yes and no.
1548 Cryptographically it would be a lot better, namely 100 times better.
1549 However, usability is a very important factor for security technology
1550 and one that gets overlooked surprisingly often. For LUKS, if you have
1551 to wait 2 minutes to unlock the LUKS container, most people will not
1552 bother and use less secure storage instead. It is better to have less
1553 protection against low-entropy passphrases and people actually use LUKS,
1554 than having them do without encryption altogether.
1556 Now, what about decreasing the iteration time? This is generally a very
1557 bad idea, unless you know and can enforce that the users only use
1558 high-entropy passphrases. If you decrease the iteration time without
1559 ensuring that, then you put your users at increased risk, and
1560 considering how rarely LUKS containers are unlocked in a typical
1561 work-flow, you do so without a good reason. Don't do it. The iteration
1562 time is already low enough that users with low entropy passphrases are
1563 vulnerable. Lowering it even further increases this danger
1566 LUKS2: Pretty much the same reasoning applies. The advantages of using
1567 GPUs or FPGAs in an attack have been significantly reduced, but that
1568 is the only main difference.
1571 * **5.11 Some people say PBKDF2 is insecure?**
1573 There is some discussion that a hash-function should have a "large
1574 memory" property, i.e. that it should require a lot of memory to be
1575 computed. This serves to prevent attacks using special programmable
1576 circuits, like FPGAs, and attacks using graphics cards. PBKDF2 does not
1577 need a lot of memory and is vulnerable to these attacks. However, the
1578 publication usually referred in these discussions is not very convincing
1579 in proving that the presented hash really is "large memory" (that may
1580 change, email the FAQ maintainer when it does) and it is of limited
1581 usefulness anyways. Attackers that use clusters of normal PCs will not
1582 be affected at all by a "large memory" property. For example the US
1583 Secret Service is known to use the off-hour time of all the office PCs
1584 of the Treasury for password breaking. The Treasury has about 110'000
1585 employees. Assuming every one has an office PC, that is significant
1586 computing power, all of it with plenty of memory for computing "large
1587 memory" hashes. Bot-net operators also have all the memory they want.
1588 The only protection against a resourceful attacker is a high-entropy
1589 passphrase, see items 5.9 and 5.10.
1591 That said, LUKS2 defaults to Argon2, which has a large-memory property
1592 and massively reduces the advantages of GPUs and FPGAs.
1595 * **5.12 What about iteration count with plain dm-crypt?**
1597 Simple: There is none. There is also no salting. If you use plain
1598 dm-crypt, the only way to be secure is to use a high entropy passphrase.
1599 If in doubt, use LUKS instead.
1602 * **5.13 Is LUKS with default parameters less secure on a slow CPU?**
1604 Unfortunately, yes. However the only aspect affected is the protection
1605 for low-entropy passphrase or volume-key. All other security aspects
1606 are independent of CPU speed.
1608 The volume key is less critical, as you really have to work at it to
1609 give it low entropy. One possibility to mess this up is to supply the
1610 volume key yourself. If that key is low-entropy, then you get what you
1611 deserve. The other known possibility to create a LUKS container with a
1612 bad volume key is to use /dev/urandom for key generation in an
1613 entropy-starved situation (e.g. automatic installation on an embedded
1614 device without network and other entropy sources or installation in a VM
1615 under certain circumstances).
1617 For the passphrase, don't use a low-entropy passphrase. If your
1618 passphrase is good, then a slow CPU will not matter. If you insist on a
1619 low-entropy passphrase on a slow CPU, use something like
1620 "--iter-time=10000" or higher and wait a long time on each LUKS unlock
1621 and pray that the attacker does not find out in which way exactly your
1622 passphrase is low entropy. This also applies to low-entropy passphrases
1623 on fast CPUs. Technology can do only so much to compensate for problems
1624 in front of the keyboard.
1626 Also note that power-saving modes will make your CPU slower. This will
1627 reduce iteration count on LUKS container creation. It will keep unlock
1628 times at the expected values though at this CPU speed.
1631 * **5.14 Why was the default aes-cbc-plain replaced with aes-cbc-essiv?**
1633 Note: This item applies both to plain dm-crypt and to LUKS
1635 The problem is that cbc-plain has a fingerprint vulnerability, where a
1636 specially crafted file placed into the crypto-container can be
1637 recognized from the outside. The issue here is that for cbc-plain the
1638 initialization vector (IV) is the sector number. The IV gets XORed to
1639 the first data chunk of the sector to be encrypted. If you make sure
1640 that the first data block to be stored in a sector contains the sector
1641 number as well, the first data block to be encrypted is all zeros and
1642 always encrypted to the same ciphertext. This also works if the first
1643 data chunk just has a constant XOR with the sector number. By having
1644 several shifted patterns you can take care of the case of a
1645 non-power-of-two start sector number of the file.
1647 This mechanism allows you to create a pattern of sectors that have the
1648 same first ciphertext block and signal one bit per sector to the
1649 outside, allowing you to e.g. mark media files that way for recognition
1650 without decryption. For large files this is a practical attack. For
1651 small ones, you do not have enough blocks to signal and take care of
1652 different file starting offsets.
1654 In order to prevent this attack, the default was changed to cbc-essiv.
1655 ESSIV uses a keyed hash of the sector number, with the encryption key as
1656 key. This makes the IV unpredictable without knowing the encryption key
1657 and the watermarking attack fails.
1660 * **5.15 Are there any problems with "plain" IV? What is "plain64"?**
1662 First, "plain" and "plain64" are both not secure to use with CBC, see
1665 However there are modes, like XTS, that are secure with "plain" IV. The
1666 next limit is that "plain" is 64 bit, with the upper 32 bit set to zero.
1667 This means that on volumes larger than 2TiB, the IV repeats, creating a
1668 vulnerability that potentially leaks some data. To avoid this, use
1669 "plain64", which uses the full sector number up to 64 bit. Note that
1670 "plain64" requires a kernel 2.6.33 or more recent. Also note that
1671 "plain64" is backwards compatible for volume sizes of maximum size 2TiB,
1672 but not for those > 2TiB. Finally, "plain64" does not cause any
1673 performance penalty compared to "plain".
1676 * **5.16 What about XTS mode?**
1678 XTS mode is potentially even more secure than cbc-essiv (but only if
1679 cbc-essiv is insecure in your scenario). It is a NIST standard and
1680 used, e.g. in Truecrypt. From version 1.6.0 of cryptsetup onwards,
1681 aes-xts-plain64 is the default for LUKS. If you want to use it with a
1682 cryptsetup before version 1.6.0 or with plain dm-crypt, you have to
1683 specify it manually as "aes-xts-plain", i.e.
1685 cryptsetup -c aes-xts-plain luksFormat <device>
1687 For volumes >2TiB and kernels >= 2.6.33 use "plain64" (see FAQ item
1688 on "plain" and "plain64"):
1690 cryptsetup -c aes-xts-plain64 luksFormat <device>
1692 There is a potential security issue with XTS mode and large blocks.
1693 LUKS and dm-crypt always use 512B blocks and the issue does not apply.
1696 * **5.17 Is LUKS FIPS-140-2 certified?**
1698 No. But that is more a problem of FIPS-140-2 than of LUKS. From a
1699 technical point-of-view, LUKS with the right parameters would be
1700 FIPS-140-2 compliant, but in order to make it certified, somebody has to
1701 pay real money for that. And then, whenever cryptsetup is changed or
1702 extended, the certification lapses and has to be obtained again.
1704 From the aspect of actual security, LUKS with default parameters should
1705 be as good as most things that are FIPS-140-2 certified, although you
1706 may want to make sure to use /dev/random (by specifying --use-random on
1707 luksFormat) as randomness source for the volume key to avoid being
1708 potentially insecure in an entropy-starved situation.
1711 * **5.18 What about Plausible Deniability?**
1713 First let me attempt a definition for the case of encrypted filesystems:
1714 Plausible deniability is when you store data inside an encrypted
1715 container and it is not possible to prove it is there without having a
1716 special passphrase. And at the same time it must be "plausible" that
1717 there actually is no hidden data there.
1719 As a simple entropy-analysis will show that here may be data there, the
1720 second part is what makes it tricky.
1722 There seem to be a lot of misunderstandings about this idea, so let me
1723 make it clear that this refers to the situation where the attackers can
1724 prove that there is data that either may be random or may be part of a
1725 plausible-deniability scheme, they just cannot prove which one it is.
1726 Hence a plausible-deniability scheme must hold up when the attackers
1727 know there is something potentially fishy. If you just hide data and
1728 rely on it not being found, that is just simple deniability, not
1729 "plausible" deniability and I am not talking about that in the
1730 following. Simple deniability against a low-competence attacker may be
1731 as simple as renaming a file or putting data into an unused part of a
1732 disk. Simple deniability against a high-skill attacker with time to
1733 invest is usually pointless unless you go for advanced steganographic
1734 techniques, which have their own drawbacks, such as low data capacity.
1736 Now, the idea of plausible deniability is compelling and on a first
1737 glance it seems possible to do it. And from a cryptographic point of
1738 view, it actually is possible.
1740 So, does the idea work in practice? No, unfortunately. The reasoning
1741 used by its proponents is fundamentally flawed in several ways and the
1742 cryptographic properties fail fatally when colliding with the real
1745 First, why should "I do not have a hidden partition" be any more
1746 plausible than "I forgot my crypto key" or "I wiped that partition with
1747 random data, nothing in there"? I do not see any reason.
1749 Second, there are two types of situations: Either they cannot force you
1750 to give them the key (then you simply do not) or they can. In the
1751 second case, they can always do bad things to you, because they cannot
1752 prove that you have the key in the first place! This means they do not
1753 have to prove you have the key, or that this random looking data on your
1754 disk is actually encrypted data. So the situation will allow them to
1755 waterboard/lock-up/deport you anyways, regardless of how "plausible"
1756 your deniability is. Do not have a hidden partition you could show to
1757 them, but there are indications you may? Too bad for you.
1758 Unfortunately "plausible deniability" also means you cannot prove there
1761 Third, hidden partitions are not that hidden. There are basically just
1762 two possibilities: a) Make a large crypto container, but put a smaller
1763 filesystem in there and put the hidden partition into the free space.
1764 Unfortunately this is glaringly obvious and can be detected in an
1765 automated fashion. This means that the initial suspicion to put you
1766 under duress in order to make you reveal your hidden data is given. b)
1767 Make a filesystem that spans the whole encrypted partition, and put the
1768 hidden partition into space not currently used by that filesystem.
1769 Unfortunately that is also glaringly obvious, as you then cannot write
1770 to the filesystem without a high risk of destroying data in the hidden
1771 container. Have not written anything to the encrypted filesystem in a
1772 while? Too bad, they have the suspicion they need to do unpleasant
1775 To be fair, if you prepare option b) carefully and directly before going
1776 into danger, it may work. But then, the mere presence of encrypted data
1777 may already be enough to get you into trouble in those places were they
1778 can demand encryption keys.
1780 Here is an additional reference for some problems with plausible
1782 https://www.schneier.com/academic/paperfiles/paper-truecrypt-dfs.pdf
1783 I strongly suggest you read it.
1785 So, no, I will not provide any instructions on how to do it with plain
1786 dm-crypt or LUKS. If you insist on shooting yourself in the foot, you
1787 can figure out how to do it yourself.
1790 * **5.19 What about SSDs, Flash, Hybrid and SMR Drives?**
1792 The problem is that you cannot reliably erase parts of these devices,
1793 mainly due to wear-leveling and possibly defect management and delayed
1794 writes to the main data area.
1796 For example for SSDs, when overwriting a sector, what the device does is
1797 to move an internal sector (may be 128kB or even larger) to some pool of
1798 discarded, not-yet erased unused sectors, take a fresh empty sector from
1799 the empty-sector pool and copy the old sector over with the changes to
1800 the small part you wrote. This is done in some fashion so that larger
1801 writes do not cause a lot of small internal updates.
1803 The thing is that the mappings between outside-addressable sectors and
1804 inside sectors is arbitrary (and the vendors are not talking). Also the
1805 discarded sectors are not necessarily erased immediately. They may
1808 For plain dm-crypt, the consequences are that older encrypted data may
1809 be lying around in some internal pools of the device. Thus may or may
1810 not be a problem and depends on the application. Remember the same can
1811 happen with a filesystem if consecutive writes to the same area of a
1812 file can go to different sectors.
1814 However, for LUKS, the worst case is that key-slots and LUKS header may
1815 end up in these internal pools. This means that password management
1816 functionality is compromised (the old passwords may still be around,
1817 potentially for a very long time) and that fast erase by overwriting the
1818 header and key-slot area is insecure.
1820 Also keep in mind that the discarded/used pool may be large. For
1821 example, a 240GB SSD has about 16GB of spare area in the chips that it
1822 is free to do with as it likes. You would need to make each individual
1823 key-slot larger than that to allow reliable overwriting. And that
1824 assumes the disk thinks all other space is in use. Reading the internal
1825 pools using forensic tools is not that hard, but may involve some
1830 If you trust the device vendor (you probably should not...) you can try
1831 an ATA "secure erase" command. That is not present in USB keys though
1832 and may or may not be secure for a hybrid drive.
1834 If you can do without password management and are fine with doing
1835 physical destruction for permanently deleting data (always after one or
1836 several full overwrites!), you can use plain dm-crypt.
1838 If you want or need all the original LUKS security features to work, you
1839 can use a detached LUKS header and put that on a conventional, magnetic
1840 disk. That leaves potentially old encrypted data in the pools on the
1841 main disk, but otherwise you get LUKS with the same security as on a
1842 traditional magnetic disk. Note however that storage vendors are prone
1843 to lying to their customers. For example, it recently came out that
1844 HDDs sold without any warning or mentioning in the data-sheets were
1845 actually using SMR and that will write data first to a faster area and
1846 only overwrite the original data area some time later when things are
1849 If you are concerned about your laptop being stolen, you are likely fine
1850 using LUKS on an SSD or hybrid drive. An attacker would need to have
1851 access to an old passphrase (and the key-slot for this old passphrase
1852 would actually need to still be somewhere in the SSD) for your data to
1853 be at risk. So unless you pasted your old passphrase all over the
1854 Internet or the attacker has knowledge of it from some other source and
1855 does a targeted laptop theft to get at your data, you should be fine.
1858 * **5.20 LUKS1 is broken! It uses SHA-1!**
1860 No, it is not. SHA-1 is (academically) broken for finding collisions,
1861 but not for using it in a key-derivation function. And that collision
1862 vulnerability is for non-iterated use only. And you need the hash-value
1865 This basically means that if you already have a slot-key, and you have
1866 set the PBKDF2 iteration count to 1 (it is > 10'000 normally), you could
1867 (maybe) derive a different passphrase that gives you the same slot-key.
1868 But if you have the slot-key, you can already unlock the key-slot and
1869 get the volume key, breaking everything. So basically, this SHA-1
1870 vulnerability allows you to open a LUKS1 container with high effort when
1871 you already have it open.
1873 The real problem here is people that do not understand crypto and claim
1874 things are broken just because some mechanism is used that has been
1875 broken for a specific different use. The way the mechanism is used
1876 matters very much. A hash that is broken for one use can be completely
1877 secure for other uses and here it is.
1879 Since version 1.7.0, cryptsetup uses SHA-256 as default to ensure that
1880 it will be compatible in the future. There are already some systems
1881 where SHA-1 is completely phased out or disabled by a security policy.
1884 * **5.21 Why is there no "Nuke-Option"?**
1886 A "Nuke-Option" or "Kill-switch" is a password that when entered upon
1887 unlocking instead wipes the header and all passwords. So when somebody
1888 forces you to enter your password, you can destroy the data instead.
1890 While this sounds attractive at first glance, it does not make sense
1891 once a real security analysis is done. One problem is that you have to
1892 have some kind of HSM (Hardware Security Module) in order to implement
1893 it securely. In the movies, a HSM starts to smoke and melt once the
1894 Nuke-Option has been activated. In actual reality, it just wipes some
1895 battery-backed RAM cells. A proper HSM costs something like
1896 20'000...100'000 EUR/USD and there a Nuke-Option may make some sense.
1897 BTW, a chipcard or a TPM is not a HSM, although some vendors are
1898 promoting that myth.
1900 Now, a proper HSMs will have a wipe option but not a Nuke-Option, i.e.
1901 you can explicitly wipe the HSM, but by a different process than
1902 unlocking it takes. Why is that? Simple: If somebody can force you to
1903 reveal passwords, then they can also do bad things to you if you do not
1904 or if you enter a nuke password instead. Think locking you up for a few
1905 years for "destroying evidence" or for far longer and without trial for
1906 being a "terrorist suspect". No HSM maker will want to expose its
1907 customers to that risk.
1909 Now think of the typical LUKS application scenario, i.e. disk
1910 encryption. Usually the ones forcing you to hand over your password
1911 will have access to the disk as well, and, if they have any real
1912 suspicion, they will mirror your disk before entering anything supplied
1913 by you. This neatly negates any Nuke-Option. If they have no suspicion
1914 (just harassing people that cross some border for example), the
1915 Nuke-Option would work, but see above about likely negative consequences
1916 and remember that a Nuke-Option may not work reliably on SSD and hybrid
1919 Hence my advice is to never take data that you do not want to reveal
1920 into any such situation in the first place. There is no need to
1921 transfer data on physical carriers today. The Internet makes it quite
1922 possible to transfer data between arbitrary places and modern encryption
1923 makes it secure. If you do it right, nobody will even be able to
1924 identify source or destination. (How to do that is out of scope of this
1925 document. It does require advanced skills in this age of pervasive
1928 Hence, LUKS has no kill option because it would do much more harm than
1931 Still, if you have a good use-case (i.e. non-abstract real-world
1932 situation) where a Nuke-Option would actually be beneficial, please let
1936 * **5.22 Does cryptsetup open network connections to websites, etc. ?**
1938 This question seems not to make much sense at first glance, but here is
1939 an example form the real world: The TrueCrypt GUI has a "Donation"
1940 button. Press it, and a web-connection to the TrueCrypt website is
1941 opened via the default browser, telling everybody that listens that you
1942 use TrueCrypt. In the worst case, things like this can get people
1945 So: Cryptsetup will never open any network connections except the
1946 local netlink socket it needs to talk to the kernel crypto API.
1948 In addition, the installation package should contain all documentation,
1949 including this FAQ, so that you do not have to go to a web-site to read
1950 it. (If your distro cuts the docu, please complain to them.) In
1951 security software, any connection initiated to anywhere outside your
1952 machine should always be the result of an explicit request for such a
1953 connection by the user and cryptsetup will stay true to that principle.
1956 * **5.23 What is cryptsetup CVE-2021-4122?**
1958 CVE-2021-4122 describes a possible attack against data confidentiality
1959 through LUKS2 online reencryption extension crash recovery.
1961 An attacker can modify on-disk metadata to simulate decryption in
1962 progress with crashed (unfinished) reencryption step and persistently
1963 decrypt part of the LUKS device.
1965 This attack requires repeated physical access to the LUKS device but
1966 no knowledge of user passphrases.
1968 The decryption step is performed after a valid user activates
1969 the device with a correct passphrase and modified metadata.
1970 There are no visible warnings for the user that such recovery happened
1971 (except using the luksDump command). The attack can also be reversed
1972 afterward (simulating crashed encryption from a plaintext) with
1973 possible modification of revealed plaintext.
1975 The problem was fixed in cryptsetup version 2.4.3 and 2.3.7.
1977 For more info, please see the report here:
1978 https://seclists.org/oss-sec/2022/q1/34
1981 # 6. Backup and Data Recovery
1984 * **6.1 Why do I need Backup?**
1986 First, disks die. The rate for well-treated (!) disk is about 5% per
1987 year, which is high enough to worry about. There is some indication
1988 that this may be even worse for some SSDs. This applies both to LUKS
1989 and plain dm-crypt partitions.
1991 Second, for LUKS, if anything damages the LUKS header or the key-stripe
1992 area then decrypting the LUKS device can become impossible. This is a
1993 frequent occurrence. For example an accidental format as FAT or some
1994 software overwriting the first sector where it suspects a partition boot
1995 sector typically makes a LUKS1 partition permanently inaccessible. See
1996 more below on LUKS header damage.
1998 So, data-backup in some form is non-optional. For LUKS, you may also
1999 want to store a header backup in some secure location. This only needs
2000 an update if you change passphrases.
2003 * **6.2 How do I backup a LUKS header?**
2005 While you could just copy the appropriate number of bytes from the start
2006 of the LUKS partition, the best way is to use command option
2007 "luksHeaderBackup" of cryptsetup. This protects also against errors
2008 when non-standard parameters have been used in LUKS partition creation.
2011 cryptsetup luksHeaderBackup --header-backup-file <file> <device>
2013 To restore, use the inverse command, i.e.
2015 cryptsetup luksHeaderRestore --header-backup-file <file> <device>
2017 If you are unsure about a header to be restored, make a backup of the
2018 current one first! You can also test the header-file without restoring
2019 it by using the --header option for a detached header like this:
2021 cryptsetup --header <file> luksOpen <device> </dev/mapper/name>
2023 If that unlocks your key-slot, you are good. Do not forget to close
2026 Under some circumstances (damaged header), this fails. Then use the
2027 following steps in case it is LUKS1:
2029 First determine the volume (volume) key size:
2031 cryptsetup luksDump <device>
2033 gives a line of the form
2037 with bits equal to 256 for the old defaults and 512 for the new
2038 defaults. 256 bits equals a total header size of 1'052'672 Bytes and
2039 512 bits one of 2MiB. (See also Item 6.12) If luksDump fails, assume
2040 2MiB, but be aware that if you restore that, you may also restore the
2041 first 1M or so of the filesystem. Do not change the filesystem if you
2042 were unable to determine the header size! With that, restoring a
2043 too-large header backup is still safe.
2045 Second, dump the header to file. There are many ways to do it, I
2046 prefer the following:
2048 head -c 1052672 <device> > header_backup.dmp
2052 head -c 2M <device> > header_backup.dmp
2054 for a 2MiB header. Verify the size of the dump-file to be sure.
2056 To restore such a backup, you can try luksHeaderRestore or do a more
2059 cat header_backup.dmp > <device>
2063 * **6.3 How do I test for a LUKS header?**
2067 cryptsetup -v isLuks <device>
2069 on the device. Without the "-v" it just signals its result via
2070 exit-status. You can also use the more general test
2074 which will also detect other types and give some more info. Omit
2075 "-p" for old versions of blkid that do not support it.
2078 * **6.4 How do I backup a LUKS or dm-crypt partition?**
2080 There are two options, a sector-image and a plain file or filesystem
2081 backup of the contents of the partition. The sector image is already
2082 encrypted, but cannot be compressed and contains all empty space. The
2083 filesystem backup can be compressed, can contain only part of the
2084 encrypted device, but needs to be encrypted separately if so desired.
2086 A sector-image will contain the whole partition in encrypted form, for
2087 LUKS the LUKS header, the keys-slots and the data area. It can be done
2088 under Linux e.g. with dd_rescue (for a direct image copy) and with
2089 "cat" or "dd". Examples:
2091 cat /dev/sda10 > sda10.img
2092 dd_rescue /dev/sda10 sda10.img
2094 You can also use any other backup software that is capable of making a
2095 sector image of a partition. Note that compression is ineffective for
2096 encrypted data, hence it does not make sense to use it.
2098 For a filesystem backup, you decrypt and mount the encrypted partition
2099 and back it up as you would a normal filesystem. In this case the
2100 backup is not encrypted, unless your encryption method does that. For
2101 example you can encrypt a backup with "tar" as follows with GnuPG:
2103 tar cjf - <path> | gpg --cipher-algo AES -c - > backup.tbz2.gpg
2105 And verify the backup like this if you are at "path":
2107 cat backup.tbz2.gpg | gpg - | tar djf -
2109 Note: Always verify backups, especially encrypted ones!
2111 There is one problem with verifying like this: The kernel may still have
2112 some files cached and in fact verify them against RAM or may even verify
2113 RAM against RAM, which defeats the purpose of the exercise. The
2114 following command empties the kernel caches:
2116 echo 3 > /proc/sys/vm/drop_caches
2118 Run it after backup and before verify.
2120 In both cases GnuPG will ask you interactively for your symmetric key.
2121 The verify will only output errors. Use "tar dvjf -" to get all
2122 comparison results. To make sure no data is written to disk
2123 unencrypted, turn off swap if it is not encrypted before doing the
2126 Restore works like certification with the 'd' ('difference') replaced
2127 by 'x' ('eXtract'). Refer to the man-page of tar for more explanations
2128 and instructions. Note that with default options tar will overwrite
2129 already existing files without warning. If you are unsure about how
2130 to use tar, experiment with it in a location where you cannot do damage.
2132 You can of course use different or no compression and you can use an
2133 asymmetric key if you have one and have a backup of the secret key that
2136 A second option for a filesystem-level backup that can be used when the
2137 backup is also on local disk (e.g. an external USB drive) is to use a
2138 LUKS container there and copy the files to be backed up between both
2139 mounted containers. Also see next item.
2142 * **6.5 Do I need a backup of the full partition? Would the header and key-slots not be enough?**
2144 Backup protects you against two things: Disk loss or corruption and user
2145 error. By far the most questions on the dm-crypt mailing list about how
2146 to recover a damaged LUKS partition are related to user error. For
2147 example, if you create a new filesystem on a non-mapped LUKS container,
2148 chances are good that all data is lost permanently.
2150 For this case, a header+key-slot backup would often be enough. But keep
2151 in mind that a well-treated (!) HDD has roughly a failure risk of 5% per
2152 year. It is highly advisable to have a complete backup to protect
2156 * **6.6 What do I need to backup if I use "decrypt_derived"?**
2158 This is a script in Debian, intended for mounting /tmp or swap with a
2159 key derived from the volume key of an already decrypted device. If you
2160 use this for an device with data that should be persistent, you need to
2161 make sure you either do not lose access to that volume key or have a
2162 backup of the data. If you derive from a LUKS device, a header backup
2163 of that device would cover backing up the volume key. Keep in mind that
2164 this does not protect against disk loss.
2166 Note: If you recreate the LUKS header of the device you derive from
2167 (using luksFormat), the volume key changes even if you use the same
2168 passphrase(s) and you will not be able to decrypt the derived device
2169 with the new LUKS header.
2172 * **6.7 Does a backup compromise security?**
2174 Depends on how you do it. However if you do not have one, you are going
2175 to eventually lose your encrypted data.
2177 There are risks introduced by backups. For example if you
2178 change/disable a key-slot in LUKS, a binary backup of the partition will
2179 still have the old key-slot. To deal with this, you have to be able to
2180 change the key-slot on the backup as well, securely erase the backup or
2181 do a filesystem-level backup instead of a binary one.
2183 If you use dm-crypt, backup is simpler: As there is no key management,
2184 the main risk is that you cannot wipe the backup when wiping the
2185 original. However wiping the original for dm-crypt should consist of
2186 forgetting the passphrase and that you can do without actual access to
2189 In both cases, there is an additional (usually small) risk with binary
2190 backups: An attacker can see how many sectors and which ones have been
2191 changed since the backup. To prevent this, use a filesystem level
2192 backup method that encrypts the whole backup in one go, e.g. as
2193 described above with tar and GnuPG.
2195 My personal advice is to use one USB disk (low value data) or three
2196 disks (high value data) in rotating order for backups, and either use
2197 independent LUKS partitions on them, or use encrypted backup with tar
2200 If you do network-backup or tape-backup, I strongly recommend to go
2201 the filesystem backup path with independent encryption, as you
2202 typically cannot reliably delete data in these scenarios, especially
2203 in a cloud setting. (Well, you can burn the tape if it is under your
2207 * **6.8 What happens if I overwrite the start of a LUKS partition or damage the LUKS header or key-slots?**
2209 There are two critical components for decryption: The salt values in the
2210 key-slot descriptors of the header and the key-slots. For LUKS2 they
2211 are a bit better protected. but for LUKS1, these are right in the first
2212 sector. If the salt values are overwritten or changed, nothing (in the
2213 cryptographically strong sense) can be done to access the data, unless
2214 there is a backup of the LUKS header. If a key-slot is damaged, the
2215 data can still be read with a different key-slot, if there is a
2216 remaining undamaged and used key-slot. Note that in order to make a
2217 key-slot completely unrecoverable, changing about 4-6 bits in random
2218 locations of its 128kiB size is quite enough.
2221 * **6.9 What happens if I (quick) format a LUKS partition?**
2223 I have not tried the different ways to do this, but very likely you will
2224 have written a new boot-sector, which in turn overwrites the LUKS
2225 header, including the salts, making your data permanently irretrievable,
2226 unless you have a LUKS header backup. For LUKS2 this may still be
2227 recoverable without that header backup, for LUKS1 it is not. You may
2228 also damage the key-slots in part or in full. See also last item.
2231 * **6.10 How do I recover the volume key from a mapped LUKS1 container?**
2233 Note: LUKS2 uses the kernel keyring to store keys and hence this
2234 procedure does not work unless you have explicitly disabled the use of
2235 the keyring with "--disable-keyring" on opening.
2237 This is typically only needed if you managed to damage your LUKS1
2238 header, but the container is still mapped, i.e. "luksOpen"ed. It also
2239 helps if you have a mapped container that you forgot or do not know a
2240 passphrase for (e.g. on a long running server.)
2242 WARNING: Things go wrong, do a full backup before trying this!
2244 WARNING: This exposes the volume key of the LUKS1 container. Note that
2245 both ways to recreate a LUKS header with the old volume key described
2246 below will write the volume key to disk. Unless you are sure you have
2247 securely erased it afterwards, e.g. by writing it to an encrypted
2248 partition, RAM disk or by erasing the filesystem you wrote it to by a
2249 complete overwrite, you should change the volume key afterwards.
2250 Changing the volume key requires a full data backup, luksFormat and then
2251 restore of the backup. Alternatively the tool cryptsetup-reencrypt from
2252 the cryptsetup package can be used to change the volume key (see its
2253 man-page), but a full backup is still highly recommended.
2255 First, there is a script by Milan that automates the whole process,
2256 except generating a new LUKS1 header with the old volume key (it prints
2257 the command for that though):
2259 https://gitlab.com/cryptsetup/cryptsetup/blob/main/misc/luks-header-from-active
2261 You can also do this manually. Here is how:
2263 - Get the volume key from the device mapper. This is done by the
2264 following command. Substitute c5 for whatever you mapped to:
2266 # dmsetup table --target crypt --showkey /dev/mapper/c5
2269 0 200704 crypt aes-cbc-essiv:sha256
2270 a1704d9715f73a1bb4db581dcacadaf405e700d591e93e2eaade13ba653d0d09
2273 The result is actually one line, wrapped here for clarity. The long
2274 hex string is the volume key.
2276 - Convert the volume key to a binary file representation. You can do
2277 this manually, e.g. with hexedit. You can also use the tool "xxd"
2280 echo "a1704d9....53d0d09" | xxd -r -p > <volume-key-file>
2283 - Do a luksFormat to create a new LUKS1 header.
2285 NOTE: If your header is intact and you just forgot the passphrase,
2286 you can just set a new passphrase, see next sub-item.
2288 Unmap the device before you do that (luksClose). Then do
2290 cryptsetup luksFormat --volume-key-file=<volume-key-file> <luks device>
2292 Note that if the container was created with other than the default
2293 settings of the cryptsetup version you are using, you need to give
2294 additional parameters specifying the deviations. If in doubt, try the
2295 script by Milan. It does recover the other parameters as well.
2297 Side note: This is the way the decrypt_derived script gets at the volume
2298 key. It just omits the conversion and hashes the volume key string.
2300 - If the header is intact and you just forgot the passphrase, just
2301 set a new passphrase like this:
2303 cryptsetup luksAddKey --volume-key-file=<volume-key-file> <luks device>
2305 You may want to disable the old one afterwards.
2308 * **6.11 What does the on-disk structure of dm-crypt look like?**
2310 There is none. dm-crypt takes a block device and gives encrypted access
2311 to each of its blocks with a key derived from the passphrase given. If
2312 you use a cipher different than the default, you have to specify that as
2313 a parameter to cryptsetup too. If you want to change the password, you
2314 basically have to create a second encrypted device with the new
2315 passphrase and copy your data over. On the plus side, if you
2316 accidentally overwrite any part of a dm-crypt device, the damage will be
2317 limited to the area you overwrote.
2320 * **6.12 What does the on-disk structure of LUKS1 look like?**
2322 Note: For LUKS2, refer to the LUKS2 document referenced in Item 1.2
2324 A LUKS1 partition consists of a header, followed by 8 key-slot
2325 descriptors, followed by 8 key slots, followed by the encrypted data
2328 Header and key-slot descriptors fill the first 592 bytes. The key-slot
2329 size depends on the creation parameters, namely on the number of
2330 anti-forensic stripes, key material offset and volume key size.
2332 With the default parameters, each key-slot is a bit less than 128kiB in
2333 size. Due to sector alignment of the key-slot start, that means the key
2334 block 0 is at offset 0x1000-0x20400, key block 1 at offset
2335 0x21000-0x40400, and key block 7 at offset 0xc1000-0xe0400. The space
2336 to the next full sector address is padded with zeros. Never used
2337 key-slots are filled with what the disk originally contained there, a
2338 key-slot removed with "luksRemoveKey" or "luksKillSlot" gets filled with
2339 0xff. Due to 2MiB default alignment, start of the data area for
2340 cryptsetup 1.3 and later is at 2MiB, i.e. at 0x200000. For older
2341 versions, it is at 0x101000, i.e. at 1'052'672 bytes, i.e. at 1MiB +
2342 4096 bytes from the start of the partition. Incidentally,
2343 "luksHeaderBackup" for a LUKS container created with default parameters
2344 dumps exactly the first 2MiB (or 1'052'672 bytes for headers created
2345 with cryptsetup versions < 1.3) to file and "luksHeaderRestore" restores
2348 For non-default parameters, you have to figure out placement yourself.
2349 "luksDump" helps. See also next item. For the most common non-default
2350 settings, namely aes-xts-plain with 512 bit key, the offsets are: 1st
2351 keyslot 0x1000-0x3f800, 2nd keyslot 0x40000-0x7e000, 3rd keyslot
2352 0x7e000-0xbd800, ..., and start of bulk data at 0x200000.
2354 The exact specification of the format is here:
2355 https://gitlab.com/cryptsetup/cryptsetup/wikis/Specification
2357 For your convenience, here is the LUKS1 header with hex offsets.
2359 The spec counts key-slots from 1 to 8, but the cryptsetup tool counts
2360 from 0 to 7. The numbers here refer to the cryptsetup numbers.
2363 Refers to LUKS1 On-Disk Format Specification Version 1.2.3
2367 offset length name data type description
2368 -----------------------------------------------------------------------
2369 0x0000 0x06 magic byte[] 'L','U','K','S', 0xba, 0xbe
2371 0x0006 0x02 version uint16_t LUKS version
2373 0x0008 0x20 cipher-name char[] cipher name spec.
2375 0x0028 0x20 cipher-mode char[] cipher mode spec.
2377 0x0048 0x20 hash-spec char[] hash spec.
2379 0x0068 0x04 payload-offset uint32_t bulk data offset in sectors
2380 104 4 (512 bytes per sector)
2381 0x006c 0x04 key-bytes uint32_t number of bytes in key
2383 0x0070 0x14 mk-digest byte[] volume key checksum
2384 112 20 calculated with PBKDF2
2385 0x0084 0x20 mk-digest-salt byte[] salt for PBKDF2 when
2386 132 32 calculating mk-digest
2387 0x00a4 0x04 mk-digest-iter uint32_t iteration count for PBKDF2
2388 164 4 when calculating mk-digest
2389 0x00a8 0x28 uuid char[] partition UUID
2391 0x00d0 0x30 key-slot-0 key slot key slot 0
2393 0x0100 0x30 key-slot-1 key slot key slot 1
2395 0x0130 0x30 key-slot-2 key slot key slot 2
2397 0x0160 0x30 key-slot-3 key slot key slot 3
2399 0x0190 0x30 key-slot-4 key slot key slot 4
2401 0x01c0 0x30 key-slot-5 key slot key slot 5
2403 0x01f0 0x30 key-slot-6 key slot key slot 6
2405 0x0220 0x30 key-slot-7 key slot key slot 7
2411 offset length name data type description
2412 -------------------------------------------------------------------------
2413 0x0000 0x04 active uint32_t key slot enabled/disabled
2415 0x0004 0x04 iterations uint32_t PBKDF2 iteration count
2417 0x0008 0x20 salt byte[] PBKDF2 salt
2419 0x0028 0x04 key-material-offset uint32_t key start sector
2420 40 4 (512 bytes/sector)
2421 0x002c 0x04 stripes uint32_t number of anti-forensic
2426 * **6.13 What is the smallest possible LUKS1 container?**
2428 Note: From cryptsetup 1.3 onwards, alignment is set to 1MB. With modern
2429 Linux partitioning tools that also align to 1MB, this will result in
2430 alignment to 2k sectors and typical Flash/SSD sectors, which is highly
2431 desirable for a number of reasons. Changing the alignment is not
2434 That said, with default parameters, the data area starts at exactly 2MB
2435 offset (at 0x101000 for cryptsetup versions before 1.3). The smallest
2436 data area you can have is one sector of 512 bytes. Data areas of 0
2437 bytes can be created, but fail on mapping.
2439 While you cannot put a filesystem into something this small, it may
2440 still be used to contain, for example, key. Note that with current
2441 formatting tools, a partition for a container this size will be 3MiB
2442 anyways. If you put the LUKS container into a file (via losetup and a
2443 loopback device), the file needs to be 2097664 bytes in size, i.e. 2MiB
2446 The two ways to influence the start of the data area are key-size and
2449 For alignment, you can go down to 1 on the parameter. This will still
2450 leave you with a data-area starting at 0x101000, i.e. 1MiB+4096B
2451 (default parameters) as alignment will be rounded up to the next
2452 multiple of 8 (i.e. 4096 bytes) If in doubt, do a dry-run on a larger
2453 file and dump the LUKS header to get actual information.
2455 For key-size, you can use 128 bit (e.g. AES-128 with CBC), 256 bit
2456 (e.g. AES-256 with CBC) or 512 bit (e.g. AES-256 with XTS mode). You
2457 can do 64 bit (e.g. blowfish-64 with CBC), but anything below 128 bit
2458 has to be considered insecure today.
2460 Example 1 - AES 128 bit with CBC:
2462 cryptsetup luksFormat -s 128 --align-payload=8 <device>
2464 This results in a data offset of 0x81000, i.e. 516KiB or 528384
2465 bytes. Add one 512 byte sector and the smallest LUKS container size
2466 with these parameters is 516KiB + 512B or 528896 bytes.
2468 Example 2 - Blowfish 64 bit with CBC (WARNING: insecure):
2470 cryptsetup luksFormat -c blowfish -s 64 --align-payload=8 /dev/loop0
2472 This results in a data offset of 0x41000, i.e. 260kiB or 266240
2473 bytes, with a minimal LUKS1 container size of 260kiB + 512B or 266752
2477 * **6.14 I think this is overly complicated. Is there an alternative?**
2479 Not really. Encryption comes at a price. You can use plain dm-crypt to
2480 simplify things a bit. It does not allow multiple passphrases, but on
2481 the plus side, it has zero on disk description and if you overwrite some
2482 part of a plain dm-crypt partition, exactly the overwritten parts are
2483 lost (rounded up to full sectors).
2485 * **6.15 Can I clone a LUKS container?**
2487 You can, but it breaks security, because the cloned container has the
2488 same header and hence the same volume key. Even if you change the
2489 passphrase(s), the volume key stays the same. That means whoever has
2490 access to one of the clones can decrypt them all, completely bypassing
2493 While you can use cryptsetup-reencrypt to change the volume key,
2494 this is probably more effort than to create separate LUKS containers
2497 The right way to do this is to first luksFormat the target container,
2498 then to clone the contents of the source container, with both containers
2499 mapped, i.e. decrypted. You can clone the decrypted contents of a LUKS
2500 container in binary mode, although you may run into secondary issues
2501 with GUIDs in filesystems, partition tables, RAID-components and the
2502 like. These are just the normal problems binary cloning causes.
2504 Note that if you need to ship (e.g.) cloned LUKS containers with a
2505 default passphrase, that is fine as long as each container was
2506 individually created (and hence has its own volume key). In this case,
2507 changing the default passphrase will make it secure again.
2509 * **6.16 How to convert the printed volume key to a raw one?**
2510 A volume key printed via something like:
2512 cryptsetup --dump-volume-key luksDump /dev/<device> >volume-key
2514 (i.e. without using `--volume-key-file`), which gives something like:
2516 LUKS header information for /dev/<device>
2518 Cipher mode: xts-plain64
2519 Payload offset: 32768
2520 UUID: 6e914442-e8b5-4eb5-98c4-5bf0cf17ecad
2522 MK dump: e0 3f 15 c2 0f e5 80 ab 35 b4 10 03 ae 30 b9 5d
2523 4c 0d 28 9e 1b 0f e3 b0 50 57 ef d4 4d 53 a0 12
2524 b7 4e 43 a1 20 7e c5 02 1f f1 f5 08 04 3c f5 20
2525 a6 0b 23 f6 7b 53 55 aa 22 d8 aa 02 e0 2f d5 04
2527 can be converted to the raw volume key for example via:
2529 sed -E -n '/^MK dump:\t/,/^[^\t]/{0,/^MK dump:\t/s/^MK dump://; /^([^\t].*)?$/q; s/\t+//p;};' volume-key | xxd -r -p
2535 # 7. Interoperability with other Disk Encryption Tools
2538 * **7.1 What is this section about?**
2540 Cryptsetup for plain dm-crypt can be used to access a number of on-disk
2541 formats created by tools like loop-aes patched into losetup. This
2542 sometimes works and sometimes does not. This section collects insights
2543 into what works, what does not and where more information is required.
2545 Additional information may be found in the mailing-list archives,
2546 mentioned at the start of this FAQ document. If you have a solution
2547 working that is not yet documented here and think a wider audience may
2548 be interested, please email the FAQ maintainer.
2551 * **7.2 loop-aes: General observations.**
2553 One problem is that there are different versions of losetup around.
2554 loop-aes is a patch for losetup. Possible problems and deviations
2555 from cryptsetup option syntax include:
2557 - Offsets specified in bytes (cryptsetup: 512 byte sectors)
2559 - The need to specify an IV offset
2561 - Encryption mode needs specifying (e.g. "-c twofish-cbc-plain")
2563 - Key size needs specifying (e.g. "-s 128" for 128 bit keys)
2565 - Passphrase hash algorithm needs specifying
2567 Also note that because plain dm-crypt and loop-aes format does not have
2568 metadata, and while the loopAES extension for cryptsetup tries
2569 autodetection (see command loopaesOpen), it may not always work. If you
2570 still have the old set-up, using a verbosity option (-v) on mapping with
2571 the old tool or having a look into the system logs after setup could
2572 give you the information you need. Below, there are also some things
2573 that worked for somebody.
2576 * **7.3 loop-aes patched into losetup on Debian 5.x, kernel 2.6.32**
2578 In this case, the main problem seems to be that this variant of
2579 losetup takes the offset (-o option) in bytes, while cryptsetup takes
2580 it in sectors of 512 bytes each.
2582 Example: The losetup command
2584 losetup -e twofish -o 2560 /dev/loop0 /dev/sdb1
2585 mount /dev/loop0 mount-point
2589 cryptsetup create -c twofish -o 5 --skip 5 e1 /dev/sdb1
2590 mount /dev/mapper/e1 mount-point
2594 * **7.4 loop-aes with 160 bit key**
2596 This seems to be sometimes used with twofish and blowfish and represents
2597 a 160 bit ripemed160 hash output padded to 196 bit key length. It seems
2598 the corresponding options for cryptsetup are
2600 --cipher twofish-cbc-null -s 192 -h ripemd160:20
2604 * **7.5 loop-aes v1 format OpenSUSE**
2606 Apparently this is done by older OpenSUSE distros and stopped working
2607 from OpenSUSE 12.1 to 12.2. One user had success with the following:
2609 cryptsetup create <target> <device> -c aes -s 128 -h sha256
2613 * **7.6 Kernel encrypted loop device (cryptoloop)**
2615 There are a number of different losetup implementations for using
2616 encrypted loop devices so getting this to work may need a bit of
2619 NOTE: Do NOT use this for new containers! Some of the existing
2620 implementations are insecure and future support is uncertain.
2622 Example for a compatible mapping:
2624 losetup -e twofish -N /dev/loop0 /image.img
2628 cryptsetup create image_plain /image.img -c twofish-cbc-plain -H plain
2630 with the mapping being done to /dev/mapper/image_plain instead of
2635 Cipher, mode and password hash (or no hash):
2637 -e cipher [-N] => -c cipher-cbc-plain -H plain [-s 256]
2638 -e cipher => -c cipher-cbc-plain -H ripemd160 [-s 256]
2641 Key size and offsets (losetup: bytes, cryptsetuop: sectors of 512 bytes):
2644 -o 2560 => -o 5 -p 5 # 2560/512 = 5
2647 There is no replacement for --pass-fd, it has to be emulated using
2648 keyfiles, see the cryptsetup man-page.
2651 # 8. Issues with Specific Versions of cryptsetup
2654 * **8.1 When using the create command for plain dm-crypt with cryptsetup 1.1.x, the mapping is incompatible and my data is not accessible anymore!**
2656 With cryptsetup 1.1.x, the distro maintainer can define different
2657 default encryption modes. You can check the compiled-in defaults using
2658 "cryptsetup --help". Moreover, the plain device default changed because
2659 the old IV mode was vulnerable to a watermarking attack.
2661 If you are using a plain device and you need a compatible mode, just
2662 specify cipher, key size and hash algorithm explicitly. For
2663 compatibility with cryptsetup 1.0.x defaults, simple use the following:
2665 cryptsetup create -c aes-cbc-plain -s 256 -h ripemd160 <name> <dev>
2667 LUKS stores cipher and mode in the metadata on disk, avoiding this
2671 * **8.2 cryptsetup on SLED 10 has problems...**
2673 SLED 10 is missing an essential kernel patch for dm-crypt, which is
2674 broken in its kernel as a result. There may be a very old version of
2675 cryptsetup (1.0.x) provided by SLED, which should also not be used
2676 anymore as well. My advice would be to drop SLED 10.
2679 * **8.3 Gcrypt 1.6.x and later break Whirlpool**
2681 It is the other way round: In gcrypt 1.5.x, Whirlpool is broken and it
2682 was fixed in 1.6.0 and later. If you selected whirlpool as hash on
2683 creation of a LUKS container, it does not work anymore with the fixed
2684 library. This shows one serious risk of using rarely used settings.
2686 Note that at the time this FAQ item was written, 1.5.4 was the latest
2687 1.5.x version and it has the flaw, i.e. works with the old Whirlpool
2688 version. Possibly later 1.5.x versions will work as well. If not,
2691 The only two ways to access older LUKS containers created with Whirlpool
2692 are to either decrypt with an old gcrypt version that has the flaw or to
2693 use a compatibility feature introduced in cryptsetup 1.6.4 and gcrypt
2694 1.6.1 or later. Version 1.6.0 cannot be used.
2698 - Make at least a header backup or better, refresh your full backup.
2699 (You have a full backup, right? See Item 6.1 and following.)
2701 - Make sure you have cryptsetup 1.6.4 or later and check the gcrypt
2704 cryptsetup luksDump <your luks device> --debug | grep backend
2706 If gcrypt is at version 1.5.x or before:
2708 - Reencrypt the LUKS header with a different hash. (Requires entering
2709 all keyslot passphrases. If you do not have all, remove the ones you
2710 do not have before.):
2712 cryptsetup-reencrypt --keep-key --hash sha256 <your luks device>
2714 If gcrypt is at version 1.6.1 or later:
2716 - Patch the hash name in the LUKS header from "whirlpool" to
2717 "whirlpool_gcryptbug". This activates the broken implementation.
2718 The detailed header layout is in Item 6.12 of this FAQ and in the
2719 LUKS on-disk format specification. One way to change the hash is
2720 with the following command:
2722 echo -n -e 'whirlpool_gcryptbug\0' | dd of=<luks device> bs=1 seek=72 conv=notrunc
2724 - You can now open the device again. It is highly advisable to change
2725 the hash now with cryptsetup-reencrypt as described above. While you
2726 can reencrypt to use the fixed whirlpool, that may not be a good idea
2727 as almost nobody seems to use it and hence the long time until the
2731 # 9. The Initrd question
2734 * **9.1 My initrd is broken with cryptsetup**
2736 That is not nice! However the initrd is supplied by your distribution,
2737 not by the cryptsetup project and hence you should complain to them. We
2738 cannot really do anything about it.
2741 * **9.2 CVE-2016-4484 says cryptsetup is broken!**
2743 Not really. It says the initrd in some Debian versions have a behavior
2744 that under some very special and unusual conditions may be considered
2747 What happens is that you can trick the initrd to go to a rescue-shell if
2748 you enter the LUKS password wrongly in a specific way. But falling back
2749 to a rescue shell on initrd errors is a sensible default behavior in the
2750 first place. It gives you about as much access as booting a rescue
2751 system from CD or USB-Stick or as removing the disk would give you. So
2752 this only applies when an attacker has physical access, but cannot boot
2753 anything else or remove the disk. These will be rare circumstances
2754 indeed, and if you rely on the default distribution initrd to keep you
2755 safe under these circumstances, then you have bigger problems than this
2756 somewhat expected behavior.
2758 The CVE was exaggerated and should not be assigned to upstream
2759 cryptsetup in the first place (it is a distro specific initrd issue).
2760 It was driven more by a try to make a splash for self-aggrandizement,
2761 than by any actual security concerns. Ignore it.
2764 * **9.3 How do I do my own initrd with cryptsetup?**
2766 Note: The instructions here apply to an initrd in initramfs format, not
2767 to an initrd in initrd format. The latter is a filesystem image, not a
2768 cpio-archive, and seems to not be widely used anymore.
2770 It depends on the distribution. Below, I give a very simple example and
2771 step-by-step instructions for Debian. With a bit of work, it should be
2772 possible to adapt this to other distributions. Note that the
2773 description is pretty general, so if you want to do other things with an
2774 initrd it provides a useful starting point for that too.
2776 01) Unpacking an existing initrd to use as template
2778 A Linux initrd is in gzip'ed cpio format. To unpack it, use something
2781 mkdir tmp; cd tmp; cat ../initrd | gunzip | cpio -id
2783 After this, you have the full initrd content in tmp/
2785 02) Inspecting the init-script
2787 The init-script is the only thing the kernel cares about. All activity
2788 starts there. Its traditional location is /sbin/init on disk, but /init
2789 in an initrd. In an initrd unpacked as above it is tmp/init.
2791 While init can be a binary despite usually being called "init script",
2792 in Debian the main init on the root partition is a binary, but the init
2793 in the initrd (and only that one is called by the kernel) is a script
2794 and starts like this:
2799 The "sh" used here is in tmp/bin/sh as just unpacked, and in Debian it
2800 currently is a busybox.
2802 03) Creating your own initrd
2804 The two examples below should give you most of what is needed. This is
2805 tested with LUKS1 and should work with LUKS2 as well. If not, please
2808 Here is a really minimal example. It does nothing but set up some
2809 things and then drop to an interactive shell. It is perfect to try out
2810 things that you want to go into the init-script.
2813 export PATH=/sbin:/bin
2814 [ -d /sys ] || mkdir /sys
2815 [ -d /proc ] || mkdir /proc
2816 [ -d /tmp ] || mkdir /tmp
2817 mount -t sysfs -o nodev,noexec,nosuid sysfs /sys
2818 mount -t proc -o nodev,noexec,nosuid proc /proc
2819 echo "initrd is running, starting BusyBox..."
2820 exec /bin/sh --login
2823 Here is an example that opens the first LUKS-partition it finds with the
2824 hard-coded password "test2" and then mounts it as root-filesystem. This
2825 is intended to be used on an USB-stick that after boot goes into a safe,
2826 as it contains the LUKS-passphrase in plain text and is not secure to be
2827 left in the system. The script contains debug-output that should make it
2828 easier to see what is going on. Note that the final hand-over to the init
2829 on the encrypted root-partition is done by "exec switch_root /mnt/root
2830 /sbin/init", after mounting the decrypted LUKS container with "mount
2831 /dev/mapper/c1 /mnt/root". The second argument of switch_root is relative
2832 to the first argument, i.e. the init started with this command is really
2833 /mnt/sbin/init before switch_root runs.
2836 export PATH=/sbin:/bin
2837 [ -d /sys ] || mkdir /sys
2838 [ -d /proc ] || mkdir /proc
2839 [ -d /tmp ] || mkdir /tmp
2840 mount -t sysfs -o nodev,noexec,nosuid sysfs /sys
2841 mount -t proc -o nodev,noexec,nosuid proc /proc
2842 echo "detecting LUKS containers in sda1-10, sdb1-10"; sleep 1
2845 for j in 1 2 3 4 5 6 7 8 9 10
2850 cryptsetup isLuks $d >/dev/null 2>&1
2852 echo -n " result: "$r""
2853 # 0 = is LUKS, 1 = is not LUKS, 4 = other error
2854 if expr $r = 0 > /dev/null
2856 echo " is LUKS, attempting unlock"
2857 echo -n "test2" | cryptsetup luksOpen --key-file=- $d c1
2859 echo " result of unlock attempt: "$r""
2861 if expr $r = 0 > /dev/null
2863 echo "*** LUKS partition unlocked, switching root ***
2864 echo " (waiting 30 seconds before doing that)"
2865 mount /dev/mapper/c1 /mnt/root
2867 exec switch_root /mnt/root /sbin/init
2874 echo "FAIL finding root on LUKS, loading BusyBox..."; sleep 5
2875 exec /bin/sh --login
2878 04) What if I want a binary in the initrd, but libraries are missing?
2880 That is a bit tricky. One option is to compile statically, but that
2881 does not work for everything. Debian puts some libraries into lib/ and
2882 lib64/ which are usually enough. If you need more, you can add the
2883 libraries you need there. That may or may not need a configuration
2884 change for the dynamic linker "ld" as well. Refer to standard Linux
2885 documentation on how to add a library to a Linux system. A running
2886 initrd is just a running Linux system after all, it is not special in
2889 05) How do I repack the initrd?
2891 Simply repack the changed directory. While in tmp/, do
2894 find . | cpio --create --format='newc' | gzip > ../new_initrd
2896 Rename "new_initrd" to however you want it called (the name of
2897 the initrd is a kernel-parameter) and move to /boot. That is it.
2900 # 10. LUKS2 Questions
2903 * **10.1 Is the cryptography of LUKS2 different?**
2905 Mostly not. The header has changed in its structure, but the
2906 cryptography is the same. The one exception is that PBKDF2 has been
2907 replaced by Argon2 to give better resilience against attacks by
2908 graphics cards and other hardware with lots of computing power but
2909 limited local memory per computing element.
2912 * **10.2 What new features does LUKS2 have?**
2914 There are quite a few. I recommend reading the man-page and the on-disk
2915 format specification, see Item 1.2.
2918 - A lot of the metadata is JSON, allowing for easier extension
2919 - Max 32 key-slots per default
2920 - Better protection for bad passphrases now available with Argon2
2921 - Authenticated encryption
2922 - The LUKS2 header is less vulnerable to corruption and has a 2nd copy
2925 * **10.3 Why does LUKS2 need so much memory?**
2927 LUKS2 uses Argon2 instead of PBKDF2. That causes the increase in memory.
2931 * **10.4 Why use Argon2 in LUKS 2 instead of PBKDF2?**
2933 LUKS tries to be secure with not-so-good passwords. Bad passwords need to
2934 be protected in some way against an attacker that just tries all possible
2935 combinations. (For good passwords, you can just wait for the attacker to
2936 die of old age...) The situation with LUKS is not quite the same as with a
2937 password stored in a database, but there are similarities.
2939 LUKS does not store passwords on disk. Instead, the passwords are used to
2940 decrypt the volume-key with it and that one is stored on disk in encrypted
2941 form. If you have a good password, with, say, more than 80 bits of
2942 entropy, you could just put the password through a single crypto-hash (to
2943 turn it into something that can be used as a key) and that would be secure.
2944 This is what plain dm-crypt does.
2946 If the password has lower entropy, you want to make this process cost some
2947 effort, so that each try takes time and resources and slows the attacker
2948 down. LUKS1 uses PBKDF2 for that, adding an iteration count and a salt.
2949 The iteration count is per default set to that it takes 1 second per try on
2950 the CPU of the device where the respective passphrase was set. The salt is
2951 there to prevent precomputation.
2953 The problem with that is that if you use a graphics card, you can massively
2954 speed up these computations as PBKDF2 needs very little memory to compute
2955 it. A graphics card is (grossly simplified) a mass of small CPUs with some
2956 small very fast local memory per CPU and a large slow memory (the 4/6/8 GB
2957 a current card may have). If you can keep a computation in the small,
2958 CPU-local memory, you can gain a speed factor of 1000 or more when trying
2959 passwords with PBKDF2.
2961 Argon2 was created to address this problem. It adds a "large memory
2962 property" where computing the result with less memory than the memory
2963 parameter requires is massively (exponentially) slowed down. That means,
2964 if you set, for example, 4GB of memory, computing Argon2 on a graphics card
2965 with around 100kB of memory per "CPU" makes no sense at all because it is
2966 far too slow. An attacker has hence to use real CPUs and furthermore is
2967 limited by main memory bandwidth.
2969 Hence the large amount of memory used is a security feature and should not
2970 be turned off or reduced. If you really (!) understand what you are doing
2971 and can assure good passwords, you can either go back to PBKDF2 or set a
2972 low amount of memory used for Argon2 when creating the header.
2975 * **10.5 LUKS2 is insecure! It uses less memory than the Argon2 RFC say!**
2977 Well, not really. The RFC recommends 6GiB of memory for use with disk
2978 encryption. That is a bit insane and something clearly went wrong in the
2979 standardization process here. First, that makes Argon2 unusable on any 32
2980 bit Linux and that is clearly a bad thing. Second, there are many small
2981 Linux devices around that do not have 6GiB of RAM in the first place. For
2982 example, the current Raspberry Pi has 1GB, 2GB or 4GB of RAM, and with the
2983 RFC recommendations, none of these could compute Argon2 hashes.
2985 Hence LUKS2 uses a more real-world approach. Iteration is set to a
2986 minimum of 4 because there are some theoretical attacks that work up to an
2987 iteration count of 3. The thread parameter is set to 4. To achieve 2
2988 second/slot unlock time, LUKS2 adjusts the memory parameter down if
2989 needed. In the other direction, it will respect available memory and not
2990 exceed it. On a current PC, the memory parameter will be somewhere around
2991 1GB, which should be quite generous. The minimum I was able to set in an
2992 experiment with "-i 1" was 400kB of memory and that is too low to be
2993 secure. A Raspberry Pi would probably end up somewhere around 50MB (have
2994 not tried it) and that should still be plenty.
2996 That said, if you have a good, high-entropy passphrase, LUKS2 is secure
2997 with any memory parameter.
3000 * **10.6 How does re-encryption store data while it is running?**
3002 All metadata necessary to perform a recovery of said segment (in case of
3003 crash) is stored in the LUKS2 metadata area. No matter if the LUKS2
3004 reencryption was run in online or offline mode.
3007 * **10.7 What do I do if re-encryption crashes?**
3009 In case of a reencryption application crash, try to close the original
3010 device via following command first:
3012 cryptsetup close <my_crypt_device>.
3014 Cryptsetup assesses if it's safe to teardown the reencryption device stack
3015 or not. It will also cut off I/O (via dm-error mapping) to current
3016 hotzone segment (to make later recovery possible). If it can't be torn
3017 down, i.e. due to a mounted fs, you must unmount the filesystem first.
3018 Never try to tear down reencryption dm devices manually using e.g.
3019 dmsetup tool, at least not unless cryptsetup says it's safe to do so. It
3020 could damage the data beyond repair.
3023 * **10.8 Do I need to enter two passphrases to recover a crashed re-encryption?**
3025 Cryptsetup (command line utility) expects the passphrases to be identical
3026 for the keyslot containing old volume key and for the keyslot containing
3027 new one. So the recovery happens during normal the "cryptsetup open"
3028 operation or the equivalent during boot.
3030 Re-encryption recovery can be also performed in offline mode by
3031 the "cryptsetup repair" command.
3034 * **10.9 What is an unbound keyslot and what is it used for?**
3036 Quite simply, an 'unbound key' is an independent 'key' stored in a luks2
3037 keyslot that cannot be used to unlock a LUKS2 data device. More specifically,
3038 an 'unbound key' or 'unbound luks2 keyslot' contains a secret that is not
3039 currently associated with any data/crypt segment (encrypted area) in the
3040 LUKS2 'Segments' section (displayed by luksDump).
3042 This is a bit of a more general idea. It basically allows one to use a
3043 keyslot as a container for a key to be used in other things than decrypting
3046 As of April 2020, the following uses are defined:
3048 1) LUKS2 re-encryption. The new volume key is stored in an unbound keyslot
3049 which becomes a regular LUKS2 keyslot later when re-encryption is
3052 2) Somewhat similar is the use with a wrapped key scheme (e.g. with the
3053 paes cipher). In this case, the VK (Volume Key) stored in a keyslot
3054 is an encrypted binary binary blob. The KEK (Key Encryption Key) for
3055 that blob may be refreshed (Note that this KEK is not managed by
3056 cryptsetup!) and the binary blob gets changed. The KEK refresh process
3057 uses an 'unbound keyslot'. First the future effective VK is placed
3058 in the unbound keyslot and later it gets turned into the new real VK
3059 (and bound to the respective crypt segment).
3062 * **10.10 What about the size of the LUKS2 header**?
3064 While the LUKS1 header has a fixed size that is determined by the cipher
3065 spec (see Item 6.12), LUKS2 is more variable. The default size is 16MB,
3066 but it can be adjusted on creation by using the --luks2-metadata-size
3067 and --luks2-keyslots-size options. Refer to the man-page for details.
3068 While adjusting the size in an existing LUKS2 container is possible,
3069 it is somewhat complicated and risky. My advice is to do a backup,
3070 recreate the container with changed parameters and restore that backup.
3073 * **10.11 Does LUKS2 store metadata anywhere except in the header?**
3075 It does not. But note that if you use the experimental integrity support,
3076 there will be an integrity header as well at the start of the data area
3077 and things get a bit more complicated. All metadata will still be at the
3078 start of the device, nothing gets stored somewhere in the middle or at
3081 * **10.12 What is a LUKS2 Token?**
3083 A LUKS2 token is an object that describes "how to get a passphrase or
3084 key" to unlock particular keyslot. A LUKS2 token is stored as json data
3085 in the LUKS2 header. The token can be related to all keyslots or a
3086 specific one. As the token is stored in JSON formay it is text by
3087 default but binary data can be encoded into it according to the JSON
3090 Documentation on the last changes to LUKS2 tokens can be found in the
3091 release notes. As of version 2.4 of cryptsetup, there are significant
3092 features. The standard documentation for working with tokens is
3093 in the luks2 reference available as PDF on the project page.
3096 # 11. References and Further Reading
3099 * **Purpose of this Section**
3101 The purpose of this section is to collect references to all materials
3102 that do not fit the FAQ but are relevant in some fashion. This can be
3103 core topics like the LUKS spec or disk encryption, but it can also be
3104 more tangential, like secure storage management or cryptography used in
3105 LUKS. It should still have relevance to cryptsetup and its
3108 If you want to see something added here, send email to the maintainer
3109 (or the cryptsetup mailing list) giving an URL, a description (1-3 lines
3110 preferred) and a section to put it in. You can also propose new
3113 At this time I would like to limit the references to things that are
3114 available on the web.
3116 * **Specifications**
3118 - LUKS on-disk format spec: See Item 1.2
3120 * **Other Documentation**
3122 - Arch Linux on LUKS, LVM and full-disk encryption:
3123 https://wiki.archlinux.org/index.php/Dm-crypt/Encrypting_an_entire_system
3127 - Some code examples are in the source package under docs/examples
3129 - LUKS AF Splitter in Ruby by John Lane: https://rubygems.org/gems/afsplitter
3131 * **Brute-forcing passphrases**
3133 - http://news.electricalchemy.net/2009/10/password-cracking-in-cloud-part-5.html
3135 - https://it.slashdot.org/story/12/12/05/0623215/new-25-gpu-monster-devours-strong-passwords-in-minutes
3139 * **SSD and Flash Disk Related**
3141 * **Disk Encryption**
3143 * **Attacks Against Disk Encryption**
3145 * **Risk Management as Relevant for Disk Encryption**
3149 * **Secure Storage**
3153 In no particular order: