8 6. Backup and Data Recovery
9 7. Interoperability with other Disk Encryption Tools
10 8. Issues with Specific Versions of cryptsetup
19 This is the FAQ (Frequently Asked Questions) for cryptsetup. It
20 covers Linux disk encryption with plain dm-crypt (one passphrase,
21 no management, no metadata on disk) and LUKS (multiple user keys
22 with one master key, anti-forensic features, metadata block at
23 start of device, ...). The latest version of this FAQ should
24 usually be available at
25 http://code.google.com/p/cryptsetup/wiki/FrequentlyAskedQuestions
30 ATTENTION: If you are going to read just one thing, make it the
31 section on Backup and Data Recovery. By far the most questions on
32 the cryptsetup mailing list are from people that managed to damage
33 the start of their LUKS partitions, i.e. the LUKS header. In
34 most cases, there is nothing that can be done to help these poor
35 souls recover their data. Make sure you understand the problem and
36 limitations imposed by the LUKS security model BEFORE you face
37 such a disaster! In particular, make sure you have a current header
38 backup before doing any potentially dangerous operations.
40 BACKUP: Yes, encrypted disks die, just as normal ones do. A full
41 backup is mandatory, see Section "6. Backup and Data Recovery" on
42 options for doing encrypted backup.
44 CLONING/IMAGING: If you clone or image a LUKS container, you make a
45 copy of the LUKS header and the master key will stay the same!
46 That means that if you distribute an image to several machines, the
47 same master key will be used on all of them, regardless of whether
48 you change the passphrases. Do NOT do this! If you do, a root-user
49 on any of the machines with a mapped (decrypted) container or a
50 passphrase on that machine can decrypt all other copies, breaking
51 security. See also Item 6.15.
53 DISTRIBUTION INSTALLERS: Some distribution installers offer to
54 create LUKS containers in a way that can be mistaken as activation
55 of an existing container. Creating a new LUKS container on top of
56 an existing one leads to permanent, complete and irreversible data
57 loss. It is strongly recommended to only use distribution
58 installers after a complete backup of all LUKS containers has been
61 NO WARNING ON NON-INERACTIVE FORMAT: If you feed cryptsetup from
62 STDIN (e.g. via GnuPG) on LUKS format, it does not give you the
63 warning that you are about to format (and e.g. will lose any
64 pre-existing LUKS container on the target), as it assumes it is
65 used from a script. In this scenario, the responsibility for
66 warning the user and possibly checking for an existing LUKS header
67 is shifted to the script. This is a more general form of the
70 LUKS PASSPHRASE IS NOT THE MASTER KEY: The LUKS passphrase is not
71 used in deriving the master key. It is used in decrypting a master
72 key that is randomly selected on header creation. This means that
73 if you create a new LUKS header on top of an old one with
74 exactly the same parameters and exactly the same passphrase as the
75 old one, it will still have a different master key and your data
76 will be permanently lost.
78 PASSPHRASE CHARACTER SET: Some people have had difficulties with
79 this when upgrading distributions. It is highly advisable to only
80 use the 94 printable characters from the first 128 characters of
81 the ASCII table, as they will always have the same binary
82 representation. Other characters may have different encoding
83 depending on system configuration and your passphrase will not
84 work with a different encoding. A table of the standardized first
85 128 ASCII caracters can, e.g. be found on
86 http://en.wikipedia.org/wiki/ASCII
89 * 1.3 System Specific warnings
91 - Ubuntu as of 4/2011: It seems the installer offers to create
92 LUKS partitions in a way that several people mistook for an offer
93 to activate their existing LUKS partition. The installer gives no
94 or an inadequate warning and will destroy your old LUKS header,
95 causing permanent data loss. See also the section on Backup and
98 This issue has been acknowledged by the Ubuntu dev team, see here:
99 http://launchpad.net/bugs/420080
102 * 1.4 Who wrote this?
104 Current FAQ maintainer is Arno Wagner <arno@wagner.name>. Other
105 contributors are listed at the end. If you want to contribute, send
106 your article, including a descriptive headline, to the maintainer,
107 or the dm-crypt mailing list with something like "FAQ ..." in the
108 subject. You can also send more raw information and have me write
109 the section. Please note that by contributing to this FAQ, you
110 accept the license described below.
112 This work is under the "Attribution-Share Alike 3.0 Unported"
113 license, which means distribution is unlimited, you may create
114 derived works, but attributions to original authors and this
115 license statement must be retained and the derived work must be
116 under the same license. See
117 http://creativecommons.org/licenses/by-sa/3.0/ for more details of
120 Side note: I did text license research some time ago and I think
121 this license is best suited for the purpose at hand and creates the
125 * 1.5 Where is the project website?
127 There is the project website at http://code.google.com/p/cryptsetup/
128 Please do not post questions there, nobody will read them. Use
129 the mailing-list instead.
132 * 1.6 Is there a mailing-list?
134 Instructions on how to subscribe to the mailing-list are at on the
135 project website. People are generally helpful and friendly on the
138 The question of how to unsubscribe from the list does crop up
139 sometimes. For this you need your list management URL, which is
140 sent to you initially and once at the start of each month. Go to
141 the URL mentioned in the email and select "unsubscribe". This page
142 also allows you to request a password reminder.
144 Alternatively, you can send an Email to dm-crypt-request@saout.de
145 with just the word "help" in the subject or message body. Make sure
146 to send it from your list address.
148 The mailing list archive is here:
149 http://dir.gmane.org/gmane.linux.kernel.device-mapper.dm-crypt
155 * 2.1 What is the difference between "plain" and LUKS format?
157 Plain format is just that: It has no metadata on disk, reads all
158 paramters from the commandline (or the defaults), derives a
159 master-key from the passphrase and then uses that to de-/encrypt
160 the sectors of the device, with a direct 1:1 mapping between
161 encrypted and decrypted sectors.
163 Primary advantage is high resilience to damage, as one damaged
164 encrypted sector results in exactly one damaged decrypted sector.
165 Also, it is not readily apparent that there even is encrypted data
166 on the device, as an overwrite with crypto-grade randomness (e.g.
167 from /dev/urandom) looks exactly the same on disk.
169 Side-note: That has limited value against the authorities. In
170 civilized countries, they cannot force you to give up a crypto-key
171 anyways. In the US, the UK and dictatorships around the world,
172 they can force you to give up the keys (using imprisonment or worse
173 to pressure you), and in the worst case, they only need a
174 nebulous "suspicion" about the presence of encrypted data. My
175 advice is to either be ready to give up the keys or to not have
176 encrypted data when traveling to those countries, especially when
177 crossing the borders.
179 Disadvantages are that you do not have all the nice features that
180 the LUKS metadata offers, like multiple passphrases that can be
181 changed, the cipher being stored in the metadata, anti-forensic
182 properties like key-slot diffusion and salts, etc..
184 LUKS format uses a metadata header and 8 key-slot areas that are
185 being placed ath the begining of the disk, see below under "What
186 does the LUKS on-disk format looks like?". The passphrases are used
187 to decryt a single master key that is stored in the anti-forensic
190 Advantages are a higher usability, automatic configuration of
191 non-default crypto parameters, defenses against low-entropy
192 passphrases like salting and iterated PBKDF2 passphrase hashing,
193 the ability to change passhrases, and others.
195 Disadvantages are that it is readily obvious there is encrypted
196 data on disk (but see side note above) and that damage to the
197 header or key-slots usually results in permanent data-loss. See
198 below under "6. Backup and Data Recovery" on how to reduce that
199 risk. Also the sector numbers get shifted by the length of the
200 header and key-slots and there is a loss of that size in capacity
201 (1MB+4096B for defaults and 2MB for the most commonly used
202 non-default XTS mode).
205 * 2.2 Can I encrypt an already existing, non-empty partition to use
208 There is no converter, and it is not really needed. The way to do
209 this is to make a backup of the device in question, securely wipe
210 the device (as LUKS device initialization does not clear away old
211 data), do a luksFormat, optionally overwrite the encrypted device,
212 create a new filesystem and restore your backup on the now
213 encrypted device. Also refer to sections "Security Aspects" and
214 "Backup and Data Recovery".
216 For backup, plain GNU tar works well and backs up anything likely
217 to be in a filesystem.
220 * 2.3 How do I use LUKS with a loop-device?
222 This can be very handy for experiments. Setup is just the same as
223 with any block device. If you want, for example, to use a 100MiB
224 file as LUKS container, do something like this:
226 head -c 100M /dev/zero > luksfile # create empty file
227 losetup /dev/loop0 luksfile # map luksfile to /dev/loop0
228 cryptsetup luksFormat /dev/loop0 # create LUKS on loop device
230 Afterwards just use /dev/loop0 as a you would use a LUKS partition.
231 To unmap the file when done, use "losetup -d /dev/loop0".
234 * 2.4 When I add a new key-slot to LUKS, it asks for a passphrase but
235 then complains about there not being a key-slot with that
238 That is as intended. You are asked a passphrase of an existing
239 key-slot first, before you can enter the passphrase for the new
240 key-slot. Otherwise you could break the encryption by just adding a
241 new key-slot. This way, you have to know the passphrase of one of
242 the already configured key-slots in order to be able to configure a
246 * 2.5 Encrytion on top of RAID or the other way round?
248 Unless you have special needs, place encryption between RAID and
249 filesystem, i.e. encryption on top of RAID. You can do it the other
250 way round, but you have to be aware that you then need to give the
251 pasphrase for each individual disk and RAID autotetection will not
252 work anymore. Therefore it is better to encrypt the RAID device,
256 * 2.6 How do I read a dm-crypt key from file?
258 Note that the file will still be hashed first, just like keyboard
259 input. Use the --key-file option, like this:
261 cryptsetup create --key-file keyfile e1 /dev/loop0
264 * 2.7 How do I read a LUKS slot key from file?
266 What you really do here is to read a passphrase from file, just as
267 you would with manual entry of a passphrase for a key-slot. You can
268 add a new passphrase to a free key-slot, set the passphrase of an
269 specific key-slot or put an already configured passphrase into a
270 file. In the last case make sure no trailing newline (0x0a) is
271 contained in the key file, or the passphrase will not work because
272 the whole file is used as input.
274 To add a new passphrase to a free key slot from file, use something
277 cryptsetup luksAddKey /dev/loop0 keyfile
279 To add a new passphrase to a specific key-slot, use something like
282 cryptsetup luksAddKey --key-slot 7 /dev/loop0 keyfile
284 To supply a key from file to any LUKS command, use the --key-file
285 option, e.g. like this:
287 cryptsetup luksOpen --key-file keyfile /dev/loop0 e1
290 * 2.8 How do I read the LUKS master key from file?
292 The question you should ask yourself first is why you would want to
293 do this. The only legitimate reason I can think of is if you want
294 to have two LUKS devices with the same master key. Even then, I
295 think it would be preferable to just use key-slots with the same
296 passphrase, or to use plain dm-crypt instead. If you really have a
297 good reason, please tell me. If I am convinced, I will add how to
301 * 2.9 What are the security requirements for a key read from file?
303 A file-stored key or passphrase has the same security requirements
304 as one entered interactively, however you can use random bytes and
305 thereby use bytes you cannot type on the keyboard. You can use any
306 file you like as key file, for example a plain text file with a
307 human readable passphrase. To generate a file with random bytes,
308 use something like this:
310 head -c 256 /dev/random > keyfile
313 * 2.10 If I map a journaled file system using dm-crypt/LUKS, does it
314 still provide its usual transactional guarantees?
316 Yes, it does, unless a very old kernel is used. The required flags
317 come from the filesystem layer and are processed and passed onwards
318 by dm-crypt. A bit more information on the process by which
319 transactional guarantees are implemented can be found here:
321 http://lwn.net/Articles/400541/
323 Please note that these "guarantees" are weaker than they appear to
324 be. One problem is that quite a few disks lie to the OS about
325 having flushed their buffers. Some other things can go wrong as
326 well. The filesystem developers are aware of these problems and
327 typically can make it work anyways. That said, dm-crypt/LUKS will
328 not make things worse.
330 One specific problem you can run into though is that you can get
331 short freezes and other slowdowns due to the encryption layer.
332 Encryption takes time and forced flushes will block for that time.
333 For example, I did run into frequent small freezes (1-2 sec) when
334 putting a vmware image on ext3 over dm-crypt. When I went back to
335 ext2, the problem went away. This seems to have gotten better with
336 kernel 2.6.36 and the reworking of filesystem flush locking
337 mechanism (less blocking of CPU activity during flushes). It
338 should improve further and eventually the problem should go away.
341 * 2.11 Can I use LUKS or cryptsetup with a more secure (external)
342 medium for key storage, e.g. TPM or a smartcard?
344 Yes, see the answers on using a file-supplied key. You do have to
345 write the glue-logic yourself though. Basically you can have
346 cryptsetup read the key from STDIN and write it there with your
347 own tool that in turn gets the key from the more secure key
351 * 2.12 Can I resize a dm-crypt or LUKS partition?
353 Yes, you can, as neither dm-crypt nor LUKS stores partition size.
354 Whether you should is a different question. Personally I recommend
355 backup, recreation of the encrypted partition with new size,
356 recreation of the filesystem and restore. This gets around the
357 tricky business of resizing the filesystem. Resizing a dm-crypt or
358 LUKS container does not resize the filesystem in it. The backup is
359 really non-optional here, as a lot can go wrong, resulting in
360 partial or complete data loss. Using something like gparted to
361 resize an encrypted partition is slow, but typicaly works. This
362 will not change the size of the filesystem hidden under the
365 You also need to be aware of size-based limitations. The one
366 currently relevant is that aes-xts-plain should not be used for
367 encrypted container sizes larger than 2TiB. Use aes-xts-plain64
374 * 3.1 My dm-crypt/LUKS mapping does not work! What general steps are
375 there to investigate the problem?
377 If you get a specific error message, investigate what it claims
378 first. If not, you may want to check the following things.
380 - Check that "/dev", including "/dev/mapper/control" is there. If it
381 is missing, you may have a problem with the "/dev" tree itself or
382 you may have broken udev rules.
384 - Check that you have the device mapper and the crypt target in your
385 kernel. The output of "dmsetup targets" should list a "crypt"
386 target. If it is not there or the command fails, add device mapper
387 and crypt-target to the kernel.
389 - Check that the hash-functions and ciphers you want to use are in
390 the kernel. The output of "cat /proc/crypto" needs to list them.
393 * 3.2 My dm-crypt mapping suddenly stopped when upgrading cryptsetup.
395 The default cipher, hash or mode may have changed (the mode changed
396 from 1.0.x to 1.1.x). See under "Issues With Specific Versions of
400 * 3.3 When I call cryptsetup from cron/CGI, I get errors about
403 If you get errors about unknown parameters or the like that are not
404 present when cryptsetup is called from the shell, make sure you
405 have no older version of cryptsetup on your system that then gets
406 called by cron/CGI. For example some distributions install
407 cryptsetup into /usr/sbin, while a manual install could go to
408 /usr/local/sbin. As a debugging aid, call "cryptsetup --version"
409 from cron/CGI or the non-shell mechanism to be sure the right
413 * 3.4 Unlocking a LUKS device takes very long. Why?
415 The iteration time for a key-slot (see Section 5 for an explanation
416 what iteration does) is calculated when setting a passphrase. By
417 default it is 1 second on the machine where the passphrase is set.
418 If you set a passphrase on a fast machine and then unlock it on a
419 slow machine, the unlocking time can be much longer. Also take into
420 account that up to 8 key-slots have to be tried in order to find the
423 If this is problem, you can add another key-slot using the slow
424 machine with the same passphrase and then remove the old key-slot.
425 The new key-slot will have an iteration count adjusted to 1 second
426 on the slow machine. Use luksKeyAdd and then luksKillSlot or
429 However, this operation will not change volume key iteration count
430 (MK iterations in output of "cryptsetup luksDump"). In order to
431 change that, you will have to backup the data in the LUKS
432 container (i.e. your encrypted data), luksFormat on the slow
433 machine and restore the data. Note that in the original LUKS
434 specification this value was fixed to 10, but it is now derived
435 from the PBKDF2 benchmark as well and set to iterations in 0.125
436 sec or 1000, whichever is larger. Also note that MK iterations
437 are not very security relevant. But as each key-slot already takes
438 1 second, spending the additional 0.125 seconds really does not
442 * 3.5 "blkid" sees a LUKS UUID and an ext2/swap UUID on the same
443 device. What is wrong?
445 Some old versions of cryptsetup have a bug where the header does
446 not get completely wiped during LUKS format and an older ext2/swap
447 signature remains on the device. This confuses blkid.
449 Fix: Wipe the unused header areas by doing a backup and restore of
450 the header with cryptsetup 1.1.x:
452 cryptsetup luksHeaderBackup --header-backup-file <file> <device>
453 cryptsetup luksHeaderRestore --header-backup-file <file> <device>
456 * 3.6 cryptsetup segfaults on Gentoo amd64 hardened ...
458 There seems to be some inteference between the hardening and and
459 the way cryptsetup benchmarks PBKDF2. The solution to this is
460 currently not quite clear for an encrypted root filesystem. For
461 other uses, you can apparently specify USE="dynamic" as compile
462 flag, see http://bugs.gentoo.org/show_bug.cgi?id=283470
468 * 4.1 I get the error "LUKS keyslot x is invalid." What does that
471 This means that the given keyslot has an offset that points
472 outside the valid keyslot area. Typically, the reason is a
473 corrupted LUKS header because something was written to the start of
474 the device the LUKS contaner is on. Refer to Section "Backup and
475 Data Recovery" and ask on the mailing list if you have trouble
476 diagnosing and (if still possible) repairing this.
479 * 4.2 Can a bad RAM module cause problems?
481 LUKS and dm-crypt can give the RAM quite a workout, especially when
482 combined with software RAID. In particular the combination RAID5 +
483 LUKS + XFS seems to uncover RAM problems that never caused obvious
484 problems before. Symptoms vary, but often the problem manifest
485 itself when copying large amounts of data, typically several times
486 larger than your main memory.
488 Side note: One thing you should always do on large data
489 copy/movements is to run a verify, for example with the "-d"
490 option of "tar" or by doing a set of MD5 checksums on the source
493 find . -type f -exec md5sum \{\} \; > checksum-file
495 and then a "md5sum -c checksum-file" on the other side. If you get
496 mismatches here, RAM is the primary suspect. A lesser suspect is
497 an overclocked CPU. I have found countless hardware problems in
498 verify runs after copying or making backups. Bit errors are much
499 more common than most people think.
501 Some RAM issues are even worse and corrupt structures in one of the
502 layers. This typically results in lockups, CPU state dumps in the
503 system logs, kernel panic or other things. It is quite possible to
504 have the problem with an encrypted device, but not with an
505 otherwise the same unencrypted device. The reason for that is that
506 encryption has an error amplification property: You flip one bit
507 in an encrypted data block, and the decrypted version has half of
508 its bits flipped. This is an important security property for modern
509 ciphers. With the usual modes in cryptsetup (CBC, ESSIV, XTS), you
510 get up to a completely changed 512 byte block per bit error. A
511 corrupt block causes a lot more havoc than the occasionally
512 flipped single bit and can result in various obscure errors.
514 Note, that a verify run on copying between encrypted or
515 unencrypted devices will reliably detect corruption, even when the
516 copying itself did not report any problems. If you find defect
517 RAM, assume all backups and copied data to be suspect, unless you
521 * 4.3 How do I test RAM?
523 First you should know that overclocking often makes memory
524 problems worse. So if you overclock (which I strongly recommend
525 against in a system holding data that has some worth), run the
526 tests with the overclocking active.
528 There are two good options. One is Memtest86+ and the other is
529 "memtester" by Charles Cazabon. Memtest86+ requires a reboot and
530 then takes over the machine, while memtester runs from a
531 root-shell. Both use different testing methods and I have found
532 problems fast with each one that the other needed long to find. I
533 recommend running the following procedure until the first error is
536 - Run Memtest86+ for one cycle
538 - Run memterster for one cycle (shut down as many other applications
541 - Run Memtest86+ for 24h or more
543 - Run memtester for 24h or more
545 If all that does not produce error messages, your RAM may be sound,
546 but I have had one weak bit that Memtest86+ needed around 60 hours
547 to find. If you can reproduce the original problem reliably, a good
548 additional test may be to remove half of the RAM (if you have more
549 than one module) and try whether the problem is still there and if
550 so, try with the other half. If you just have one module, get a
551 different one and try with that. If you do overclocking, reduce
552 the settings to the most conservative ones available and try with
559 * 5.1 Is LUKS insecure? Everybody can see I have encrypted data!
561 In practice it does not really matter. In most civilized countries
562 you can just refuse to hand over the keys, no harm done. In some
563 countries they can force you to hand over the keys, if they suspect
564 encryption. However the suspicion is enough, they do not have to
565 prove anything. This is for practical reasons, as even the presence
566 of a header (like the LUKS header) is not enough to prove that you
567 have any keys. It might have been an experiment, for example. Or it
568 was used as encrypted swap with a key from /dev/random. So they
569 make you prove you do not have encrypted data. Of course that is
570 just as impossible as the other way round.
572 This means that if you have a large set of random-looking data,
573 they can already lock you up. Hidden containers (encryption hidden
574 within encryption), as possible with Truecrypt, do not help
575 either. They will just assume the hidden container is there and
576 unless you hand over the key, you will stay locked up. Don't have
577 a hidden container? Though luck. Anybody could claim that.
579 Still, if you are concerned about the LUKS header, use plain
580 dm-crypt with a good passphrase. See also Section 2, "What is the
581 difference between "plain" and LUKS format?"
584 * 5.2 Should I initialize (overwrite) a new LUKS/dm-crypt partition?
586 If you just create a filesystem on it, most of the old data will
587 still be there. If the old data is sensitive, you should overwrite
588 it before encrypting. In any case, not initializing will leave the
589 old data there until the specific sector gets written. That may
590 enable an attacker to determine how much and where on the
591 partition data was written. If you think this is a risk, you can
592 prevent this by overwriting the encrypted device (here assumed to
593 be named "e1") with zeros like this:
595 dd_rescue -w /dev/zero /dev/mapper/e1
597 or alternatively with one of the following more standard commands:
599 cat /dev/zero > /dev/mapper/e1
600 dd if=/dev/zero of=/dev/mapper/e1
603 * 5.3 How do I securely erase a LUKS (or other) partition?
605 For LUKS, if you are in a desperate hurry, overwrite the LUKS
606 header and key-slot area. This means overwriting the first
607 (keyslots x stripes x keysize) + offset bytes. For the default
608 parameters, this is the 1'052'672 bytes, i.e. 1MiB + 4096 of the
609 LUKS partition. For 512 bit key length (e.g. for aes-xts-plain with
610 512 bit key) this is 2MiB. (The diferent offset stems from
611 differences in the sector alignment of the key-slots.) If in doubt,
612 just be generous and overwrite the first 10MB or so, it will likely
613 still be fast enough. A single overwrite with zeros should be
614 enough. If you anticipate being in a desperate hurry, prepare the
615 command beforehand. Example with /dev/sde1 as the LUKS partition
616 and default parameters:
618 head -c 1052672 /dev/zero > /dev/sde1; sync
620 A LUKS header backup or full backup will still grant access to
621 most or all data, so make sure that an attacker does not have
622 access to backups or destroy them as well.
624 If you have time, overwrite the whole LUKS partition with a single
625 pass of zeros. This is enough for current HDDs. For SSDs or FLASH
626 (USB sticks) you may want to overwrite the whole drive several
627 times to be sure data is not retained by wear leveling. This is
628 possibly still insecure as SSD technology is not fully understood
629 in this regard. Still, due to the anti-forensic properties of the
630 LUKS key-slots, a single overwrite of an SSD or FLASH drive could
631 be enough. If in doubt, use physical destruction in addition. Here
632 is a link to some current reseach results on erasing SSDs and FLASH
634 http://www.usenix.org/events/fast11/tech/full_papers/Wei.pdf
636 Keep in mind to also erase all backups.
638 Example for a zero-overwrite erase of partition sde1 done with
641 dd_rescue -w /dev/zero /dev/sde1
644 * 5.4 How do I securely erase a backup of a LUKS partition or header?
646 That depends on the medium it is stored on. For HDD and SSD, use
647 overwrite with zeros. For an SSD or FLASH drive (USB stick), you
648 may want to overwrite the complete SSD several times and use
649 physical destruction in addition, see last item. For re-writable
650 CD/DVD, a single overwrite should also be enough, due to the
651 anti-forensic properties of the LUKS keyslots. For write-once
652 media, use physical destruction. For low security requirements,
653 just cut the CD/DVD into several parts. For high security needs,
654 shred or burn the medium. If your backup is on magnetic tape, I
655 advise physical destruction by shredding or burning, after
656 overwriting . The problem with magnetic tape is that it has a
657 higher dynamic range than HDDs and older data may well be
658 recoverable after overwrites. Also write-head alignment issues can
659 lead to data not actually being deleted at all during overwrites.
662 * 5.5 What about backup? Does it compromise security?
664 That depends. See item 6.7.
667 * 5.6 Why is all my data permanently gone if I overwrite the LUKS
670 Overwriting the LUKS header in part or in full is the most common
671 reason why access to LUKS containers is lost permanently.
672 Overwriting can be done in a number of fashions, like creating a
673 new filesystem on the raw LUKS partition, making the raw partition
674 part of a raid array and just writing to the raw partition.
676 The LUKS header contains a 256 bit "salt" value and without that no
677 decryption is possible. While the salt is not secret, it is
678 key-grade material and cannot be reconstructed. This is a
679 cryptographically strong "cannot". From observations on the
680 cryptsetup mailing-list, people typically go though the usual
681 stages of grief (Denial, Anger, Bargaining, Depression, Acceptance)
682 when this happens to them. Observed times vary between 1 day and 2
683 weeks to complete the cycle. Seeking help on the mailing-list is
684 fine. Even if we usually cannot help with getting back your data,
685 most people found the feedback comforting.
687 If your header does not contain an intact salt, best go directly
688 to the last stage ("Acceptance") and think about what to do now.
689 There is one exception that I know of: If your LUKS container is
690 still open, then it may be possible to extract the master key from
691 the running system. See Item "How do I recover the master key from
692 a mapped LUKS container?" in Section "Backup and Data Recovery".
695 * 5.7 What is a "salt"?
697 A salt is a random key-grade value added to the passphrase before
698 it is processed. It is not kept secret. The reason for using salts
699 is as follows: If an attacker wants to crack the password for a
700 single LUKS container, then every possible passphrase has to be
701 tried. Typically an attacker will not try every binary value, but
702 will try words and sentences from a dictionary.
704 If an attacker wants to attack several LUKS containers with the
705 same dictionary, then a different approach makes sense: Compute the
706 resulting slot-key for each dictionary element and store it on
707 disk. Then the test for each entry is just the slow unlocking with
708 the slot key (say 0.00001 sec) instead of calculating the slot-key
709 first (1 sec). For a single attack, this does not help. But if you
710 have more than one container to attack, this helps tremendously,
711 also because you can prepare your table before you even have the
712 container to attack! The calculation is also very simple to
713 parallelize. You could, for example, use the night-time unused CPU
714 power of your desktop PCs for this.
716 This is where the salt comes in. If the salt is combined with the
717 passphrase (in the simplest form, just appended to it), you
718 suddenly need a separate table for each salt value. With a
719 reasonably-sized salt value (256 bit, e.g.) this is quite
723 * 5.8 Is LUKS secure with a low-entropy (bad) passphrase?
725 Note: You should only use the 94 printable characters from 7 bit
726 ASCII code to prevent your passphrase from failing when the
727 character encoding changes, e.g. because of a system upgrade, see
728 also the note at the very start of this FAQ under "WARNINGS".
730 This needs a bit of theory. The quality of your passphrase is
731 directly related to its entropy (information theoretic, not
732 thermodynamic). The entropy says how many bits of "uncertainty" or
733 "randomness" are in you passphrase. In other words, that is how
734 difficult guessing the passphrase is.
736 Example: A random English sentence has about 1 bit of entropy per
737 character. A random lowercase (or uppercase) character has about
740 Now, if n is the number of bits of entropy in your passphrase and t
741 is the time it takes to process a passphrase in order to open the
742 LUKS container, then an attacker has to spend at maximum
744 attack_time_max = 2^n * t
746 time for a successful attack and on average half that. There is no
747 way getting around that relationship. However, there is one thing
748 that does help, namely increasing t, the time it takes to use a
749 passphrase, see next FAQ item.
751 Still, if you want good security, a high-entropy passphrase is the
752 only option. For example, a low-entropy passphrase can never be
753 considered secure against a TLA-level (Three Letter Agency level,
754 i.e. government-level) attacker, no matter what tricks are used in
755 the key-derivation function. Use at least 64 bits for secret stuff.
756 That is 64 characters of English text (but only if randomly chosen)
757 or a combination of 12 truly random letters and digits.
759 For passphrase generation, do not use lines from very well-known
760 texts (religious texts, Harry potter, etc.) as they are to easy to
761 guess. For example, the total Harry Potter has about 1'500'000
762 words (my estimation). Trying every 64 character sequence starting
763 and ending at a word boundary would take only something like 20
764 days on a single CPU and is entirely feasible. To put that into
765 perspective, using a number of Amazon EC2 High-CPU Extra Large
766 instances (each gives about 8 real cores), this test costs
767 currently about 50USD/EUR, but can be made to run arbitrarily fast.
769 On the other hand, choosing 1.5 lines from, say, the Wheel of Time
770 is in itself not more secure, but the book selection adds quite a
771 bit of entropy. (Now that I have mentioned it here, don't use tWoT
772 either!) If you add 2 or 3 typos or switch some words around, then
773 this is good passphrase material.
776 * 5.9 What is "iteration count" and why is decreasing it a bad idea?
778 Iteration count is the number of PBKDF2 iterations a passphrase is
779 put through before it is used to unlock a key-slot. Iterations are
780 done with the explicit purpose to increase the time that it takes
781 to unlock a key-slot. This provides some protection against use of
782 low-entropy passphrases.
784 The idea is that an attacker has to try all possible passphrases.
785 Even if the attacker knows the passphrase is low-entropy (see last
786 item), it is possible to make each individual try take longer. The
787 way to do this is to repeatedly hash the passphrase for a certain
788 time. The attacker then has to spend the same time (given the same
789 computing power) as the user per try. With LUKS, the default is 1
790 second of PBKDF2 hashing.
792 Example 1: Lets assume we have a really bad passphrase (e.g. a
793 girlfriends name) with 10 bits of entropy. With the same CPU, an
794 attacker would need to spend around 500 seconds on average to
795 break that passphrase. Without iteration, it would be more like
796 0.0001 seconds on a modern CPU.
798 Example 2: The user did a bit better and has 32 chars of English
799 text. That would be about 32 bits of entropy. With 1 second
800 iteration, that means an attacker on the same CPU needs around 136
801 years. That is pretty impressive for such a weak passphrase.
802 Without the iterations, it would be more like 50 days on a modern
803 CPU, and possibly far less.
805 In addition, the attacker can both parallelize and use special
806 hardware like GPUs or FPGAs to speed up the attack. The attack can
807 also happen quite some time after the luksFormat operation and CPUs
808 can have become faster and cheaper. For that reason you want a
809 bit of extra security. Anyways, in Example 1 your are screwed.
810 In example 2, not necessarily. Even if the attack is faster, it
811 still has a certain cost associated with it, say 10000 EUR/USD
812 with iteration and 1 EUR/USD without iteration. The first can be
813 prohibitively expensive, while the second is something you try
814 even without solid proof that the decryption will yield something
817 The numbers above are mostly made up, but show the idea. Of course
818 the best thing is to have a high-entropy passphrase.
820 Would a 100 sec iteration time be even better? Yes and no.
821 Cryptographically it would be a lot better, namely 100 times better.
822 However, usability is a very important factor for security
823 technology and one that gets overlooked surprisingly often. For
824 LUKS, if you have to wait 2 minutes to unlock the LUKS container,
825 most people will not bother and use less secure storage instead. It
826 is better to have less protection against low-entropy passphrases
827 and people actually use LUKS, than having them do without
828 encryption altogether.
830 Now, what about decreasing the iteration time? This is generally a
831 very bad idea, unless you know and can enforce that the users only
832 use high-entropy passphrases. If you decrease the iteration time
833 without ensuring that, then you put your users at increased risk,
834 and considering how rarely LUKS containers are unlocked in a
835 typical work-flow, you do so without a good reason. Don't do it.
836 The iteration time is already low enough that users with entropy
837 low passphrases are vulnerable. Lowering it even further increases
838 this danger significantly.
841 * 5.10 Some people say PBKDF2 is insecure?
843 There is some discussion that a hash-function should have a "large
844 memory" property, i.e. that it should require a lot of memory to be
845 computed. This serves to prevent attacks using special programmable
846 circuits, like FPGAs, and attacks using graphics cards. PBKDF2
847 does not need a lot of memory and is vulnerable to these attacks.
848 However, the publication usually refered in these discussions is
849 not very convincing in proving that the presented hash really is
850 "large memory" (that may change, email the FAQ maintainer when it
851 does) and it is of limited usefulness anyways. Attackers that use
852 clusters of normal PCs will not be affected at all by a "large
853 memory" property. For example the US Secret Service is known to
854 use the off-hour time of all the office PCs of the Treasury for
855 password breaking. The Treasury has about 110'000 employees.
856 Asuming every one has an office PC, that is significant computing
857 power, all of it with plenty of memory for computing "large
858 memory" hashes. Bot-net operators also have all the memory they
859 want. The only protection against a resouceful attacker is a
860 high-entropy passphrase, see items 5.8 and 5.9.
863 * 5.11 What about iteration count with plain dm-crypt?
865 Simple: There is none. There is also no salting. If you use plain
866 dm-crypt, the only way to be secure is to use a high entropy
867 passphrase. If in doubt, use LUKS instead.
870 * 5.12 Is LUKS with default parameters less secure on a slow CPU?
872 Unfortunately, yes. However the only aspect affected is the
873 protection for low-entropy passphrase or master-key. All other
874 security aspects are independent of CPU speed.
876 The master key is less critical, as you really have to work at it
877 to give it low entropy. One possibility is to supply the master key
878 yourself. If that key is low-entropy, then you get what you
879 deserve. The other known possibility is to use /dev/urandom for
880 key generation in an entropy-startved situation (e.g. automatic
881 installation on an embedded device without network and other entropy
884 For the passphrase, don't use a low-entropy passphrase. If your
885 passphrase is good, then a slow CPU will not matter. If you insist
886 on a low-entropy passphrase on a slow CPU, use something like
887 "--iter-time=10" or higher and wait a long time on each LUKS unlock
888 and pray that the attacker does not find out in which way exactly
889 your passphrase is low entropy. This also applies to low-entropy
890 passphrases on fast CPUs. Technology can do only so much to
891 compensate for problems in front of the keyboard.
894 * 5.13 Why was the default aes-cbc-plain replaced with aes-cbc-essiv?
896 The problem is that cbc-plain has a fingerprint vulnerability, where
897 a specially crafted file placed into the crypto-container can be
898 recognized from the outside. The issue here is that for cbc-plain
899 the initialization vector (IV) is the sector number. The IV gets
900 XORed to the first data chunk of the sector to be encrypted. If you
901 make sure that the first data block to be stored in a sector
902 contains the sector number as well, the first data block to be
903 encrypted is all zeros and always encrypted to the same ciphertext.
904 This also works if the first data chunk just has a constant XOR
905 with the sector number. By having several shifted patterns you can
906 take care of the case of a non-power-of-two start sector number of
909 This mechanism allows you to create a pattern of sectors that have
910 the same first ciphertext block and signal one bit per sector to the
911 outside, allowing you to e.g. mark media files that way for
912 recognition without decryption. For large files this is a
913 practical attack. For small ones, you do not have enough blocks to
914 signal and take care of different file starting offsets.
916 In order to prevent this attack, the default was changed to
917 cbc-essiv. ESSIV uses a keyed hash of the sector number, with the
918 encryption key as key. This makes the IV unpredictable without
919 knowing the encryption key and the watermarking attack fails.
922 * 5.14 Are there any problems with "plain" IV? What is "plain64"?
924 First, "plain" and "plain64" are both not secure to use with CBC,
925 see previous FAQ item.
927 However there are modes, like XTS, that are secure with "plain" IV.
928 The next limit is that "plain" is 64 bit, with the upper 32 bit set
929 to zero. This means that on volumes larger than 2TiB, the IV
930 repeats, creating a vulnerability that potentially leaks some
931 data. To avoid this, use "plain64", which uses the full sector
932 number up to 64 bit. Note that "plain64" requires a kernel >=
933 2.6.33. Also note that "plain64" is backwards compatible for
934 volume sizes <= 2TiB, but not for those > 2TiB. Finally, "plain64"
935 does not cause any performance penalty compared to "plain".
938 * 5.15 What about XTS mode?
940 XTS mode is potentially even more secure than cbc-essiv (but only if
941 cbc-essiv is insecure in your scenario). It is a NIST standard and
942 used, e.g. in Truecrypt. At the moment, if you want to use it, you
943 have to specify it manually as "aes-xts-plain", i.e.
945 cryptsetup -c aes-xts-plain luksFormat <device>
947 For volumes >2TiB and kernels >= 2.6.33 use "plain64" (see FAQ
948 item on "plain" and "plain64"):
950 cryptsetup -c aes-xts-plain64 luksFormat <device>
952 There is a potential security issue with XTS mode and large blocks.
953 LUKS and dm-crypt always use 512B blocks and the issue does not
957 * 5.16 Is LUKS FIPS-140-2 certified?
959 No. But that is more a problem of FIPS-140-2 than of LUKS. From a
960 technical point-of-view, LUKS with the right parameters would be
961 FIPS-140-2 compliant, but in order to make it certified, somebody
962 has to pay real money for that. And then, whenever cryptsetup is
963 changed or extended, the certification lapses and has to be
966 From the aspect of actual security, LUKS with default parameters
967 should be as good as most things that are FIPS-140-2 certified,
968 although you may want to make sure to use /dev/random (by
969 specifying --use-random on luksFormat) as randomness source for
970 the master key to avoid being potentially insecure in an
971 entropy-starved situation.
974 6. Backup and Data Recovery
977 * 6.1 Why do I need Backup?
979 First, disks die. The rate for well-treated (!) disk is about 5%
980 per year, which is high enough to worry about. There is some
981 indication that this may be even worse for some SSDs. This applies
982 both to LUKS and plain dm-crypt partitions.
984 Second, for LUKS, if anything damages the LUKS header or the
985 key-stripe area then decrypting the LUKS device can become
986 impossible. This is a frequent occurrence. For example an
987 accidental format as FAT or some software overwriting the first
988 sector where it suspects a partition boot sector typically makes a
989 LUKS partition permanently inacessible. See more below on LUKS
992 So, data-backup in some form is non-optional. For LUKS, you may
993 also want to store a header backup in some secure location. This
994 only needs an update if you change passphrases.
997 * 6.2 How do I backup a LUKS header?
999 While you could just copy the appropriate number of bytes from the
1000 start of the LUKS partition, the best way is to use command option
1001 "luksHeaderBackup" of cryptsetup. This protects also against
1002 errors when non-standard parameters have been used in LUKS
1003 partition creation. Example:
1006 cryptsetup luksHeaderBackup --header-backup-file <file> <device>
1008 To restore, use the inverse command, i.e.
1010 cryptsetup luksHeaderRestore --header-backup-file <file> <device>
1013 * 6.3 How do I test a LUKS header?
1017 cryptsetup -v isLuks <device>
1019 on the device. Without the "-v" it just signals its result via
1020 exit-status. You can alos use the more general test
1024 which will also detect other types and give some more info. Omit
1025 "-p" for old versions of blkid that do not support it.
1028 * 6.4 How do I backup a LUKS or dm-crypt partition?
1030 There are two options, a sector-image and a plain file or
1031 filesystem backup of the contents of the partition. The sector
1032 image is already encrypted, but cannot be compressed and contains
1033 all empty space. The filesystem backup can be compressed, can
1034 contain only part of the encrypted device, but needs to be
1035 encrypted separately if so desired.
1037 A sector-image will contain the whole partition in encrypted form,
1038 for LUKS the LUKS header, the keys-slots and the data area. It can
1039 be done under Linux e.g. with dd_rescue (for a direct image copy)
1040 and with "cat" or "dd". Example:
1042 cat /dev/sda10 > sda10.img
1043 dd_rescue /dev/sda10 sda10.img
1045 You can also use any other backup software that is capable of making
1046 a sector image of a partition. Note that compression is
1047 ineffective for encrypted data, hence it does not make sense to
1050 For a filesystem backup, you decrypt and mount the encrypted
1051 partition and back it up as you would a normal filesystem. In this
1052 case the backup is not encrypted, unless your encryption method
1053 does that. For example you can encrypt a backup with "tar" as
1056 tar cjf - <path> | gpg --cipher-algo AES -c - > backup.tbz2.gpg
1058 And verify the backup like this if you are at "path":
1060 cat backup.tbz2.gpg | gpg - | tar djf -
1062 Note: Allways verify backups, especially encrypted ones.
1064 In both cases GnuPG will ask you interactively for your symmetric
1065 key. The verify will only output errors. Use "tar dvjf -" to get
1066 all comparison results. To make sure no data is written to disk
1067 unencrypted, turn off swap if it is not encrypted before doing the
1070 You can of course use different or no compression and you can use
1071 an asymmetric key if you have one and have a backup of the secret
1072 key that belongs to it.
1074 A second option for a filestem-level backup that can be used when
1075 the backup is also on local disk (e.g. an external USB drive) is
1076 to use a LUKS container there and copy the files to be backed up
1077 between both mounted containers. Also see next item.
1080 * 6.5 Do I need a backup of the full partition? Would the header and
1081 key-slots not be enough?
1083 Backup protects you against two things: Disk loss or corruption
1084 and user error. By far the most questions on the dm-crypt mailing
1085 list about how to recover a damaged LUKS partition are related
1086 to user error. For example, if you create a new filesystem on a
1087 LUKS partition, chances are good that all data is lost
1090 For this case, a header+key-slot backup would often be enough. But
1091 keep in mind that a well-treated (!) HDD has roughly a failure
1092 risk of 5% per year. It is highly advisable to have a complete
1093 backup to protect against this case.
1096 * *6.6 What do I need to backup if I use "decrypt_derived"?
1098 This is a script in Debian, intended for mounting /tmp or swap with
1099 a key derived from the master key of an already decrypted device.
1100 If you use this for an device with data that should be persistent,
1101 you need to make sure you either do not lose access to that master
1102 key or have a backup of the data. If you derive from a LUKS
1103 device, a header backup of that device would cover backing up the
1104 master key. Keep in mind that this does not protect against disk
1107 Note: If you recreate the LUKS header of the device you derive from
1108 (using luksFormat), the master key changes even if you use the same
1109 passphrase(s) and you will not be able to decrypt the derived
1110 device with the new LUKS header.
1113 * 6.7 Does a backup compromise security?
1115 Depends on how you do it. However if you do not have one, you are
1116 going to eventually lose your encrypted data.
1118 There are risks introduced by backups. For example if you
1119 change/disable a key-slot in LUKS, a binary backup of the partition
1120 will still have the old key-slot. To deal with this, you have to
1121 be able to change the key-slot on the backup as well, securely
1122 erase the backup or do a filesystem-level backup instead of a binary
1125 If you use dm-crypt, backup is simpler: As there is no key
1126 management, the main risk is that you cannot wipe the backup when
1127 wiping the original. However wiping the original for dm-crypt
1128 should consist of forgetting the passphrase and that you can do
1129 without actual access to the backup.
1131 In both cases, there is an additional (usually small) risk with
1132 binary backups: An attacker can see how many sectors and which
1133 ones have been changed since the backup. To prevent this, use a
1134 filesystem level backup method that encrypts the whole backup in
1135 one go, e.g. as described above with tar and GnuPG.
1137 My personal advice is to use one USB disk (low value data) or
1138 three disks (high value data) in rotating order for backups, and
1139 either use independent LUKS partitions on them, or use encrypted
1140 backup with tar and GnuPG.
1142 If you do network-backup or tape-backup, I strongly recommend to
1143 go the filesystem backup path with independent encryption, as you
1144 typically cannot reliably delete data in these scenarios,
1145 especially in a cloud setting. (Well, you can burn the tape if it
1146 is under your control...)
1149 * 6.8 What happens if I overwrite the start of a LUKS partition or
1150 damage the LUKS header or key-slots?
1152 There are two critical components for decryption: The salt values
1153 in the header itself and the key-slots. If the salt values are
1154 overwritten or changed, nothing (in the cryptographically strong
1155 sense) can be done to access the data, unless there is a backup
1156 of the LUKS header. If a key-slot is damaged, the data can still
1157 be read with a different key-slot, if there is a remaining
1158 undamaged and used key-slot. Note that in order to make a key-slot
1159 unrecoverable in a cryptographically strong sense, changing about
1160 4-6 bits in random locations of its 128kiB size is quite enough.
1163 * 6.9 What happens if I (quick) format a LUKS partition?
1165 I have not tried the different ways to do this, but very likely you
1166 will have written a new boot-sector, which in turn overwrites the
1167 LUKS header, including the salts, making your data permanently
1168 irretrivable, unless you have a LUKS header backup. You may also
1169 damage the key-slots in part or in full. See also last item.
1172 * 6.10 How do I recover the master key from a mapped LUKS container?
1174 This is typically only needed if you managed to damage your LUKS
1175 header, but the container is still mapped, i.e. "luksOpen"ed. It
1176 also helps if you have a mapped container that you forgot or do not
1177 know a passphrase for (e.g. on a long running server.)
1179 WARNING: Things go wrong, do a full backup before trying this!
1181 WARNING: This exposes the master key of the LUKS container. Note
1182 that both ways to recreate a LUKS header with the old master key
1183 described below will write the master key to disk. Unless you are
1184 sure you have securely erased it afterwards, e.g. by writing it to
1185 an encrypted partition, RAM disk or by erasing the filesystem you
1186 wrote it to by a complete overwrite, you should change the master
1187 key afterwards. Changing the master key requires a full data
1188 backup, luksFormat and then restore of the backup.
1190 First, there is a script by Milan that automatizes the whole
1191 process, except generating a new LUKS header with the old master
1192 key (it prints the command for that though):
1194 http://code.google.com/p/cryptsetup/source/browse/trunk/misc/luks-header-from-active
1196 You can also do this manually. Here is how:
1198 - Get the master key from the device mapper. This is done by the
1199 following command. Substitute c5 for whatever you mapped to:
1201 # dmsetup table --target crypt --showkey /dev/mapper/c5
1203 0 200704 crypt aes-cbc-essiv:sha256
1204 a1704d9715f73a1bb4db581dcacadaf405e700d591e93e2eaade13ba653d0d09
1207 The result is actually one line, wrapped here for clarity. The long
1208 hex string is the master key.
1210 - Convert the master key to a binary file representation. You can
1211 do this manually, e.g. with hexedit. You can also use the tool
1212 "xxd" from vim like this:
1214 echo "a1704d9....53d0d09" | xxd -r -p > <master-key-file>
1216 - Do a luksFormat to create a new LUKS header.
1218 NOTE: If your header is intact and you just forgot the
1219 passphrase, you can just set a new passphrase, see next subitem.
1221 Unmap the device before you do that (luksClose). Then do
1223 cryptsetup luksFormat --master-key-file=<master-key-file> <luks device>
1225 Note that if the container was created with other than the default
1226 settings of the cryptsetup version you are using, you need to give
1227 additional parameters specifying the deviations. If in doubt, try
1228 the script by Milan. It does recover the other parameters as well.
1230 Side note: This is the way the decrypt_derived script gets at the
1231 master key. It just omits the conversion and hashes the master key
1234 - If the header is intact and you just forgot the passphrase, just
1235 set a new passphrase like this:
1237 cryptsetup luksAddKey --master-key-file=<master-key-file> <luks device>
1239 You may want to disable the old one afterwards.
1242 * 6.11 What does the on-disk structure of dm-crypt look like?
1244 There is none. dm-crypt takes a block device and gives encrypted
1245 access to each of its blocks with a key derived from the passphrase
1246 given. If you use a cipher different than the default, you have to
1247 specify that as a parameter to cryptsetup too. If you want to
1248 change the password, you basically have to create a second
1249 encrypted device with the new passphrase and copy your data over.
1250 On the plus side, if you accidentally overwrite any part of a
1251 dm-crypt device, the damage will be limited to the are you
1255 * 6.12 What does the on-disk structure of LUKS look like?
1257 A LUKS partition consists of a header, followed by 8 key-slot
1258 descriptors, followed by 8 key slots, followed by the encrypted
1261 Header and key-slot descriptors fill the first 592 bytes. The
1262 key-slot size depends on the creation parameters, namely on the
1263 number of anti-forensic stripes, key material offset and master
1266 With the default parameters, each key-slot is a bit less than
1267 128kiB in size. Due to sector alignment of the key-slot start,
1268 that means the key block 0 is at offset 0x1000-0x20400, key
1269 block 1 at offset 0x21000-0x40400, and key block 7 at offset
1270 0xc1000-0xe0400. The space to the next full sector address is
1271 padded with zeros. Never used key-slots are filled with what the
1272 disk originally contained there, a key-slot removed with
1273 "luksRemoveKey" or "luksKillSlot" gets filled with 0xff. Due to
1274 2MiB default alignment, start of the data area for cryptsetup 1.3
1275 and later is at 2MiB, i.e. at 0x200000. For older versions, it is
1276 at 0x101000, i.e. at 1'052'672 bytes, i.e. at 1MiB + 4096 bytes
1277 from the start of the partition. Incidentally, "luksHeaderBackup"
1278 for a LUKS container created with default parameters dumps exactly
1279 the first 2MiB (or 1'052'672 bytes for headers created with
1280 cryptsetup versions < 1.3) to file and "luksHeaderRestore" restores
1283 For non-default parameters, you have to figure out placement
1284 yourself. "luksDump" helps. See also next item. For the most common
1285 non-default settings, namely aes-xts-plain with 512 bit key, the
1286 offsets are: 1st keyslot 0x1000-0x3f800, 2nd keyslot
1287 0x40000-0x7e000, 3rd keyslot 0x7e000-0xbd800, ..., and start of
1288 bulk data at 0x200000.
1290 The exact specification of the format is here:
1291 http://code.google.com/p/cryptsetup/wiki/Specification
1294 * 6.13 What is the smallest possible LUKS container?
1296 Note: From cryptsetup 1.3 onwards, alignment is set to 1MB. With
1297 modern Linux partitioning tools that also align to 1MB, this will
1298 result in aligmnet to 2k secors and typical Flash/SSD sectors,
1299 which is highly desirable for a number of reasons. Changing the
1300 alignment is not recomended.
1302 That said, with default parameters, the data area starts at
1303 exactly 2MB offset (at 0x101000 for cryptsetup versions before
1304 1.3). The smallest data area you can have is one sector of 512
1305 bytes. Data areas of 0 bytes can be created, but fail on mapping.
1307 While you cannot put a filesystem into something this small, it may
1308 still be used to contain, for example, key. Note that with current
1309 formatting tools, a partition for a container this size will be
1310 3MiB anyways. If you put the LUKS container into a file (via
1311 losetup and a loopback device), the file needs to be 2097664 bytes
1312 in size, i.e. 2MiB + 512B.
1314 There two ways to influence the start of the data area are key-size
1317 For alignment, you can go down to 1 on the parameter. This will
1318 still leave you with a data-area starting at 0x101000, i.e.
1319 1MiB+4096B (default parameters) as alignment will be rounded up to
1320 the next multiple of 8 (i.e. 4096 bytes) If in doubt, do a dry-run
1321 on a larger file and dump the LUKS header to get actual
1324 For key-size, you can use 128 bit (e.g. AES-128 with CBC), 256 bit
1325 (e.g. AES-256 with CBC) or 512 bit (e.g. AES-256 with XTS mode).
1326 You can do 64 bit (e.g. blowfish-64 with CBC), but anything below
1327 128 bit has to be considered insecure today.
1329 Example 1 - AES 128 bit with CBC:
1331 cryptsetup luksFormat -s 128 --align-payload=8 <device>
1333 This results in a data offset of 0x81000, i.e. 516KiB or 528384
1334 bytes. Add one 512 byte sector and the smallest LUKS container size
1335 with these parameters is 516KiB + 512B or 528896 bytes.
1337 Example 2 - Blowfish 64 bit with CBC (WARNING: insecure):
1339 cryptsetup luksFormat -c blowfish -s 64 --align-payload=8 /dev/loop0
1341 This results in a data offset of 0x41000, i.e. 260kiB or 266240
1342 bytes, with a minimal LUKS conatiner size of 260kiB + 512B or
1346 * 6.14 I think this is overly complicated. Is there an alternative?
1348 Not really. Encryption comes at a price. You can use plain
1349 dm-crypt to simplify things a bit. It does not allow multiple
1350 passphrases, but on the plus side, it has zero on disk description
1351 and if you overwrite some part of a plain dm-crypt partition,
1352 exactly the overwritten parts are lost (rounded up to sector
1356 * 6.15 Can I clone a LUKS container?
1358 You can, but it breaks security, because the cloned container has
1359 the same header and hence the same master key. You cannot change
1360 the master key on a LUKS container, even if you change the
1361 passphrase(s), the master key stays the same. That means whoever
1362 has access to one of the clones can decrypt them all, completely
1363 bypassing the passphrases.
1365 The right way to do this is to first luksFormat the target
1366 container, then to clone the contents of the source container, with
1367 both containers mapped, i.e. decrypted. You can clone the decrypted
1368 contents of a LUKS container in binary mode, although you may run
1369 into secondary issuses with GUIDs in filesystems, partition tables,
1370 RAID-components and the like. These are just the normal problems
1371 binary cloning causes.
1373 Note that if you need to ship (e.g.) cloned LUKS containers with a
1374 default passphrase, that is fine as long as each container was
1375 individually created (and hence has its own master key). In this
1376 case, changing the default passphrase will make it secure again.
1379 7. Interoperability with other Disk Encryption Tools
1382 * 7.1 What is this section about?
1384 Cryptsetup for plain dm-crypt can be used to access a number of
1385 on-disk formats created by tools like loop-aes patched into
1386 losetup. This somtimes works and sometimes does not. This section
1387 collects insights into what works, what does not and where more
1388 information is required.
1390 Additional information may be found in the mailing-list archives,
1391 mentioned at the start of this FAQ document. If you have a
1392 solution working that is not yet documented here and think a wider
1393 audience may be intertested, please email the FAQ maintainer.
1396 * 7.2 loop-aes: General observations.
1398 One problem is that there are different versions of losetup around.
1399 loop-aes is a patch for losetup. Possible problems and deviations
1400 from cryptsetup option syntax include:
1402 - Offsets specifed in bytes (cryptsetup: 512 byte sectors)
1404 - The need to specify an IV offset
1406 - Encryption mode needs specifying (e.g. "-c twofish-cbc-plain")
1408 - Key size needs specifying (e.g. "-s 128" for 128 bit keys)
1410 - Passphrase hash algorithm needs specifying
1412 Also note that because plain dm-crypt and loop-aes format does not
1413 have metadata, autodetection, while feasible in most cases, would
1414 be a lot of work that nobody really wants to do. If you still have
1415 the old set-up, using a verbosity option (-v) on mapping with the
1416 old tool or having a look into the system logs after setup could
1417 give you the information you need.
1420 * 7.3 loop-aes patched into losetup on debian 5.x, kernel 2.6.32
1422 In this case, the main problem seems to be that this variant of
1423 losetup takes the offset (-o option) in bytes, while cryptsetup
1424 takes it in sectors of 512 bytes each. Example: The losetupp
1427 losetup -e twofish -o 2560 /dev/loop0 /dev/sdb1
1428 mount /dev/loop0 mountpoint
1432 cryptsetup create -c twofish -o 5 --skip 5 e1 /dev/sdb1
1433 mount /dev/mapper/e1 mountpoint
1436 * 7.4 loop-aes with 160 bit key
1438 This seems to be sometimes used with twofish and blowfish and
1439 represents a 160 bit ripemed160 hash output padded to 196 bit key
1440 length. It seems the corresponding options for cryptsetup are
1442 --cipher twofish-cbc-null -s 192 -h ripemd160:20
1445 8. Issues with Specific Versions of cryptsetup
1448 * 8.1 When using the create command for plain dm-crypt with
1449 cryptsetup 1.1.x, the mapping is incompatible and my data is not
1452 With cryptsetup 1.1.x, the distro maintainer can define different
1453 default encryption modes for LUKS and plain devices. You can check
1454 these compiled-in defaults using "cryptsetup --help". Moreover, the
1455 plain device default changed because the old IV mode was
1456 vulnerable to a watermarking attack.
1458 If you are using a plain device and you need a compatible mode, just
1459 specify cipher, key size and hash algorithm explicitly. For
1460 compatibility with cryptsetup 1.0.x defaults, simple use the
1463 cryptsetup create -c aes-cbc-plain -s 256 -h ripemd160 <name> <dev>
1465 LUKS stores cipher and mode in the metadata on disk, avoiding this
1469 * 8.2 cryptsetup on SLED 10 has problems...
1471 SLED 10 is missing an essential kernel patch for dm-crypt, which
1472 is broken in its kernel as a result. There may be a very old
1473 version of cryptsetup (1.0.x) provided by SLED, which should also
1474 not be used anymore as well. My advice would be to drop SLED 10.
1476 A. Contributors In no particular order: