8 6. Backup and Data Recovery
9 7. Interoperability with other Disk Encryption Tools
10 8. Issues with Specific Versions of cryptsetup
19 This is the FAQ (Frequently Asked Questions) for cryptsetup. It
20 covers Linux disk encryption with plain dm-crypt (one passphrase,
21 no management, no metadata on disk) and LUKS (multiple user keys
22 with one master key, anti-forensic features, metadata block at
23 start of device, ...). The latest version of this FAQ should
24 usually be available at
25 http://code.google.com/p/cryptsetup/wiki/FrequentlyAskedQuestions
30 ATTENTION: If you are going to read just one thing, make it the
31 section on Backup and Data Recovery. By far the most questions on
32 the cryptsetup mailing list are from people that managed to damage
33 the start of their LUKS partitions, i.e. the LUKS header. In
34 most cases, there is nothing that can be done to help these poor
35 souls recover their data. Make sure you understand the problem and
36 limitations imposed by the LUKS security model BEFORE you face
37 such a disaster! In particular, make sure you have a current header
38 backup before doing any potentially dangerous operations.
40 SSDs/FLASH DRIVES: SSDs and Flash are different. Currently it is
41 unclear how to get LUKS or plain dm-crypt to run on them with the
42 full set of security features intact. This may or may not be a
43 problem, depending on the attacher model. See Section 5.17.
45 BACKUP: Yes, encrypted disks die, just as normal ones do. A full
46 backup is mandatory, see Section "6. Backup and Data Recovery" on
47 options for doing encrypted backup.
49 CLONING/IMAGING: If you clone or image a LUKS container, you make a
50 copy of the LUKS header and the master key will stay the same!
51 That means that if you distribute an image to several machines, the
52 same master key will be used on all of them, regardless of whether
53 you change the passphrases. Do NOT do this! If you do, a root-user
54 on any of the machines with a mapped (decrypted) container or a
55 passphrase on that machine can decrypt all other copies, breaking
56 security. See also Item 6.15.
58 DISTRIBUTION INSTALLERS: Some distribution installers offer to
59 create LUKS containers in a way that can be mistaken as activation
60 of an existing container. Creating a new LUKS container on top of
61 an existing one leads to permanent, complete and irreversible data
62 loss. It is strongly recommended to only use distribution
63 installers after a complete backup of all LUKS containers has been
66 NO WARNING ON NON-INTERACTIVE FORMAT: If you feed cryptsetup from
67 STDIN (e.g. via GnuPG) on LUKS format, it does not give you the
68 warning that you are about to format (and e.g. will lose any
69 pre-existing LUKS container on the target), as it assumes it is
70 used from a script. In this scenario, the responsibility for
71 warning the user and possibly checking for an existing LUKS header
72 is shifted to the script. This is a more general form of the
75 LUKS PASSPHRASE IS NOT THE MASTER KEY: The LUKS passphrase is not
76 used in deriving the master key. It is used in decrypting a master
77 key that is randomly selected on header creation. This means that
78 if you create a new LUKS header on top of an old one with
79 exactly the same parameters and exactly the same passphrase as the
80 old one, it will still have a different master key and your data
81 will be permanently lost.
83 PASSPHRASE CHARACTER SET: Some people have had difficulties with
84 this when upgrading distributions. It is highly advisable to only
85 use the 95 printable characters from the first 128 characters of
86 the ASCII table, as they will always have the same binary
87 representation. Other characters may have different encoding
88 depending on system configuration and your passphrase will not
89 work with a different encoding. A table of the standardized first
90 128 ASCII characters can, e.g. be found on
91 http://en.wikipedia.org/wiki/ASCII
94 * 1.3 System specific warnings
96 - Ubuntu as of 4/2011: It seems the installer offers to create
97 LUKS partitions in a way that several people mistook for an offer
98 to activate their existing LUKS partition. The installer gives no
99 or an inadequate warning and will destroy your old LUKS header,
100 causing permanent data loss. See also the section on Backup and
103 This issue has been acknowledged by the Ubuntu dev team, see here:
104 http://launchpad.net/bugs/420080
106 Update 7/2012: I am unsure whether this has been fixed by now, best
110 * 1.4 My LUKS-device is broken! Help!
112 First: Do not panic! In many cases the data is still recoverable.
113 Do not do anything hasty! Steps:
115 - Take some deep breaths. Maybe add some relaxing music. This may
116 sound funny, but I am completely serious. Often, critical damage is
117 done only after the initial problem.
119 - Do not reboot. The keys mays still be in the kernel if the device
122 - Make sure others do not reboot the system.
124 - Do not write to your disk without a clear understanding why this
125 will not make matters worse. Do a sector-level backup before any
126 writes. Often you do not need to write at all to get enough access
127 to make a backup of the data.
131 - Read section 6 of this FAQ.
133 - Ask on the mailing-list if you need more help.
136 * 1.5 Who wrote this?
138 Current FAQ maintainer is Arno Wagner <arno@wagner.name>. Other
139 contributors are listed at the end. If you want to contribute, send
140 your article, including a descriptive headline, to the maintainer,
141 or the dm-crypt mailing list with something like "FAQ ..." in the
142 subject. You can also send more raw information and have me write
143 the section. Please note that by contributing to this FAQ, you
144 accept the license described below.
146 This work is under the "Attribution-Share Alike 3.0 Unported"
147 license, which means distribution is unlimited, you may create
148 derived works, but attributions to original authors and this
149 license statement must be retained and the derived work must be
150 under the same license. See
151 http://creativecommons.org/licenses/by-sa/3.0/ for more details of
154 Side note: I did text license research some time ago and I think
155 this license is best suited for the purpose at hand and creates the
159 * 1.5 Where is the project website?
161 There is the project website at http://code.google.com/p/cryptsetup/
162 Please do not post questions there, nobody will read them. Use
163 the mailing-list instead.
166 * 1.6 Is there a mailing-list?
168 Instructions on how to subscribe to the mailing-list are at on the
169 project website. People are generally helpful and friendly on the
172 The question of how to unsubscribe from the list does crop up
173 sometimes. For this you need your list management URL, which is
174 sent to you initially and once at the start of each month. Go to
175 the URL mentioned in the email and select "unsubscribe". This page
176 also allows you to request a password reminder.
178 Alternatively, you can send an Email to dm-crypt-request@saout.de
179 with just the word "help" in the subject or message body. Make sure
180 to send it from your list address.
182 The mailing list archive is here:
183 http://dir.gmane.org/gmane.linux.kernel.device-mapper.dm-crypt
189 * 2.1 What is the difference between "plain" and LUKS format?
191 First, unless you happen to understand the cryptographic background
192 well, you should use LUKS. It does protect the user from a lot of
193 common mistakes. Plain dm-crypt is for experts.
195 Plain format is just that: It has no metadata on disk, reads all
196 parameters from the commandline (or the defaults), derives a
197 master-key from the passphrase and then uses that to de-/encrypt
198 the sectors of the device, with a direct 1:1 mapping between
199 encrypted and decrypted sectors.
201 Primary advantage is high resilience to damage, as one damaged
202 encrypted sector results in exactly one damaged decrypted sector.
203 Also, it is not readily apparent that there even is encrypted data
204 on the device, as an overwrite with crypto-grade randomness (e.g.
205 from /dev/urandom) looks exactly the same on disk.
207 Side-note: That has limited value against the authorities. In
208 civilized countries, they cannot force you to give up a crypto-key
209 anyways. In the US, the UK and dictatorships around the world,
210 they can force you to give up the keys (using imprisonment or worse
211 to pressure you), and in the worst case, they only need a
212 nebulous "suspicion" about the presence of encrypted data. My
213 advice is to either be ready to give up the keys or to not have
214 encrypted data when traveling to those countries, especially when
215 crossing the borders.
217 Disadvantages are that you do not have all the nice features that
218 the LUKS metadata offers, like multiple passphrases that can be
219 changed, the cipher being stored in the metadata, anti-forensic
220 properties like key-slot diffusion and salts, etc..
222 LUKS format uses a metadata header and 8 key-slot areas that are
223 being placed at the beginning of the disk, see below under "What
224 does the LUKS on-disk format looks like?". The passphrases are used
225 to decrypt a single master key that is stored in the anti-forensic
228 Advantages are a higher usability, automatic configuration of
229 non-default crypto parameters, defenses against low-entropy
230 passphrases like salting and iterated PBKDF2 passphrase hashing,
231 the ability to change passphrases, and others.
233 Disadvantages are that it is readily obvious there is encrypted
234 data on disk (but see side note above) and that damage to the
235 header or key-slots usually results in permanent data-loss. See
236 below under "6. Backup and Data Recovery" on how to reduce that
237 risk. Also the sector numbers get shifted by the length of the
238 header and key-slots and there is a loss of that size in capacity
239 (1MB+4096B for defaults and 2MB for the most commonly used
240 non-default XTS mode).
243 * 2.2 Can I encrypt an already existing, non-empty partition to use
246 There is no converter, and it is not really needed. The way to do
247 this is to make a backup of the device in question, securely wipe
248 the device (as LUKS device initialization does not clear away old
249 data), do a luksFormat, optionally overwrite the encrypted device,
250 create a new filesystem and restore your backup on the now
251 encrypted device. Also refer to sections "Security Aspects" and
252 "Backup and Data Recovery".
254 For backup, plain GNU tar works well and backs up anything likely
255 to be in a filesystem.
258 * 2.3 How do I use LUKS with a loop-device?
260 This can be very handy for experiments. Setup is just the same as
261 with any block device. If you want, for example, to use a 100MiB
262 file as LUKS container, do something like this:
264 head -c 100M /dev/zero > luksfile # create empty file
265 losetup /dev/loop0 luksfile # map luksfile to /dev/loop0
266 cryptsetup luksFormat /dev/loop0 # create LUKS on loop device
268 Afterwards just use /dev/loop0 as a you would use a LUKS partition.
269 To unmap the file when done, use "losetup -d /dev/loop0".
272 * 2.4 When I add a new key-slot to LUKS, it asks for a passphrase but
273 then complains about there not being a key-slot with that
276 That is as intended. You are asked a passphrase of an existing
277 key-slot first, before you can enter the passphrase for the new
278 key-slot. Otherwise you could break the encryption by just adding a
279 new key-slot. This way, you have to know the passphrase of one of
280 the already configured key-slots in order to be able to configure a
284 * 2.5 Encryption on top of RAID or the other way round?
286 Unless you have special needs, place encryption between RAID and
287 filesystem, i.e. encryption on top of RAID. You can do it the other
288 way round, but you have to be aware that you then need to give the
289 passphrase for each individual disk and RAID autodetection will
290 not work anymore. Therefore it is better to encrypt the RAID
291 device, e.g. /dev/dm0 .
294 * 2.6 How do I read a dm-crypt key from file?
296 Note that the file will still be hashed first, just like keyboard
297 input. Use the --key-file option, like this:
299 cryptsetup create --key-file keyfile e1 /dev/loop0
302 * 2.7 How do I read a LUKS slot key from file?
304 What you really do here is to read a passphrase from file, just as
305 you would with manual entry of a passphrase for a key-slot. You can
306 add a new passphrase to a free key-slot, set the passphrase of an
307 specific key-slot or put an already configured passphrase into a
308 file. In the last case make sure no trailing newline (0x0a) is
309 contained in the key file, or the passphrase will not work because
310 the whole file is used as input.
312 To add a new passphrase to a free key slot from file, use something
315 cryptsetup luksAddKey /dev/loop0 keyfile
317 To add a new passphrase to a specific key-slot, use something like
320 cryptsetup luksAddKey --key-slot 7 /dev/loop0 keyfile
322 To supply a key from file to any LUKS command, use the --key-file
323 option, e.g. like this:
325 cryptsetup luksOpen --key-file keyfile /dev/loop0 e1
328 * 2.8 How do I read the LUKS master key from file?
330 The question you should ask yourself first is why you would want to
331 do this. The only legitimate reason I can think of is if you want
332 to have two LUKS devices with the same master key. Even then, I
333 think it would be preferable to just use key-slots with the same
334 passphrase, or to use plain dm-crypt instead. If you really have a
335 good reason, please tell me. If I am convinced, I will add how to
339 * 2.9 What are the security requirements for a key read from file?
341 A file-stored key or passphrase has the same security requirements
342 as one entered interactively, however you can use random bytes and
343 thereby use bytes you cannot type on the keyboard. You can use any
344 file you like as key file, for example a plain text file with a
345 human readable passphrase. To generate a file with random bytes,
346 use something like this:
348 head -c 256 /dev/random > keyfile
351 * 2.10 If I map a journaled file system using dm-crypt/LUKS, does it
352 still provide its usual transactional guarantees?
354 Yes, it does, unless a very old kernel is used. The required flags
355 come from the filesystem layer and are processed and passed onwards
356 by dm-crypt. A bit more information on the process by which
357 transactional guarantees are implemented can be found here:
359 http://lwn.net/Articles/400541/
361 Please note that these "guarantees" are weaker than they appear to
362 be. One problem is that quite a few disks lie to the OS about
363 having flushed their buffers. Some other things can go wrong as
364 well. The filesystem developers are aware of these problems and
365 typically can make it work anyways. That said, dm-crypt/LUKS will
366 not make things worse.
368 One specific problem you can run into though is that you can get
369 short freezes and other slowdowns due to the encryption layer.
370 Encryption takes time and forced flushes will block for that time.
371 For example, I did run into frequent small freezes (1-2 sec) when
372 putting a vmware image on ext3 over dm-crypt. When I went back to
373 ext2, the problem went away. This seems to have gotten better with
374 kernel 2.6.36 and the reworking of filesystem flush locking
375 mechanism (less blocking of CPU activity during flushes). It
376 should improve further and eventually the problem should go away.
379 * 2.11 Can I use LUKS or cryptsetup with a more secure (external)
380 medium for key storage, e.g. TPM or a smartcard?
382 Yes, see the answers on using a file-supplied key. You do have to
383 write the glue-logic yourself though. Basically you can have
384 cryptsetup read the key from STDIN and write it there with your
385 own tool that in turn gets the key from the more secure key
389 * 2.12 Can I resize a dm-crypt or LUKS partition?
391 Yes, you can, as neither dm-crypt nor LUKS stores partition size.
392 Whether you should is a different question. Personally I recommend
393 backup, recreation of the encrypted partition with new size,
394 recreation of the filesystem and restore. This gets around the
395 tricky business of resizing the filesystem. Resizing a dm-crypt or
396 LUKS container does not resize the filesystem in it. The backup is
397 really non-optional here, as a lot can go wrong, resulting in
398 partial or complete data loss. Using something like gparted to
399 resize an encrypted partition is slow, but typically works. This
400 will not change the size of the filesystem hidden under the
403 You also need to be aware of size-based limitations. The one
404 currently relevant is that aes-xts-plain should not be used for
405 encrypted container sizes larger than 2TiB. Use aes-xts-plain64
412 * 3.1 My dm-crypt/LUKS mapping does not work! What general steps are
413 there to investigate the problem?
415 If you get a specific error message, investigate what it claims
416 first. If not, you may want to check the following things.
418 - Check that "/dev", including "/dev/mapper/control" is there. If it
419 is missing, you may have a problem with the "/dev" tree itself or
420 you may have broken udev rules.
422 - Check that you have the device mapper and the crypt target in your
423 kernel. The output of "dmsetup targets" should list a "crypt"
424 target. If it is not there or the command fails, add device mapper
425 and crypt-target to the kernel.
427 - Check that the hash-functions and ciphers you want to use are in
428 the kernel. The output of "cat /proc/crypto" needs to list them.
431 * 3.2 My dm-crypt mapping suddenly stopped when upgrading cryptsetup.
433 The default cipher, hash or mode may have changed (the mode changed
434 from 1.0.x to 1.1.x). See under "Issues With Specific Versions of
438 * 3.3 When I call cryptsetup from cron/CGI, I get errors about
441 If you get errors about unknown parameters or the like that are not
442 present when cryptsetup is called from the shell, make sure you
443 have no older version of cryptsetup on your system that then gets
444 called by cron/CGI. For example some distributions install
445 cryptsetup into /usr/sbin, while a manual install could go to
446 /usr/local/sbin. As a debugging aid, call "cryptsetup --version"
447 from cron/CGI or the non-shell mechanism to be sure the right
451 * 3.4 Unlocking a LUKS device takes very long. Why?
453 The iteration time for a key-slot (see Section 5 for an explanation
454 what iteration does) is calculated when setting a passphrase. By
455 default it is 1 second on the machine where the passphrase is set.
456 If you set a passphrase on a fast machine and then unlock it on a
457 slow machine, the unlocking time can be much longer. Also take into
458 account that up to 8 key-slots have to be tried in order to find the
461 If this is problem, you can add another key-slot using the slow
462 machine with the same passphrase and then remove the old key-slot.
463 The new key-slot will have an iteration count adjusted to 1 second
464 on the slow machine. Use luksKeyAdd and then luksKillSlot or
467 However, this operation will not change volume key iteration count
468 (MK iterations in output of "cryptsetup luksDump"). In order to
469 change that, you will have to backup the data in the LUKS
470 container (i.e. your encrypted data), luksFormat on the slow
471 machine and restore the data. Note that in the original LUKS
472 specification this value was fixed to 10, but it is now derived
473 from the PBKDF2 benchmark as well and set to iterations in 0.125
474 sec or 1000, whichever is larger. Also note that MK iterations
475 are not very security relevant. But as each key-slot already takes
476 1 second, spending the additional 0.125 seconds really does not
480 * 3.5 "blkid" sees a LUKS UUID and an ext2/swap UUID on the same
481 device. What is wrong?
483 Some old versions of cryptsetup have a bug where the header does
484 not get completely wiped during LUKS format and an older ext2/swap
485 signature remains on the device. This confuses blkid.
487 Fix: Wipe the unused header areas by doing a backup and restore of
488 the header with cryptsetup 1.1.x:
490 cryptsetup luksHeaderBackup --header-backup-file <file> <device>
491 cryptsetup luksHeaderRestore --header-backup-file <file> <device>
494 * 3.6 cryptsetup segfaults on Gentoo amd64 hardened ...
496 There seems to be some interference between the hardening and and
497 the way cryptsetup benchmarks PBKDF2. The solution to this is
498 currently not quite clear for an encrypted root filesystem. For
499 other uses, you can apparently specify USE="dynamic" as compile
500 flag, see http://bugs.gentoo.org/show_bug.cgi?id=283470
506 * 4.1 I get the error "LUKS keyslot x is invalid." What does that
509 This means that the given keyslot has an offset that points
510 outside the valid keyslot area. Typically, the reason is a
511 corrupted LUKS header because something was written to the start of
512 the device the LUKS container is on. Refer to Section "Backup and
513 Data Recovery" and ask on the mailing list if you have trouble
514 diagnosing and (if still possible) repairing this.
517 * 4.2 Can a bad RAM module cause problems?
519 LUKS and dm-crypt can give the RAM quite a workout, especially when
520 combined with software RAID. In particular the combination RAID5 +
521 LUKS + XFS seems to uncover RAM problems that never caused obvious
522 problems before. Symptoms vary, but often the problem manifest
523 itself when copying large amounts of data, typically several times
524 larger than your main memory.
526 Side note: One thing you should always do on large data
527 copy/movements is to run a verify, for example with the "-d"
528 option of "tar" or by doing a set of MD5 checksums on the source
531 find . -type f -exec md5sum \{\} \; > checksum-file
533 and then a "md5sum -c checksum-file" on the other side. If you get
534 mismatches here, RAM is the primary suspect. A lesser suspect is
535 an overclocked CPU. I have found countless hardware problems in
536 verify runs after copying or making backups. Bit errors are much
537 more common than most people think.
539 Some RAM issues are even worse and corrupt structures in one of the
540 layers. This typically results in lockups, CPU state dumps in the
541 system logs, kernel panic or other things. It is quite possible to
542 have the problem with an encrypted device, but not with an
543 otherwise the same unencrypted device. The reason for that is that
544 encryption has an error amplification property: You flip one bit
545 in an encrypted data block, and the decrypted version has half of
546 its bits flipped. This is an important security property for modern
547 ciphers. With the usual modes in cryptsetup (CBC, ESSIV, XTS), you
548 get up to a completely changed 512 byte block per bit error. A
549 corrupt block causes a lot more havoc than the occasionally
550 flipped single bit and can result in various obscure errors.
552 Note, that a verify run on copying between encrypted or
553 unencrypted devices will reliably detect corruption, even when the
554 copying itself did not report any problems. If you find defect
555 RAM, assume all backups and copied data to be suspect, unless you
559 * 4.3 How do I test RAM?
561 First you should know that overclocking often makes memory
562 problems worse. So if you overclock (which I strongly recommend
563 against in a system holding data that has some worth), run the
564 tests with the overclocking active.
566 There are two good options. One is Memtest86+ and the other is
567 "memtester" by Charles Cazabon. Memtest86+ requires a reboot and
568 then takes over the machine, while memtester runs from a
569 root-shell. Both use different testing methods and I have found
570 problems fast with each one that the other needed long to find. I
571 recommend running the following procedure until the first error is
574 - Run Memtest86+ for one cycle
576 - Run memtester for one cycle (shut down as many other applications
579 - Run Memtest86+ for 24h or more
581 - Run memtester for 24h or more
583 If all that does not produce error messages, your RAM may be sound,
584 but I have had one weak bit that Memtest86+ needed around 60 hours
585 to find. If you can reproduce the original problem reliably, a good
586 additional test may be to remove half of the RAM (if you have more
587 than one module) and try whether the problem is still there and if
588 so, try with the other half. If you just have one module, get a
589 different one and try with that. If you do overclocking, reduce
590 the settings to the most conservative ones available and try with
597 * 5.1 Is LUKS insecure? Everybody can see I have encrypted data!
599 In practice it does not really matter. In most civilized countries
600 you can just refuse to hand over the keys, no harm done. In some
601 countries they can force you to hand over the keys, if they suspect
602 encryption. However the suspicion is enough, they do not have to
603 prove anything. This is for practical reasons, as even the presence
604 of a header (like the LUKS header) is not enough to prove that you
605 have any keys. It might have been an experiment, for example. Or it
606 was used as encrypted swap with a key from /dev/random. So they
607 make you prove you do not have encrypted data. Of course that is
608 just as impossible as the other way round.
610 This means that if you have a large set of random-looking data,
611 they can already lock you up. Hidden containers (encryption hidden
612 within encryption), as possible with Truecrypt, do not help
613 either. They will just assume the hidden container is there and
614 unless you hand over the key, you will stay locked up. Don't have
615 a hidden container? Though luck. Anybody could claim that.
617 Still, if you are concerned about the LUKS header, use plain
618 dm-crypt with a good passphrase. See also Section 2, "What is the
619 difference between "plain" and LUKS format?"
622 * 5.2 Should I initialize (overwrite) a new LUKS/dm-crypt partition?
624 If you just create a filesystem on it, most of the old data will
625 still be there. If the old data is sensitive, you should overwrite
626 it before encrypting. In any case, not initializing will leave the
627 old data there until the specific sector gets written. That may
628 enable an attacker to determine how much and where on the
629 partition data was written. If you think this is a risk, you can
630 prevent this by overwriting the encrypted device (here assumed to
631 be named "e1") with zeros like this:
633 dd_rescue -w /dev/zero /dev/mapper/e1
635 or alternatively with one of the following more standard commands:
637 cat /dev/zero > /dev/mapper/e1
638 dd if=/dev/zero of=/dev/mapper/e1
641 * 5.3 How do I securely erase a LUKS (or other) partition?
643 For LUKS, if you are in a desperate hurry, overwrite the LUKS
644 header and key-slot area. This means overwriting the first
645 (keyslots x stripes x keysize) + offset bytes. For the default
646 parameters, this is the 1'052'672 bytes, i.e. 1MiB + 4096 of the
647 LUKS partition. For 512 bit key length (e.g. for aes-xts-plain with
648 512 bit key) this is 2MiB. (The different offset stems from
649 differences in the sector alignment of the key-slots.) If in doubt,
650 just be generous and overwrite the first 10MB or so, it will likely
651 still be fast enough. A single overwrite with zeros should be
652 enough. If you anticipate being in a desperate hurry, prepare the
653 command beforehand. Example with /dev/sde1 as the LUKS partition
654 and default parameters:
656 head -c 1052672 /dev/zero > /dev/sde1; sync
658 A LUKS header backup or full backup will still grant access to
659 most or all data, so make sure that an attacker does not have
660 access to backups or destroy them as well.
662 If you have time, overwrite the whole LUKS partition with a single
663 pass of zeros. This is enough for current HDDs. For SSDs or FLASH
664 (USB sticks) you may want to overwrite the whole drive several
665 times to be sure data is not retained by wear leveling. This is
666 possibly still insecure as SSD technology is not fully understood
667 in this regard. Still, due to the anti-forensic properties of the
668 LUKS key-slots, a single overwrite of an SSD or FLASH drive could
669 be enough. If in doubt, use physical destruction in addition. Here
670 is a link to some current research results on erasing SSDs and
672 http://www.usenix.org/events/fast11/tech/full_papers/Wei.pdf
674 Keep in mind to also erase all backups.
676 Example for a zero-overwrite erase of partition sde1 done with
679 dd_rescue -w /dev/zero /dev/sde1
682 * 5.4 How do I securely erase a backup of a LUKS partition or header?
684 That depends on the medium it is stored on. For HDD and SSD, use
685 overwrite with zeros. For an SSD or FLASH drive (USB stick), you
686 may want to overwrite the complete SSD several times and use
687 physical destruction in addition, see last item. For re-writable
688 CD/DVD, a single overwrite should also be enough, due to the
689 anti-forensic properties of the LUKS keyslots. For write-once
690 media, use physical destruction. For low security requirements,
691 just cut the CD/DVD into several parts. For high security needs,
692 shred or burn the medium. If your backup is on magnetic tape, I
693 advise physical destruction by shredding or burning, after
694 overwriting . The problem with magnetic tape is that it has a
695 higher dynamic range than HDDs and older data may well be
696 recoverable after overwrites. Also write-head alignment issues can
697 lead to data not actually being deleted at all during overwrites.
700 * 5.5 What about backup? Does it compromise security?
702 That depends. See item 6.7.
705 * 5.6 Why is all my data permanently gone if I overwrite the LUKS
708 Overwriting the LUKS header in part or in full is the most common
709 reason why access to LUKS containers is lost permanently.
710 Overwriting can be done in a number of fashions, like creating a
711 new filesystem on the raw LUKS partition, making the raw partition
712 part of a raid array and just writing to the raw partition.
714 The LUKS header contains a 256 bit "salt" value and without that no
715 decryption is possible. While the salt is not secret, it is
716 key-grade material and cannot be reconstructed. This is a
717 cryptographically strong "cannot". From observations on the
718 cryptsetup mailing-list, people typically go though the usual
719 stages of grief (Denial, Anger, Bargaining, Depression, Acceptance)
720 when this happens to them. Observed times vary between 1 day and 2
721 weeks to complete the cycle. Seeking help on the mailing-list is
722 fine. Even if we usually cannot help with getting back your data,
723 most people found the feedback comforting.
725 If your header does not contain an intact salt, best go directly
726 to the last stage ("Acceptance") and think about what to do now.
727 There is one exception that I know of: If your LUKS container is
728 still open, then it may be possible to extract the master key from
729 the running system. See Item "How do I recover the master key from
730 a mapped LUKS container?" in Section "Backup and Data Recovery".
733 * 5.7 What is a "salt"?
735 A salt is a random key-grade value added to the passphrase before
736 it is processed. It is not kept secret. The reason for using salts
737 is as follows: If an attacker wants to crack the password for a
738 single LUKS container, then every possible passphrase has to be
739 tried. Typically an attacker will not try every binary value, but
740 will try words and sentences from a dictionary.
742 If an attacker wants to attack several LUKS containers with the
743 same dictionary, then a different approach makes sense: Compute the
744 resulting slot-key for each dictionary element and store it on
745 disk. Then the test for each entry is just the slow unlocking with
746 the slot key (say 0.00001 sec) instead of calculating the slot-key
747 first (1 sec). For a single attack, this does not help. But if you
748 have more than one container to attack, this helps tremendously,
749 also because you can prepare your table before you even have the
750 container to attack! The calculation is also very simple to
751 parallelize. You could, for example, use the night-time unused CPU
752 power of your desktop PCs for this.
754 This is where the salt comes in. If the salt is combined with the
755 passphrase (in the simplest form, just appended to it), you
756 suddenly need a separate table for each salt value. With a
757 reasonably-sized salt value (256 bit, e.g.) this is quite
761 * 5.8 Is LUKS secure with a low-entropy (bad) passphrase?
763 Note: You should only use the 94 printable characters from 7 bit
764 ASCII code to prevent your passphrase from failing when the
765 character encoding changes, e.g. because of a system upgrade, see
766 also the note at the very start of this FAQ under "WARNINGS".
768 This needs a bit of theory. The quality of your passphrase is
769 directly related to its entropy (information theoretic, not
770 thermodynamic). The entropy says how many bits of "uncertainty" or
771 "randomness" are in you passphrase. In other words, that is how
772 difficult guessing the passphrase is.
774 Example: A random English sentence has about 1 bit of entropy per
775 character. A random lowercase (or uppercase) character has about
778 Now, if n is the number of bits of entropy in your passphrase and t
779 is the time it takes to process a passphrase in order to open the
780 LUKS container, then an attacker has to spend at maximum
782 attack_time_max = 2^n * t
784 time for a successful attack and on average half that. There is no
785 way getting around that relationship. However, there is one thing
786 that does help, namely increasing t, the time it takes to use a
787 passphrase, see next FAQ item.
789 Still, if you want good security, a high-entropy passphrase is the
790 only option. For example, a low-entropy passphrase can never be
791 considered secure against a TLA-level (Three Letter Agency level,
792 i.e. government-level) attacker, no matter what tricks are used in
793 the key-derivation function. Use at least 64 bits for secret stuff.
794 That is 64 characters of English text (but only if randomly chosen)
795 or a combination of 12 truly random letters and digits.
797 For passphrase generation, do not use lines from very well-known
798 texts (religious texts, Harry potter, etc.) as they are to easy to
799 guess. For example, the total Harry Potter has about 1'500'000
800 words (my estimation). Trying every 64 character sequence starting
801 and ending at a word boundary would take only something like 20
802 days on a single CPU and is entirely feasible. To put that into
803 perspective, using a number of Amazon EC2 High-CPU Extra Large
804 instances (each gives about 8 real cores), this test costs
805 currently about 50USD/EUR, but can be made to run arbitrarily fast.
807 On the other hand, choosing 1.5 lines from, say, the Wheel of Time
808 is in itself not more secure, but the book selection adds quite a
809 bit of entropy. (Now that I have mentioned it here, don't use tWoT
810 either!) If you add 2 or 3 typos or switch some words around, then
811 this is good passphrase material.
814 * 5.9 What is "iteration count" and why is decreasing it a bad idea?
816 Iteration count is the number of PBKDF2 iterations a passphrase is
817 put through before it is used to unlock a key-slot. Iterations are
818 done with the explicit purpose to increase the time that it takes
819 to unlock a key-slot. This provides some protection against use of
820 low-entropy passphrases.
822 The idea is that an attacker has to try all possible passphrases.
823 Even if the attacker knows the passphrase is low-entropy (see last
824 item), it is possible to make each individual try take longer. The
825 way to do this is to repeatedly hash the passphrase for a certain
826 time. The attacker then has to spend the same time (given the same
827 computing power) as the user per try. With LUKS, the default is 1
828 second of PBKDF2 hashing.
830 Example 1: Lets assume we have a really bad passphrase (e.g. a
831 girlfriends name) with 10 bits of entropy. With the same CPU, an
832 attacker would need to spend around 500 seconds on average to
833 break that passphrase. Without iteration, it would be more like
834 0.0001 seconds on a modern CPU.
836 Example 2: The user did a bit better and has 32 chars of English
837 text. That would be about 32 bits of entropy. With 1 second
838 iteration, that means an attacker on the same CPU needs around 136
839 years. That is pretty impressive for such a weak passphrase.
840 Without the iterations, it would be more like 50 days on a modern
841 CPU, and possibly far less.
843 In addition, the attacker can both parallelize and use special
844 hardware like GPUs or FPGAs to speed up the attack. The attack can
845 also happen quite some time after the luksFormat operation and CPUs
846 can have become faster and cheaper. For that reason you want a
847 bit of extra security. Anyways, in Example 1 your are screwed.
848 In example 2, not necessarily. Even if the attack is faster, it
849 still has a certain cost associated with it, say 10000 EUR/USD
850 with iteration and 1 EUR/USD without iteration. The first can be
851 prohibitively expensive, while the second is something you try
852 even without solid proof that the decryption will yield something
855 The numbers above are mostly made up, but show the idea. Of course
856 the best thing is to have a high-entropy passphrase.
858 Would a 100 sec iteration time be even better? Yes and no.
859 Cryptographically it would be a lot better, namely 100 times better.
860 However, usability is a very important factor for security
861 technology and one that gets overlooked surprisingly often. For
862 LUKS, if you have to wait 2 minutes to unlock the LUKS container,
863 most people will not bother and use less secure storage instead. It
864 is better to have less protection against low-entropy passphrases
865 and people actually use LUKS, than having them do without
866 encryption altogether.
868 Now, what about decreasing the iteration time? This is generally a
869 very bad idea, unless you know and can enforce that the users only
870 use high-entropy passphrases. If you decrease the iteration time
871 without ensuring that, then you put your users at increased risk,
872 and considering how rarely LUKS containers are unlocked in a
873 typical work-flow, you do so without a good reason. Don't do it.
874 The iteration time is already low enough that users with entropy
875 low passphrases are vulnerable. Lowering it even further increases
876 this danger significantly.
879 * 5.10 Some people say PBKDF2 is insecure?
881 There is some discussion that a hash-function should have a "large
882 memory" property, i.e. that it should require a lot of memory to be
883 computed. This serves to prevent attacks using special programmable
884 circuits, like FPGAs, and attacks using graphics cards. PBKDF2
885 does not need a lot of memory and is vulnerable to these attacks.
886 However, the publication usually referred in these discussions is
887 not very convincing in proving that the presented hash really is
888 "large memory" (that may change, email the FAQ maintainer when it
889 does) and it is of limited usefulness anyways. Attackers that use
890 clusters of normal PCs will not be affected at all by a "large
891 memory" property. For example the US Secret Service is known to
892 use the off-hour time of all the office PCs of the Treasury for
893 password breaking. The Treasury has about 110'000 employees.
894 Assuming every one has an office PC, that is significant computing
895 power, all of it with plenty of memory for computing "large
896 memory" hashes. Bot-net operators also have all the memory they
897 want. The only protection against a resourceful attacker is a
898 high-entropy passphrase, see items 5.8 and 5.9.
901 * 5.11 What about iteration count with plain dm-crypt?
903 Simple: There is none. There is also no salting. If you use plain
904 dm-crypt, the only way to be secure is to use a high entropy
905 passphrase. If in doubt, use LUKS instead.
908 * 5.12 Is LUKS with default parameters less secure on a slow CPU?
910 Unfortunately, yes. However the only aspect affected is the
911 protection for low-entropy passphrase or master-key. All other
912 security aspects are independent of CPU speed.
914 The master key is less critical, as you really have to work at it
915 to give it low entropy. One possibility is to supply the master key
916 yourself. If that key is low-entropy, then you get what you
917 deserve. The other known possibility is to use /dev/urandom for
918 key generation in an entropy-starved situation (e.g. automatic
919 installation on an embedded device without network and other entropy
922 For the passphrase, don't use a low-entropy passphrase. If your
923 passphrase is good, then a slow CPU will not matter. If you insist
924 on a low-entropy passphrase on a slow CPU, use something like
925 "--iter-time=10" or higher and wait a long time on each LUKS unlock
926 and pray that the attacker does not find out in which way exactly
927 your passphrase is low entropy. This also applies to low-entropy
928 passphrases on fast CPUs. Technology can do only so much to
929 compensate for problems in front of the keyboard.
932 * 5.13 Why was the default aes-cbc-plain replaced with aes-cbc-essiv?
934 Note: This item applies both to plain dm-crypt and to LUKS
936 The problem is that cbc-plain has a fingerprint vulnerability, where
937 a specially crafted file placed into the crypto-container can be
938 recognized from the outside. The issue here is that for cbc-plain
939 the initialization vector (IV) is the sector number. The IV gets
940 XORed to the first data chunk of the sector to be encrypted. If you
941 make sure that the first data block to be stored in a sector
942 contains the sector number as well, the first data block to be
943 encrypted is all zeros and always encrypted to the same ciphertext.
944 This also works if the first data chunk just has a constant XOR
945 with the sector number. By having several shifted patterns you can
946 take care of the case of a non-power-of-two start sector number of
949 This mechanism allows you to create a pattern of sectors that have
950 the same first ciphertext block and signal one bit per sector to the
951 outside, allowing you to e.g. mark media files that way for
952 recognition without decryption. For large files this is a
953 practical attack. For small ones, you do not have enough blocks to
954 signal and take care of different file starting offsets.
956 In order to prevent this attack, the default was changed to
957 cbc-essiv. ESSIV uses a keyed hash of the sector number, with the
958 encryption key as key. This makes the IV unpredictable without
959 knowing the encryption key and the watermarking attack fails.
962 * 5.14 Are there any problems with "plain" IV? What is "plain64"?
964 First, "plain" and "plain64" are both not secure to use with CBC,
965 see previous FAQ item.
967 However there are modes, like XTS, that are secure with "plain" IV.
968 The next limit is that "plain" is 64 bit, with the upper 32 bit set
969 to zero. This means that on volumes larger than 2TiB, the IV
970 repeats, creating a vulnerability that potentially leaks some
971 data. To avoid this, use "plain64", which uses the full sector
972 number up to 64 bit. Note that "plain64" requires a kernel >=
973 2.6.33. Also note that "plain64" is backwards compatible for
974 volume sizes <= 2TiB, but not for those > 2TiB. Finally, "plain64"
975 does not cause any performance penalty compared to "plain".
978 * 5.15 What about XTS mode?
980 XTS mode is potentially even more secure than cbc-essiv (but only if
981 cbc-essiv is insecure in your scenario). It is a NIST standard and
982 used, e.g. in Truecrypt. At the moment, if you want to use it, you
983 have to specify it manually as "aes-xts-plain", i.e.
985 cryptsetup -c aes-xts-plain luksFormat <device>
987 For volumes >2TiB and kernels >= 2.6.33 use "plain64" (see FAQ
988 item on "plain" and "plain64"):
990 cryptsetup -c aes-xts-plain64 luksFormat <device>
992 There is a potential security issue with XTS mode and large blocks.
993 LUKS and dm-crypt always use 512B blocks and the issue does not
997 * 5.16 Is LUKS FIPS-140-2 certified?
999 No. But that is more a problem of FIPS-140-2 than of LUKS. From a
1000 technical point-of-view, LUKS with the right parameters would be
1001 FIPS-140-2 compliant, but in order to make it certified, somebody
1002 has to pay real money for that. And then, whenever cryptsetup is
1003 changed or extended, the certification lapses and has to be
1006 From the aspect of actual security, LUKS with default parameters
1007 should be as good as most things that are FIPS-140-2 certified,
1008 although you may want to make sure to use /dev/random (by
1009 specifying --use-random on luksFormat) as randomness source for
1010 the master key to avoid being potentially insecure in an
1011 entropy-starved situation.
1014 * 5.16 What about Plausible Deniability?
1016 First let me attempt a definition for the case of encrypted
1017 filesystems: Plausible deniability is when you hide encrypted data
1018 inside an encrypted container and it is not possible to prove it is
1019 there. The idea is compelling and on first glance it seems
1020 possible to do it. And from a cryptographic point of view, it
1021 actually is possible.
1023 So, does it work in practice? No, unfortunately. The reasoning used
1024 by its proponents is fundamentally flawed in several ways and the
1025 cryptographic properties fail fatally when colliding with the real
1028 First, why should "I do not have a hidden partition" be any more
1029 plausible than "I forgot my crypto key" or "I wiped that partition
1030 with random data, nothing in there"? I do not see any reason.
1032 Second, there are two types of situations: Either they cannot force
1033 you to give them the key (then you simply do not) or the can. In
1034 the second case, they can always do bad things to you, because they
1035 cannot prove that you have the key in the first place! This means
1036 they do not have to prove you have the key, or that this random
1037 looking data on your disk is actually encrypted data. So the
1038 situation will allow them to waterboard/lock-up/deport you
1039 anyways, regardless of how "plausible" your deniability is. Do not
1040 have a hidden partition you could show to them, but there are
1041 indications you may? Too bad for you. Unfortunately "plausible
1042 deniability" also means you cannot prove there is no hidden data.
1044 Third, hidden partitions are not that hidden. There are basically
1045 just two possibilities: a) Make a large crypto container, but put a
1046 smaller filesystem in there and put the hidden partition into the
1047 free space. Unfortunately this is glaringly obvious and can be
1048 detected in an automated fashion. This means that the initial
1049 suspicion to put you under duress in order to make you reveal you
1050 hidden data is given. b) Make a filesystem that spans the whole
1051 encrypted partition, and put the hidden partition into space not
1052 currently used by that filesystem. Unfortunately that is also
1053 glaringly obvious, as you then cannot write to the filesystem
1054 without a high risk of destroying data in the hidden container.
1055 Have not written anything to the encrypted filesystem in a while?
1056 Too bad, they have the suspicion they need to do unpleasant things
1059 To be fair, if you prepare option b) carefully and directly before
1060 going into danger, it may work. But then, the mere presence of
1061 encrypted data may already be enough to get you into trouble in
1062 those places were they can demand encryption keys.
1064 Here is an additional reference for some problems with plausible
1065 deniability: http://www.schneier.com/paper-truecrypt-dfs.pdf I
1066 strongly suggest you read it.
1068 So, no, I will not provide any instructions on how to do it with
1069 plain dm-crypt or LUKS. If you insist on shooting yourself in the
1070 foot, you can figure out how to do it yourself.
1073 * 5.17 What about SSDs or Flash Drives?
1075 The problem is that you cannot reliably erase parts of these
1076 devices, mainly due to wear-leveling and possibly defect
1079 Basically, when overwriting a sector (of 512B), what the device
1080 does is to move an internal sector (may be 128kB or even larger) to
1081 some pool of discarded, not-yet erased unused sectors, take a
1082 fresh empty sector from the empty-sector pool and copy the old
1083 sector over with the changes to the small part you wrote. This is
1084 done in some fashion so that larger writes do not cause a lot of
1085 small internal updates.
1087 The thing is that the mappings between outside-adressable sectors
1088 and inside sectors is arbitrary (and the vendors are not talking).
1089 Also the discarded sectors are not necessarily erased immediately.
1090 They may linger a long time.
1092 For plain dm-crypt, the consequences are that older encrypted data
1093 may be lying around in some internal pools of the device. Thus may
1094 or may not be a problem and depends on the application. Remember
1095 the same can happen with a filesystem if consecutive writes to the
1096 same area of a file can go to different sectors.
1098 However, for LUKS, the worst case is that key-slots and LUKS
1099 header may end up in these internal pools. This means that password
1100 management functionality is compromised (the old passwords may
1101 still be around, potentially for a very long time) and that fast
1102 erase by overwriting the header and key-slot area is insecure.
1104 Also keep in mind that the discarded/used pool may be large. For
1105 example, a 240GB SSD has about 16GB of spare area in the chips that
1106 it is free to do with as it likes. You would need to make each
1107 individual key-slot larger than that to allow reliable overwriting.
1108 And that assumes the disk thinks all other space is in use.
1109 Reading the internal pools using forensic tools is not that hard,
1110 but may involve some soldering.
1114 If you trust the device vendor (you probably should not...) you can
1115 try an ATA "secure erase" command for SSDs. That does not work for
1116 USB keys though. And if it finishes after a few seconds, it was
1117 possibly faked by the SSD.
1119 If you can do without password management and are fine with doing
1120 physical destruction for permenently deleting data (allways after
1121 one or several full overwrites!), you can use plain dm-crypt or
1124 If you want or need the original LUKS security features to work,
1125 you can use a detached LUKS header and put that on a conventional,
1126 magnetic disk. That leaves potentially old encrypted data in the
1127 pools on the disk, but otherwise you get LUKS with the same
1128 security as on a magnetic disk.
1130 If you are concerned about your laptop being stolen, you are likely
1131 fine using LUKS on an SSD. An attacker would need to have access
1132 to an old passphrase (and the key-slot for this old passphrase
1133 would actually need to still be somewhere in the SSD) for your
1134 data to be at risk. So unless you pasted your old passphrase all
1135 over the Internet or the attacker has knowledge of it from some
1136 other source and does a targetted laptop theft to get at your
1137 data, you should be fine.
1140 6. Backup and Data Recovery
1143 * 6.1 Why do I need Backup?
1145 First, disks die. The rate for well-treated (!) disk is about 5%
1146 per year, which is high enough to worry about. There is some
1147 indication that this may be even worse for some SSDs. This applies
1148 both to LUKS and plain dm-crypt partitions.
1150 Second, for LUKS, if anything damages the LUKS header or the
1151 key-stripe area then decrypting the LUKS device can become
1152 impossible. This is a frequent occurrence. For example an
1153 accidental format as FAT or some software overwriting the first
1154 sector where it suspects a partition boot sector typically makes a
1155 LUKS partition permanently inaccessible. See more below on LUKS
1158 So, data-backup in some form is non-optional. For LUKS, you may
1159 also want to store a header backup in some secure location. This
1160 only needs an update if you change passphrases.
1163 * 6.2 How do I backup a LUKS header?
1165 While you could just copy the appropriate number of bytes from the
1166 start of the LUKS partition, the best way is to use command option
1167 "luksHeaderBackup" of cryptsetup. This protects also against
1168 errors when non-standard parameters have been used in LUKS
1169 partition creation. Example:
1172 cryptsetup luksHeaderBackup --header-backup-file <file> <device>
1174 To restore, use the inverse command, i.e.
1176 cryptsetup luksHeaderRestore --header-backup-file <file> <device>
1179 * 6.3 How do I test a LUKS header?
1183 cryptsetup -v isLuks <device>
1185 on the device. Without the "-v" it just signals its result via
1186 exit-status. You can also use the more general test
1190 which will also detect other types and give some more info. Omit
1191 "-p" for old versions of blkid that do not support it.
1194 * 6.4 How do I backup a LUKS or dm-crypt partition?
1196 There are two options, a sector-image and a plain file or
1197 filesystem backup of the contents of the partition. The sector
1198 image is already encrypted, but cannot be compressed and contains
1199 all empty space. The filesystem backup can be compressed, can
1200 contain only part of the encrypted device, but needs to be
1201 encrypted separately if so desired.
1203 A sector-image will contain the whole partition in encrypted form,
1204 for LUKS the LUKS header, the keys-slots and the data area. It can
1205 be done under Linux e.g. with dd_rescue (for a direct image copy)
1206 and with "cat" or "dd". Example:
1208 cat /dev/sda10 > sda10.img
1209 dd_rescue /dev/sda10 sda10.img
1211 You can also use any other backup software that is capable of making
1212 a sector image of a partition. Note that compression is
1213 ineffective for encrypted data, hence it does not make sense to
1216 For a filesystem backup, you decrypt and mount the encrypted
1217 partition and back it up as you would a normal filesystem. In this
1218 case the backup is not encrypted, unless your encryption method
1219 does that. For example you can encrypt a backup with "tar" as
1222 tar cjf - <path> | gpg --cipher-algo AES -c - > backup.tbz2.gpg
1224 And verify the backup like this if you are at "path":
1226 cat backup.tbz2.gpg | gpg - | tar djf -
1228 Note: Always verify backups, especially encrypted ones.
1230 In both cases GnuPG will ask you interactively for your symmetric
1231 key. The verify will only output errors. Use "tar dvjf -" to get
1232 all comparison results. To make sure no data is written to disk
1233 unencrypted, turn off swap if it is not encrypted before doing the
1236 You can of course use different or no compression and you can use
1237 an asymmetric key if you have one and have a backup of the secret
1238 key that belongs to it.
1240 A second option for a filesystem-level backup that can be used when
1241 the backup is also on local disk (e.g. an external USB drive) is
1242 to use a LUKS container there and copy the files to be backed up
1243 between both mounted containers. Also see next item.
1246 * 6.5 Do I need a backup of the full partition? Would the header and
1247 key-slots not be enough?
1249 Backup protects you against two things: Disk loss or corruption
1250 and user error. By far the most questions on the dm-crypt mailing
1251 list about how to recover a damaged LUKS partition are related
1252 to user error. For example, if you create a new filesystem on a
1253 LUKS partition, chances are good that all data is lost
1256 For this case, a header+key-slot backup would often be enough. But
1257 keep in mind that a well-treated (!) HDD has roughly a failure
1258 risk of 5% per year. It is highly advisable to have a complete
1259 backup to protect against this case.
1262 * *6.6 What do I need to backup if I use "decrypt_derived"?
1264 This is a script in Debian, intended for mounting /tmp or swap with
1265 a key derived from the master key of an already decrypted device.
1266 If you use this for an device with data that should be persistent,
1267 you need to make sure you either do not lose access to that master
1268 key or have a backup of the data. If you derive from a LUKS
1269 device, a header backup of that device would cover backing up the
1270 master key. Keep in mind that this does not protect against disk
1273 Note: If you recreate the LUKS header of the device you derive from
1274 (using luksFormat), the master key changes even if you use the same
1275 passphrase(s) and you will not be able to decrypt the derived
1276 device with the new LUKS header.
1279 * 6.7 Does a backup compromise security?
1281 Depends on how you do it. However if you do not have one, you are
1282 going to eventually lose your encrypted data.
1284 There are risks introduced by backups. For example if you
1285 change/disable a key-slot in LUKS, a binary backup of the partition
1286 will still have the old key-slot. To deal with this, you have to
1287 be able to change the key-slot on the backup as well, securely
1288 erase the backup or do a filesystem-level backup instead of a binary
1291 If you use dm-crypt, backup is simpler: As there is no key
1292 management, the main risk is that you cannot wipe the backup when
1293 wiping the original. However wiping the original for dm-crypt
1294 should consist of forgetting the passphrase and that you can do
1295 without actual access to the backup.
1297 In both cases, there is an additional (usually small) risk with
1298 binary backups: An attacker can see how many sectors and which
1299 ones have been changed since the backup. To prevent this, use a
1300 filesystem level backup method that encrypts the whole backup in
1301 one go, e.g. as described above with tar and GnuPG.
1303 My personal advice is to use one USB disk (low value data) or
1304 three disks (high value data) in rotating order for backups, and
1305 either use independent LUKS partitions on them, or use encrypted
1306 backup with tar and GnuPG.
1308 If you do network-backup or tape-backup, I strongly recommend to
1309 go the filesystem backup path with independent encryption, as you
1310 typically cannot reliably delete data in these scenarios,
1311 especially in a cloud setting. (Well, you can burn the tape if it
1312 is under your control...)
1315 * 6.8 What happens if I overwrite the start of a LUKS partition or
1316 damage the LUKS header or key-slots?
1318 There are two critical components for decryption: The salt values
1319 in the header itself and the key-slots. If the salt values are
1320 overwritten or changed, nothing (in the cryptographically strong
1321 sense) can be done to access the data, unless there is a backup
1322 of the LUKS header. If a key-slot is damaged, the data can still
1323 be read with a different key-slot, if there is a remaining
1324 undamaged and used key-slot. Note that in order to make a key-slot
1325 unrecoverable in a cryptographically strong sense, changing about
1326 4-6 bits in random locations of its 128kiB size is quite enough.
1329 * 6.9 What happens if I (quick) format a LUKS partition?
1331 I have not tried the different ways to do this, but very likely you
1332 will have written a new boot-sector, which in turn overwrites the
1333 LUKS header, including the salts, making your data permanently
1334 irretrievable, unless you have a LUKS header backup. You may also
1335 damage the key-slots in part or in full. See also last item.
1338 * 6.10 How do I recover the master key from a mapped LUKS container?
1340 This is typically only needed if you managed to damage your LUKS
1341 header, but the container is still mapped, i.e. "luksOpen"ed. It
1342 also helps if you have a mapped container that you forgot or do not
1343 know a passphrase for (e.g. on a long running server.)
1345 WARNING: Things go wrong, do a full backup before trying this!
1347 WARNING: This exposes the master key of the LUKS container. Note
1348 that both ways to recreate a LUKS header with the old master key
1349 described below will write the master key to disk. Unless you are
1350 sure you have securely erased it afterwards, e.g. by writing it to
1351 an encrypted partition, RAM disk or by erasing the filesystem you
1352 wrote it to by a complete overwrite, you should change the master
1353 key afterwards. Changing the master key requires a full data
1354 backup, luksFormat and then restore of the backup.
1356 First, there is a script by Milan that automates the whole
1357 process, except generating a new LUKS header with the old master
1358 key (it prints the command for that though):
1360 http://code.google.com/p/cryptsetup/source/browse/misc/luks-header-from-active
1362 You can also do this manually. Here is how:
1364 - Get the master key from the device mapper. This is done by the
1365 following command. Substitute c5 for whatever you mapped to:
1367 # dmsetup table --target crypt --showkey /dev/mapper/c5
1369 0 200704 crypt aes-cbc-essiv:sha256
1370 a1704d9715f73a1bb4db581dcacadaf405e700d591e93e2eaade13ba653d0d09
1373 The result is actually one line, wrapped here for clarity. The long
1374 hex string is the master key.
1376 - Convert the master key to a binary file representation. You can
1377 do this manually, e.g. with hexedit. You can also use the tool
1378 "xxd" from vim like this:
1380 echo "a1704d9....53d0d09" | xxd -r -p > <master-key-file>
1382 - Do a luksFormat to create a new LUKS header.
1384 NOTE: If your header is intact and you just forgot the
1385 passphrase, you can just set a new passphrase, see next
1388 Unmap the device before you do that (luksClose). Then do
1390 cryptsetup luksFormat --master-key-file=<master-key-file> <luks device>
1392 Note that if the container was created with other than the default
1393 settings of the cryptsetup version you are using, you need to give
1394 additional parameters specifying the deviations. If in doubt, try
1395 the script by Milan. It does recover the other parameters as well.
1397 Side note: This is the way the decrypt_derived script gets at the
1398 master key. It just omits the conversion and hashes the master key
1401 - If the header is intact and you just forgot the passphrase, just
1402 set a new passphrase like this:
1404 cryptsetup luksAddKey --master-key-file=<master-key-file> <luks device>
1406 You may want to disable the old one afterwards.
1409 * 6.11 What does the on-disk structure of dm-crypt look like?
1411 There is none. dm-crypt takes a block device and gives encrypted
1412 access to each of its blocks with a key derived from the passphrase
1413 given. If you use a cipher different than the default, you have to
1414 specify that as a parameter to cryptsetup too. If you want to
1415 change the password, you basically have to create a second
1416 encrypted device with the new passphrase and copy your data over.
1417 On the plus side, if you accidentally overwrite any part of a
1418 dm-crypt device, the damage will be limited to the are you
1422 * 6.12 What does the on-disk structure of LUKS look like?
1424 A LUKS partition consists of a header, followed by 8 key-slot
1425 descriptors, followed by 8 key slots, followed by the encrypted
1428 Header and key-slot descriptors fill the first 592 bytes. The
1429 key-slot size depends on the creation parameters, namely on the
1430 number of anti-forensic stripes, key material offset and master
1433 With the default parameters, each key-slot is a bit less than
1434 128kiB in size. Due to sector alignment of the key-slot start,
1435 that means the key block 0 is at offset 0x1000-0x20400, key
1436 block 1 at offset 0x21000-0x40400, and key block 7 at offset
1437 0xc1000-0xe0400. The space to the next full sector address is
1438 padded with zeros. Never used key-slots are filled with what the
1439 disk originally contained there, a key-slot removed with
1440 "luksRemoveKey" or "luksKillSlot" gets filled with 0xff. Due to
1441 2MiB default alignment, start of the data area for cryptsetup 1.3
1442 and later is at 2MiB, i.e. at 0x200000. For older versions, it is
1443 at 0x101000, i.e. at 1'052'672 bytes, i.e. at 1MiB + 4096 bytes
1444 from the start of the partition. Incidentally, "luksHeaderBackup"
1445 for a LUKS container created with default parameters dumps exactly
1446 the first 2MiB (or 1'052'672 bytes for headers created with
1447 cryptsetup versions < 1.3) to file and "luksHeaderRestore" restores
1450 For non-default parameters, you have to figure out placement
1451 yourself. "luksDump" helps. See also next item. For the most common
1452 non-default settings, namely aes-xts-plain with 512 bit key, the
1453 offsets are: 1st keyslot 0x1000-0x3f800, 2nd keyslot
1454 0x40000-0x7e000, 3rd keyslot 0x7e000-0xbd800, ..., and start of
1455 bulk data at 0x200000.
1457 The exact specification of the format is here:
1458 http://code.google.com/p/cryptsetup/wiki/Specification
1461 * 6.13 What is the smallest possible LUKS container?
1463 Note: From cryptsetup 1.3 onwards, alignment is set to 1MB. With
1464 modern Linux partitioning tools that also align to 1MB, this will
1465 result in alignment to 2k sectors and typical Flash/SSD sectors,
1466 which is highly desirable for a number of reasons. Changing the
1467 alignment is not recommended.
1469 That said, with default parameters, the data area starts at
1470 exactly 2MB offset (at 0x101000 for cryptsetup versions before
1471 1.3). The smallest data area you can have is one sector of 512
1472 bytes. Data areas of 0 bytes can be created, but fail on mapping.
1474 While you cannot put a filesystem into something this small, it may
1475 still be used to contain, for example, key. Note that with current
1476 formatting tools, a partition for a container this size will be
1477 3MiB anyways. If you put the LUKS container into a file (via
1478 losetup and a loopback device), the file needs to be 2097664 bytes
1479 in size, i.e. 2MiB + 512B.
1481 There two ways to influence the start of the data area are key-size
1484 For alignment, you can go down to 1 on the parameter. This will
1485 still leave you with a data-area starting at 0x101000, i.e.
1486 1MiB+4096B (default parameters) as alignment will be rounded up to
1487 the next multiple of 8 (i.e. 4096 bytes) If in doubt, do a dry-run
1488 on a larger file and dump the LUKS header to get actual
1491 For key-size, you can use 128 bit (e.g. AES-128 with CBC), 256 bit
1492 (e.g. AES-256 with CBC) or 512 bit (e.g. AES-256 with XTS mode).
1493 You can do 64 bit (e.g. blowfish-64 with CBC), but anything below
1494 128 bit has to be considered insecure today.
1496 Example 1 - AES 128 bit with CBC:
1498 cryptsetup luksFormat -s 128 --align-payload=8 <device>
1500 This results in a data offset of 0x81000, i.e. 516KiB or 528384
1501 bytes. Add one 512 byte sector and the smallest LUKS container size
1502 with these parameters is 516KiB + 512B or 528896 bytes.
1504 Example 2 - Blowfish 64 bit with CBC (WARNING: insecure):
1506 cryptsetup luksFormat -c blowfish -s 64 --align-payload=8 /dev/loop0
1508 This results in a data offset of 0x41000, i.e. 260kiB or 266240
1509 bytes, with a minimal LUKS container size of 260kiB + 512B or
1513 * 6.14 I think this is overly complicated. Is there an alternative?
1515 Not really. Encryption comes at a price. You can use plain
1516 dm-crypt to simplify things a bit. It does not allow multiple
1517 passphrases, but on the plus side, it has zero on disk description
1518 and if you overwrite some part of a plain dm-crypt partition,
1519 exactly the overwritten parts are lost (rounded up to sector
1523 * 6.15 Can I clone a LUKS container?
1525 You can, but it breaks security, because the cloned container has
1526 the same header and hence the same master key. You cannot change
1527 the master key on a LUKS container, even if you change the
1528 passphrase(s), the master key stays the same. That means whoever
1529 has access to one of the clones can decrypt them all, completely
1530 bypassing the passphrases.
1532 The right way to do this is to first luksFormat the target
1533 container, then to clone the contents of the source container, with
1534 both containers mapped, i.e. decrypted. You can clone the decrypted
1535 contents of a LUKS container in binary mode, although you may run
1536 into secondary issues with GUIDs in filesystems, partition tables,
1537 RAID-components and the like. These are just the normal problems
1538 binary cloning causes.
1540 Note that if you need to ship (e.g.) cloned LUKS containers with a
1541 default passphrase, that is fine as long as each container was
1542 individually created (and hence has its own master key). In this
1543 case, changing the default passphrase will make it secure again.
1546 7. Interoperability with other Disk Encryption Tools
1549 * 7.1 What is this section about?
1551 Cryptsetup for plain dm-crypt can be used to access a number of
1552 on-disk formats created by tools like loop-aes patched into
1553 losetup. This sometimes works and sometimes does not. This
1554 section collects insights into what works, what does not and where
1555 more information is required.
1557 Additional information may be found in the mailing-list archives,
1558 mentioned at the start of this FAQ document. If you have a
1559 solution working that is not yet documented here and think a wider
1560 audience may be interested, please email the FAQ maintainer.
1563 * 7.2 loop-aes: General observations.
1565 One problem is that there are different versions of losetup around.
1566 loop-aes is a patch for losetup. Possible problems and deviations
1567 from cryptsetup option syntax include:
1569 - Offsets specified in bytes (cryptsetup: 512 byte sectors)
1571 - The need to specify an IV offset
1573 - Encryption mode needs specifying (e.g. "-c twofish-cbc-plain")
1575 - Key size needs specifying (e.g. "-s 128" for 128 bit keys)
1577 - Passphrase hash algorithm needs specifying
1579 Also note that because plain dm-crypt and loop-aes format does not
1580 have metadata, autodetection, while feasible in most cases, would
1581 be a lot of work that nobody really wants to do. If you still have
1582 the old set-up, using a verbosity option (-v) on mapping with the
1583 old tool or having a look into the system logs after setup could
1584 give you the information you need.
1587 * 7.3 loop-aes patched into losetup on Debian 5.x, kernel 2.6.32
1589 In this case, the main problem seems to be that this variant of
1590 losetup takes the offset (-o option) in bytes, while cryptsetup
1591 takes it in sectors of 512 bytes each. Example: The losetup command
1593 losetup -e twofish -o 2560 /dev/loop0 /dev/sdb1
1594 mount /dev/loop0 mount-point
1598 cryptsetup create -c twofish -o 5 --skip 5 e1 /dev/sdb1
1599 mount /dev/mapper/e1 mount-point
1602 * 7.4 loop-aes with 160 bit key
1604 This seems to be sometimes used with twofish and blowfish and
1605 represents a 160 bit ripemed160 hash output padded to 196 bit key
1606 length. It seems the corresponding options for cryptsetup are
1608 --cipher twofish-cbc-null -s 192 -h ripemd160:20
1611 8. Issues with Specific Versions of cryptsetup
1614 * 8.1 When using the create command for plain dm-crypt with
1615 cryptsetup 1.1.x, the mapping is incompatible and my data is not
1618 With cryptsetup 1.1.x, the distro maintainer can define different
1619 default encryption modes for LUKS and plain devices. You can check
1620 these compiled-in defaults using "cryptsetup --help". Moreover, the
1621 plain device default changed because the old IV mode was
1622 vulnerable to a watermarking attack.
1624 If you are using a plain device and you need a compatible mode, just
1625 specify cipher, key size and hash algorithm explicitly. For
1626 compatibility with cryptsetup 1.0.x defaults, simple use the
1629 cryptsetup create -c aes-cbc-plain -s 256 -h ripemd160 <name> <dev>
1631 LUKS stores cipher and mode in the metadata on disk, avoiding this
1635 * 8.2 cryptsetup on SLED 10 has problems...
1637 SLED 10 is missing an essential kernel patch for dm-crypt, which
1638 is broken in its kernel as a result. There may be a very old
1639 version of cryptsetup (1.0.x) provided by SLED, which should also
1640 not be used anymore as well. My advice would be to drop SLED 10.
1642 A. Contributors In no particular order: