8 6. Backup and Data Recovery
9 7. Interoperability with other Disk Encryption Tools
10 8. Issues with Specific Versions of cryptsetup
19 This is the FAQ (Frequently Asked Questions) for cryptsetup. It
20 covers Linux disk encryption with plain dm-crypt (one passphrase,
21 no management, no metadata on disk) and LUKS (multiple user keys
22 with one master key, anti-forensic features, metadata block at
23 start of device, ...). The latest version of this FAQ should
24 usually be available at
25 http://code.google.com/p/cryptsetup/wiki/FrequentlyAskedQuestions
30 ATTENTION: If you are going to read just one thing, make it the
31 section on Backup and Data Recovery. By far the most questions on
32 the cryptsetup mailing list are from people that just managed to
33 somehow format or overwrite the start of their LUKS partitions. In
34 most cases, there is nothing that can be done to help these poor
35 souls recover their data. Make sure you understand the problem and
36 limitations imposed by the LUKS security model BEFORE you face such
39 PASSPHRASES: Some people have had difficulties when upgrading
40 distributions. It is highly advisable to only use the 94 printable
41 characters from the first 128 characters of the ASCII table, as
42 they will always have the same binary representation. Other
43 characters may have different encoding depending on system
44 configuration and your passphrase will not work with a different
45 encoding. A table of the standardized first 128 ASCII caracters
46 can, e.g. be found on http://en.wikipedia.org/wiki/ASCII
49 * System Specific warnings
51 - Ubuntu as of 4/2011: It seems the installer offers to create
52 LUKS partitions in a way that several people mistook for an offer
53 to activate their existing LUKS partition. The installer gives no
54 or an inadequate warning and will destroy your old LUKS header,
55 causing permanent data loss. See also the section on Backup and
58 This issue has been acknowledged by the Ubuntu dev team, see here:
59 http://launchpad.net/bugs/420080
64 Current FAQ maintainer is Arno Wagner <arno@wagner.name>. Other
65 contributors are listed at the end. If you want to contribute, send
66 your article, including a descriptive headline, to the maintainer,
67 or the dm-crypt mailing list with something like "FAQ ..." in the
68 subject. You can also send more raw information and have me write
69 the section. Please note that by contributing to this FAQ, you
70 accept the license described below.
72 This work is under the "Attribution-Share Alike 3.0 Unported"
73 license, which means distribution is unlimited, you may create
74 derived works, but attributions to original authors and this
75 license statement must be retained and the derived work must be
76 under the same license. See
77 http://creativecommons.org/licenses/by-sa/3.0/ for more details of
80 Side note: I did text license research some time ago and I think
81 this license is best suited for the purpose at hand and creates the
85 * Where is the project website?
87 There is the project website at http://code.google.com/p/cryptsetup/
88 Please do not post questions there, nobody will read them. Use
89 the mailing-list instead.
92 * Is there a mailing-list?
94 Instructions on how to subscribe to the mailing-list are at on the
95 project website. People are generally helpful and friendly on the
98 The question of how to unsubscribe from the list does crop up
99 sometimes. For this you need your list management URL, which is
100 sent to you initially and once at the start of each month. Go to
101 the URL mentioned in the email and select "unsubscribe". This page
102 also allows you to request a password reminder.
104 Alternatively, you can send an Email to dm-crypt-request@saout.de
105 with just the word "help" in the subject or message body. Make sure
106 to send it from your list address.
108 The mailing list archive is here:
109 http://dir.gmane.org/gmane.linux.kernel.device-mapper.dm-crypt
115 * What is the difference between "plain" and LUKS format?
117 Plain format is just that: It has no metadata on disk, reads all
118 paramters from the commandline (or the defaults), derives a
119 master-key from the passphrase and then uses that to de-/encrypt
120 the sectors of the device, with a direct 1:1 mapping between
121 encrypted and decrypted sectors.
123 Primary advantage is high resilience to damage, as one damaged
124 encrypted sector results in exactly one damaged decrypted sector.
125 Also, it is not readily apparent that there even is encrypted data
126 on the device, as an overwrite with crypto-grade randomness (e.g.
127 from /dev/urandom) looks exactly the same on disk.
129 Side-note: That has limited value against the authorities. In
130 civilized countries, they cannot force you to give up a crypto-key
131 anyways. In the US, the UK and dictatorships around the world,
132 they can force you to give up the keys (using imprisonment or worse
133 to pressure you), and in the worst case, they only need a
134 nebulous "suspicion" about the presence of encrypted data. My
135 advice is to either be ready to give up the keys or to not have
136 encrypted data when traveling to those countries, especially when
137 crossing the borders.
139 Disadvantages are that you do not have all the nice features that
140 the LUKS metadata offers, like multiple passphrases that can be
141 changed, the cipher being stored in the metadata, anti-forensic
142 properties like key-slot diffusion and salts, etc..
144 LUKS format uses a metadata header and 8 key-slot areas that are
145 being placed ath the begining of the disk, see below under "What
146 does the LUKS on-disk format looks like?". The passphrases are used
147 to decryt a single master key that is stored in the anti-forensic
150 Advantages are a higher usability, automatic configuration of
151 non-default crypto parameters, defenses against low-entropy
152 passphrases like salting and iterated PBKDF2 passphrase hashing,
153 the ability to change passhrases, and others.
155 Disadvantages are that it is readily obvious there is encrypted
156 data on disk (but see side note above) and that damage to the
157 header or key-slots usually results in permanent data-loss. See
158 below under "6. Backup and Data Recovery" on how to reduce that
159 risk. Also the sector numbers get shifted by the length of the
160 header and key-slots and there is a loss of that size in capacity
161 (1MB+4096B for defaults and 2MB for the most commonly used
162 non-default XTS mode).
165 * Can I encrypt an already existing, non-empty partition to use LUKS?
167 There is no converter, and it is not really needed. The way to do
168 this is to make a backup of the device in question, securely wipe
169 the device (as LUKS device initialization does not clear away old
170 data), do a luksFormat, optionally overwrite the encrypted device,
171 create a new filesystem and restore your backup on the now
172 encrypted device. Also refer to sections "Security Aspects" and
173 "Backup and Data Recovery".
175 For backup, plain GNU tar works well and backs up anything likely
176 to be in a filesystem.
179 * How do I use LUKS with a loop-device?
181 This can be very handy for experiments. Setup is just the same as
182 with any block device. If you want, for example, to use a 100MiB
183 file as LUKS container, do something like this:
185 head -c 100M /dev/zero > luksfile # create empty file
186 losetup /dev/loop0 luksfile # map luksfile to /dev/loop0
187 cryptsetup luksFormat /dev/loop0 # create LUKS on loop device
189 Afterwards just use /dev/loop0 as a you would use a LUKS partition.
190 To unmap the file when done, use "losetup -d /dev/loop0".
193 * When I add a new key-slot to LUKS, it asks for a passphrase but
194 then complains about there not being a key-slot with that
197 That is as intended. You are asked a passphrase of an existing
198 key-slot first, before you can enter the passphrase for the new
199 key-slot. Otherwise you could break the encryption by just adding a
200 new key-slot. This way, you have to know the passphrase of one of
201 the already configured key-slots in order to be able to configure a
205 * Encrytion on top of RAID or the other way round?
207 Unless you have special needs, place encryption between RAID and
208 filesystem, i.e. encryption on top of RAID. You can do it the other
209 way round, but you have to be aware that you then need to give the
210 pasphrase for each individual disk and RAID autotetection will not
211 work anymore. Therefore it is better to encrypt the RAID device,
215 * How do I read a dm-crypt key from file?
217 Note that the file will still be hashed first, just like keyboard
218 input. Use the --key-file option, like this:
220 cryptsetup create --key-file keyfile e1 /dev/loop0
223 * How do I read a LUKS slot key from file?
225 What you really do here is to read a passphrase from file, just as
226 you would with manual entry of a passphrase for a key-slot. You can
227 add a new passphrase to a free key-slot, set the passphrase of an
228 specific key-slot or put an already configured passphrase into a
229 file. In the last case make sure no trailing newline (0x0a) is
230 contained in the key file, or the passphrase will not work because
231 the whole file is used as input.
233 To add a new passphrase to a free key slot from file, use something
236 cryptsetup luksAddKey /dev/loop0 keyfile
238 To add a new passphrase to a specific key-slot, use something like
241 cryptsetup luksAddKey --key-slot 7 /dev/loop0 keyfile
243 To supply a key from file to any LUKS command, use the --key-file
244 option, e.g. like this:
246 cryptsetup luksOpen --key-file keyfile /dev/loop0 e1
249 * How do I read the LUKS master key from file?
251 The question you should ask yourself first is why you would want to
252 do this. The only legitimate reason I can think of is if you want
253 to have two LUKS devices with the same master key. Even then, I
254 think it would be preferable to just use key-slots with the same
255 passphrase, or to use plain dm-crypt instead. If you really have a
256 good reason, please tell me. If I am convinced, I will add how to
260 * What are the security requirements for a key read from file?
262 A file-stored key or passphrase has the same security requirements
263 as one entered interactively, however you can use random bytes and
264 thereby use bytes you cannot type on the keyboard. You can use any
265 file you like as key file, for example a plain text file with a
266 human readable passphrase. To generate a file with random bytes,
267 use something like this:
269 head -c 256 /dev/random > keyfile
272 * If I map a journaled file system using dm-crypt/LUKS, does it still
273 provide its usual transactional guarantees?
275 As far as I know it does (but I may be wrong), but please note that
276 these "guarantees" are far weaker than they appear to be. For
277 example, you may not get a hard flush to disk surface even on a
278 call to fsync. In addition, the HDD itself may do independent
279 write reordering. Some other things can go wrong as well. The
280 filesystem developers are aware of these problems and typically
281 can make it work anyways. That said, dm-crypt/LUKS should not make
284 Personally, I have several instances of ext3 on dm-crypt and have
285 not noticed any specific problems.
287 Update: I did run into frequent small freezes (1-2 sec) when putting
288 a vmware image on ext3 over dm-crypt. This does indicate that the
289 transactional guarantees are in place, but at a cost. When I went
290 back to ext2, the problem went away. This also seems to have gotten
291 better with kernel 2.6.36 and the reworking of filesystem flush
292 locking. Kernel 2.6.38 is expected to have more improvements here.
295 * Can I use LUKS or cryptsetup with a more secure (external) medium
296 for key storage, e.g. TPM or a smartcard?
298 Yes, see the answers on using a file-supplied key. You do have to
299 write the glue-logic yourself though. Basically you can have
300 cryptsetup read the key from STDIN and write it there with your
301 own tool that in turn gets the key from the more secure key
305 * Can I resize a dm-crypt or LUKS partition?
307 Yes, you can, as neither dm-crypt nor LUKS stores partition size.
308 Whether you should is a different question. Personally I recommend
309 backup, recreation of the encrypted partition with new size,
310 recreation of the filesystem and restore. This gets around the
311 tricky business of resizing the filesystem. Resizing a dm-crypt or
312 LUKS container does not resize the filesystem in it. The backup is
313 really non-optional here, as a lot can go wrong, resulting in
314 partial or complete data loss. Using something like gparted to
315 resize an encrypted partition is slow, but typicaly works. This
316 will not change the size of the filesystem hidden under the
319 You also need to be aware of size-based limitations. The one
320 currently relevant is that aes-xts-plain should not be used for
321 encrypted container sizes larger than 2TiB. Use aes-xts-plain64
328 * My dm-crypt/LUKS mapping does not work! What general steps are
329 there to investigate the problem?
331 If you get a specific error message, investigate what it claims
332 first. If not, you may want to check the following things.
334 - Check that "/dev", including "/dev/mapper/control" is there. If it
335 is missing, you may have a problem with the "/dev" tree itself or
336 you may have broken udev rules.
338 - Check that you have the device mapper and the crypt target in your
339 kernel. The output of "dmsetup targets" should list a "crypt"
340 target. If it is not there or the command fails, add device mapper
341 and crypt-target to the kernel.
343 - Check that the hash-functions and ciphers you want to use are in
344 the kernel. The output of "cat /proc/crypto" needs to list them.
347 * My dm-crypt mapping suddenly stopped when upgrading cryptsetup.
349 The default cipher, hash or mode may have changed (the mode changed
350 from 1.0.x to 1.1.x). See under "Issues With Specific Versions of
354 * When I call cryptsetup from cron/CGI, I get errors about unknown
357 If you get errors about unknown parameters or the like that are not
358 present when cryptsetup is called from the shell, make sure you
359 have no older version of cryptsetup on your system that then gets
360 called by cron/CGI. For example some distributions install
361 cryptsetup into /usr/sbin, while a manual install could go to
362 /usr/local/sbin. As a debugging aid, call "cryptsetup --version"
363 from cron/CGI or the non-shell mechanism to be sure the right
367 * Unlocking a LUKS device takes very long. Why?
369 The iteration time for a key-slot (see Section 5 for an explanation
370 what iteration does) is calculated when setting a passphrase. By
371 default it is 1 second on the machine where the passphrase is set.
372 If you set a passphrase on a fast machine and then unlock it on a
373 slow machine, the unlocking time can be much longer. Also take into
374 account that up to 8 key-slots have to be tried in order to find the
377 If this is problem, you can add another key-slot using the slow
378 machine with the same passphrase and then remove the old key-slot.
379 The new key-slot will have an iteration count adjusted to 1 second
380 on the slow machine. Use luksKeyAdd and then luksKillSlot or
383 However, this operation will not change volume key iteration count
384 (MK iterations in output of "cryptsetup luksDump"). In order to
385 change that, you will have to backup the data in the LUKS
386 container (i.e. your encrypted data), luksFormat on the slow
387 machine and restore the data. Note that in the original LUKS
388 specification this value was fixed to 10, but it is now derived
389 from the PBKDF2 benchmark as well and set to iterations in 0.125
390 sec or 1000, whichever is larger. Also note that MK iterations
391 are not very security relevant. But as each key-slot already takes
392 1 second, spending the additional 0.125 seconds really does not
396 * "blkid" sees a LUKS UUID and an ext2/swap UUID on the same device.
399 Some old versions of cryptsetup have a bug where the header does
400 not get completely wiped during LUKS format and an older ext2/swap
401 signature remains on the device. This confuses blkid.
403 Fix: Wipe the unused header areas by doing a backup and restore of
404 the header with cryptsetup 1.1.x:
406 cryptsetup luksHeaderBackup --header-backup-file <file> <device>
407 cryptsetup luksHeaderRestore --header-backup-file <file> <device>
410 * cryptsetup segfaults on Gentoo amd64 hardened ...
412 There seems to be some inteference between the hardening and and
413 the way cryptsetup benchmarks PBKDF2. The solution to this is
414 currently not quite clear for an encrypted root filesystem. For
415 other uses, you can apparently specify USE="dynamic" as compile
416 flag, see http://bugs.gentoo.org/show_bug.cgi?id=283470
422 * Can a bad RAM module cause problems?
424 LUKS and dm-crypt can give the RAM quite a workout, especially when
425 combined with software RAID. In particular the combination RAID5 +
426 LUKS + XFS seems to uncover RAM problems that never caused obvious
427 problems before. Symptoms vary, but often the problem manifest
428 itself when copying large amounts of data, typically several times
429 larger than your main memory.
431 Side note: One thing you should always do on large data
432 copy/movements is to run a verify, for example with the "-d"
433 option of "tar" or by doing a set of MD5 checksums on the source
436 find . -type f -exec md5sum \{\} \; > checksum-file
438 and then a "md5sum -c checksum-file" on the other side. If you get
439 mismatches here, RAM is the primary suspect. A lesser suspect is
440 an overclocked CPU. I have found countless hardware problems in
441 verify runs after copying or making backups. Bit errors are much
442 more common than most people think.
444 Some RAM issues are even worse and corrupt structures in one of the
445 layers. This typically results in lockups, CPU state dumps in the
446 system logs, kernel panic or other things. It is quite possible to
447 have the problem with an encrypted device, but not with an
448 otherwise the same unencrypted device. The reason for that is that
449 encryption has an error amplification property: You flip one bit
450 in an encrypted data block, and the decrypted version has half of
451 its bits flipped. This is an important security property for modern
452 ciphers. With the usual modes in cryptsetup (CBC, ESSIV, XTS), you
453 get up to a completely changed 512 byte block per bit error. A
454 corrupt block causes a lot more havoc than the occasionally
455 flipped single bit and can result in various obscure errors.
457 Note, that a verify run on copying between encrypted or
458 unencrypted devices will reliably detect corruption, even when the
459 copying itself did not report any problems. If you find defect
460 RAM, assume all backups and copied data to be suspect, unless you
466 First you should know that overclocking often makes memory
467 problems worse. So if you overclock (which I strongly recommend
468 against in a system holding data that has some worth), run the
469 tests with the overclocking active.
471 There are two good options. One is Memtest86+ and the other is
472 "memtester" by Charles Cazabon. Memtest86+ requires a reboot and
473 then takes over the machine, while memtester runs from a
474 root-shell. Both use different testing methods and I have found
475 problems fast with each one that the other needed long to find. I
476 recommend running the following procedure until the first error is
479 - Run Memtest86+ for one cycle
481 - Run memterster for one cycle (shut down as many other applications
484 - Run Memtest86+ for 24h or more
486 - Run memtester for 24h or more
488 If all that does not produce error messages, your RAM may be sound,
489 but I have had one weak bit that Memtest86+ needed around 60 hours
490 to find. If you can reproduce the original problem reliably, a good
491 additional test may be to remove half of the RAM (if you have more
492 than one module) and try whether the problem is still there and if
493 so, try with the other half. If you just have one module, get a
494 different one and try with that. If you do overclocking, reduce
495 the settings to the most conservative ones available and try with
502 * Is LUKS insecure? Everybody can see I have encrypted data!
504 In practice it does not really matter. In most civilized countries
505 you can just refuse to hand over the keys, no harm done. In some
506 countries they can force you to hand over the keys, if they suspect
507 encryption. However the suspicion is enough, they do not have to
508 prove anything. This is for practical reasons, as even the presence
509 of a header (like the LUKS header) is not enough to prove that you
510 have any keys. It might have been an experiment, for example. Or it
511 was used as encrypted swap with a key from /dev/random. So they
512 make you prove you do not have encrypted data. Of course that is
513 just as impossible as the other way round.
515 This means that if you have a large set of random-looking data,
516 they can already lock you up. Hidden containers (encryption hidden
517 within encryption), as possible with Truecrypt, do not help
518 either. They will just assume the hidden container is there and
519 unless you hand over the key, you will stay locked up. Don't have
520 a hidden container? Though luck. Anybody could claim that.
522 Still, if you are concerned about the LUKS header, use plain
523 dm-crypt with a good passphrase. See also Section 2, "What is the
524 difference between "plain" and LUKS format?"
527 * Should I initialize (overwrite) a new LUKS/dm-crypt partition?
529 If you just create a filesystem on it, most of the old data will
530 still be there. If the old data is sensitive, you should overwrite
531 it before encrypting. In any case, not initializing will leave the
532 old data there until the specific sector gets written. That may
533 enable an attacker to determine how much and where on the
534 partition data was written. If you think this is a risk, you can
535 prevent this by overwriting the encrypted device (here assumed to
536 be named "e1") with zeros like this:
538 dd_rescue -w /dev/zero /dev/mapper/e1
540 or alternatively with one of the following more standard commands:
542 cat /dev/zero > /dev/mapper/e1
543 dd if=/dev/zero of=/dev/mapper/e1
546 * How do I securely erase a LUKS (or other) partition?
548 For LUKS, if you are in a desperate hurry, overwrite the LUKS
549 header and key-slot area. This means overwriting the first
550 (keyslots x stripes x keysize) + offset bytes. For the default
551 parameters, this is the 1'052'672 bytes, i.e. 1MiB + 4096 of the
552 LUKS partition. For 512 bit key length (e.g. for aes-xts-plain with
553 512 bit key) this is 2MiB. (The diferent offset stems from
554 differences in the sector alignment of the key-slots.) If in doubt,
555 just be generous and overwrite the first 10MB or so, it will likely
556 still be fast enough. A single overwrite with zeros should be
557 enough. If you anticipate being in a desperate hurry, prepare the
558 command beforehand. Example with /dev/sde1 as the LUKS partition
559 and default parameters:
561 head -c 1052672 /dev/zero > /dev/sde1; sync
563 A LUKS header backup or full backup will still grant access to
564 most or all data, so make sure that an attacker does not have
565 access to backups or destroy them as well.
567 If you have time, overwrite the whole LUKS partition with a single
568 pass of zeros. This is enough for current HDDs. For SSDs or FLASH
569 (USB sticks) you may want to overwrite the whole drive several
570 times to be sure data is not retained by wear leveling. This is
571 possibly still insecure as SSD technology is not fully understood
572 in this regard. Still, due to the anti-forensic properties of the
573 LUKS key-slots, a single overwrite of an SSD or FLASH drive could
574 be enough. If in doubt, use physical destruction in addition. Here
575 is a link to some current reseach results on erasing SSDs and FLASH
577 http://www.usenix.org/events/fast11/tech/full_papers/Wei.pdf
579 Keep in mind to also erase all backups.
581 Example for a zero-overwrite erase of partition sde1 done with
584 dd_rescue -w /dev/zero /dev/sde1
587 * How do I securely erase a backup of a LUKS partition or header?
589 That depends on the medium it is stored on. For HDD and SSD, use
590 overwrite with zeros. For an SSD or FLASH drive (USB stick), you
591 may want to overwrite the complete SSD several times and use
592 physical destruction in addition, see last item. For re-writable
593 CD/DVD, a single overwrite should also be enough, due to the
594 anti-forensic properties of the LUKS keyslots. For write-once
595 media, use physical destruction. For low security requirements,
596 just cut the CD/DVD into several parts. For high security needs,
597 shred or burn the medium. If your backup is on magnetic tape, I
598 advise physical destruction by shredding or burning, after
599 overwriting . The problem with magnetic tape is that it has a
600 higher dynamic range than HDDs and older data may well be
601 recoverable after overwrites. Also write-head alignment issues can
602 lead to data not actually being deleted at all during overwrites.
605 * What about backup? Does it compromise security?
607 That depends. See next section.
610 * Why is all my data permanently gone if I overwrite the LUKS header?
612 Overwriting the LUKS header in part or in full is the most common
613 reason why access to LUKS containers is lost permanently.
614 Overwriting can be done in a number of fashions, like creating a
615 new filesystem on the raw LUKS partition, making the raw partition
616 part of a raid array and just writing to the raw partition.
618 The LUKS header contains a 256 bit "salt" value and without that no
619 decryption is possible. While the salt is not secret, it is
620 key-grade material and cannot be reconstructed. This is a
621 cryptographically strong "cannot". From observations on the
622 cryptsetup mailing-list, people typically go though the usual
623 stages of grief (Denial, Anger, Bargaining, Depression, Acceptance)
624 when this happens to them. Observed times vary between 1 day and 2
625 weeks to complete the cycle. Seeking help on the mailing-list is
626 fine. Even if we usually cannot help with getting back your data,
627 most people found the feedback comforting.
629 If your header does not contain an intact salt, best go directly
630 to the last stage ("Acceptance") and think about what to do now.
631 There is one exception that I know of: If your LUKS container is
632 still open, then it may be possible to extract the master key from
633 the running system. See Item "How do I recover the master key from
634 a mapped LUKS container?" in Section "Backup and Data Recovery".
639 A salt is a random key-grade value added to the passphrase before
640 it is processed. It is not kept secret. The reason for using salts
641 is as follows: If an attacker wants to crack the password for a
642 single LUKS container, then every possible passphrase has to be
643 tried. Typically an attacker will not try every binary value, but
644 will try words and sentences from a dictionary.
646 If an attacker wants to attack several LUKS containers with the
647 same dictionary, then a different approach makes sense: Compute the
648 resulting slot-key for each dictionary element and store it on
649 disk. Then the test for each entry is just the slow unlocking with
650 the slot key (say 0.00001 sec) instead of calculating the slot-key
651 first (1 sec). For a single attack, this does not help. But if you
652 have more than one container to attack, this helps tremendously,
653 also because you can prepare your table before you even have the
654 container to attack! The calculation is also very simple to
655 parallelize. You could, for example, use the night-time unused CPU
656 power of your desktop PCs for this.
658 This is where the salt comes in. If the salt is combined with the
659 passphrase (in the simplest form, just appended to it), you
660 suddenly need a separate table for each salt value. With a
661 reasonably-sized salt value (256 bit, e.g.) this is quite
665 * Is LUKS secure with a low-entropy (bad) passphrase?
667 Note: You should only use the 94 printable characters from 7 bit
668 ASCII code to prevent your passphrase from failing when the
669 character encoding changes, e.g. because of a system upgrade, see
670 also the note at the very start of this FAQ under "WARNINGS".
672 This needs a bit of theory. The quality of your passphrase is
673 directly related to its entropy (information theoretic, not
674 thermodynamic). The entropy says how many bits of "uncertainty" or
675 "randomness" are in you passphrase. In other words, that is how
676 difficult guessing the passphrase is.
678 Example: A random English sentence has about 1 bit of entropy per
679 character. A random lowercase (or uppercase) character has about
682 Now, if n is the number of bits of entropy in your passphrase and t
683 is the time it takes to process a passphrase in order to open the
684 LUKS container, then an attacker has to spend at maximum
686 attack_time_max = 2^n * t
688 time for a successful attack and on average half that. There is no
689 way getting around that relationship. However, there is one thing
690 that does help, namely increasing t, the time it takes to use a
691 passphrase, see next FAQ item.
693 Still, if you want good security, a high-entropy passphrase is the
694 only option. Use at least 64 bits for secret stuff. That is 64
695 characters of English text (but only if randomly chosen) or a
696 combination of 12 truly random letters and digits.
698 For passphrase generation, do not use lines from very well-known
699 texts (religious texts, Harry potter, etc.) as they are to easy to
700 guess. For example, the total Harry Potter has about 1'500'000
701 words (my estimation). Trying every 64 character sequence starting
702 and ending at a word boundary would take only something like 20
703 days on a single CPU and is entirely feasible. To put that into
704 perspective, using a number of Amazon EC2 High-CPU Extra Large
705 instances (each gives about 8 real cores), this tests costs
706 currently about 50USD/EUR, but can be made to run arbitrarily fast.
708 On the other hand, choosing 1.5 lines from, say, the Wheel of Time
709 is in itself not more secure, but the book selection adds quite a
710 bit of entropy. (Now that I have mentioned it here, don't use tWoT
711 either!) If you add 2 or 3 typos or switch some words around, then
712 this is good passphrase material.
715 * What is "iteration count" and why is decreasing it a bad idea?
717 Iteration count is the number of PBKDF2 iterations a passphrase is
718 put through before it is used to unlock a key-slot. Iterations are
719 done with the explicit purpose to increase the time that it takes
720 to unlock a key-slot. This provides some protection against use of
721 low-entropy passphrases.
723 The idea is that an attacker has to try all possible passphrases.
724 Even if the attacker knows the passphrase is low-entropy (see last
725 item), it is possible to make each individual try take longer. The
726 way to do this is to repeatedly hash the passphrase for a certain
727 time. The attacker then has to spend the same time (given the same
728 computing power) as the user per try. With LUKS, the default is 1
729 second of PBKDF2 hashing.
731 Example 1: Lets assume we have a really bad passphrase (e.g. a
732 girlfriends name) with 10 bits of entropy. With the same CPU, an
733 attacker would need to spend around 500 seconds on average to
734 break that passphrase. Without iteration, it would be more like
735 0.0001 seconds on a modern CPU.
737 Example 2: The user did a bit better and has 32 chars of English
738 text. That would be about 32 bits of entropy. With 1 second
739 iteration, that means an attacker on the same CPU needs around 136
740 years. That is pretty impressive for such a weak passphrase.
741 Without the iterations, it would be more like 50 days on a modern
742 CPU, and possibly far less.
744 In addition, the attacker can both parallelize and use special
745 hardware like GPUs to speed up the attack. The attack can also
746 happen quite some time after the luksFormat operation and CPUs can
747 have become faster and cheaper. For that reason you want a bit
748 of extra security. Anyways, in Example 1 your are screwed. In
749 example 2, not necessarily. Even if the attack is faster, it still
750 has a certain cost associated with it, say 10000 EUR/USD with
751 iteration and 1 EUR/USD without iteration. The first can be
752 prohibitively expensive, while the second is something you try
753 even without solid proof that the decryption will yield something
756 The numbers above are mostly made up, but show the idea. Of course
757 the best thing is to have a high-entropy passphrase.
759 Would a 100 sec iteration time be even better? Yes and no.
760 Cryptographically it would be a lot better, namely 100 times better.
761 However, usability is a very important factor for security
762 technology and one that gets overlooked surprisingly often. For
763 LUKS, if you have to wait 2 minutes to unlock the LUKS container,
764 most people will not bother and use less secure storage instead. It
765 is better to have less protection against low-entropy passphrases
766 and people actually use LUKS, than having them do without
767 encryption altogether.
769 Now, what about decreasing the iteration time? This is generally a
770 very bad idea, unless you know and can enforce that the users only
771 use high-entropy passphrases. If you decrease the iteration time
772 without ensuring that, then you put your users at increased risk,
773 and considering how rarely LUKS containers are unlocked in a
774 typical work-flow, you do so without a good reason. Don't do it.
775 The iteration time is already low enough that users with entropy
776 low passphrases are vulnerable. Lowering it even further increases
777 this danger significantly.
780 * What about iteration count with plain dm-crypt?
782 Simple: There is none. There is also no salting. If you use plain
783 dm-crypt, the only way to be secure is to use a high entropy
784 passphrase. If in doubt, use LUKS instead.
787 * Is LUKS with default parameters less secure on a slow CPU?
789 Unfortunately, yes. However the only aspect affected is the
790 protection for low-entropy passphrase or master-key. All other
791 security aspects are independent of CPU speed.
793 The master key is less critical, as you really have to work at it
794 to give it low entropy. One possibility is to supply the master key
795 yourself. If that key is low-entropy, then you get what you
796 deserve. The other known possibility is to use /dev/urandom for
797 key generation in an entropy-startved situation (e.g. automatic
798 installation on an embedded device without network and other entropy
801 For the passphrase, don't use a low-entropy passphrase. If your
802 passphrase is good, then a slow CPU will not matter. If you insist
803 on a low-entropy passphrase on a slow CPU, use something like
804 "--iter-time=10" or higher and wait a long time on each LUKS unlock
805 and pray that the attacker does not find out in which way exactly
806 your passphrase is low entropy. This also applies to low-entropy
807 passphrases on fast CPUs. Technology can do only so much to
808 compensate for problems in front of the keyboard.
811 * Why was the default aes-cbc-plain replaced with aes-cbc-essiv?
813 The problem is that cbc-plain has a fingerprint vulnerability, where
814 a specially crafted file placed into the crypto-container can be
815 recognized from the outside. The issue here is that for cbc-plain
816 the initialization vector (IV) is the sector number. The IV gets
817 XORed to the first data chunk of the sector to be encrypted. If you
818 make sure that the first data block to be stored in a sector
819 contains the sector number as well, the first data block to be
820 encrypted is all zeros and always encrypted to the same ciphertext.
821 This also works if the first data chunk just has a constant XOR
822 with the sector number. By having several shifted patterns you can
823 take care of the case of a non-power-of-two start sector number of
826 This mechanism allows you to create a pattern of sectors that have
827 the same first ciphertext block and signal one bit per sector to the
828 outside, allowing you to e.g. mark media files that way for
829 recognition without decryption. For large files this is a
830 practical attack. For small ones, you do not have enough blocks to
831 signal and take care of different file starting offsets.
833 In order to prevent this attack, the default was changed to
834 cbc-essiv. ESSIV uses a keyed hash of the sector number, with the
835 encryption key as key. This makes the IV unpredictable without
836 knowing the encryption key and the watermarking attack fails.
839 * Are there any problems with "plain" IV? What is "plain64"?
841 First, "plain" and "plain64" are both not secure to use with CBC,
842 see previous FAQ item.
844 However there are modes, like XTS, that are secure with "plain" IV.
845 The next limit is that "plain" is 64 bit, with the upper 32 bit set
846 to zero. This means that on volumes larger than 2TiB, the IV
847 repeats, creating a vulnerability that potentially leaks some
848 data. To avoid this, use "plain64", which uses the full sector
849 number up to 64 bit. Note that "plain64" requires a kernel >=
850 2.6.33. Also note that "plain64" is backwards compatible for
851 volume sizes <= 2TiB, but not for those > 2TiB. Finally, "plain64"
852 does not cause any performance penalty compared to "plain".
855 * What about XTS mode?
857 XTS mode is potentially even more secure than cbc-essiv (but only if
858 cbc-essiv is insecure in your scenario). It is a NIST standard and
859 used, e.g. in Truecrypt. At the moment, if you want to use it, you
860 have to specify it manually as "aes-xts-plain", i.e.
862 cryptsetup -c aes-xts-plain luksFormat <device>
864 For volumes >2TiB and kernels >= 2.6.33 use "plain64" (see FAQ
865 item on "plain" and "plain64"):
867 cryptsetup -c aes-xts-plain64 luksFormat <device>
869 There is a potential security issue with XTS mode and large blocks.
870 LUKS and dm-crypt always use 512B blocks and the issue does not
874 6. Backup and Data Recovery
877 * Why do I need Backup?
879 First, disks die. The rate for well-treated (!) disk is about 5%
880 per year, which is high enough to worry about. There is some
881 indication that this may be even worse for some SSDs. This applies
882 both to LUKS and plain dm-crypt partitions.
884 Second, for LUKS, if anything damages the LUKS header or the
885 key-stripe area then decrypting the LUKS device can become
886 impossible. This is a frequent occuurence. For example an
887 accidental format as FAT or some software overwriting the first
888 sector where it suspects a partition boot sector typically makes a
889 LUKS partition permanently inacessible. See more below on LUKS
892 So, data-backup in some form is non-optional. For LUKS, you may
893 also want to store a header backup in some secure location. This
894 only needs an update if you change passphrases.
897 * How do I backup a LUKS header?
899 While you could just copy the appropriate number of bytes from the
900 start of the LUKS partition, the best way is to use command option
901 "luksHeaderBackup" of cryptsetup. This protects also against
902 errors when non-standard parameters have been used in LUKS
903 partition creation. Example:
906 cryptsetup luksHeaderBackup --header-backup-file h /dev/mapper/c1
908 To restore, use the inverse command, i.e.
910 cryptsetup luksHeaderRestore --header-backup-file h /dev/mapper/c1
913 * How do I backup a LUKS or dm-crypt partition?
915 There are two options, a sector-image and a plain file or
916 filesystem backup of the contents of the partition. The sector
917 image is already encrypted, but cannot be compressed and contains
918 all empty space. The filesystem backup can be compressed, can
919 contain only part of the encrypted device, but needs to be
920 encrypted separately if so desired.
922 A sector-image will contain the whole partition in encrypted form,
923 for LUKS the LUKS header, the keys-slots and the data area. It can
924 be done under Linux e.g. with dd_rescue (for a direct image copy)
925 and with "cat" or "dd". Example:
927 cat /dev/sda10 > sda10.img
928 dd_rescue /dev/sda10 sda10.img
930 You can also use any other backup software that is capable of making
931 a sector image of a partition. Note that compression is
932 ineffective for encrypted data, hence it does not make sense to
935 For a filesystem backup, you decrypt and mount the encrypted
936 partition and back it up as you would a normal filesystem. In this
937 case the backup is not encrypted, unless your encryption method
938 does that. For example you can encrypt a backup with "tar" as
941 tar cjf - <path> | gpg --cipher-algo AES -c - > backup.tbz2.gpg
943 And verify the backup like this if you are at "path":
945 cat backup.tbz2.gpg | gpg - | tar djf -
947 Note: Allways verify backups, especially encrypted ones.
949 In both cases GnuPG will ask you interactively for your symmetric
950 key. The verify will only output errors. Use "tar dvjf -" to get
951 all comparison results. To make sure no data is written to disk
952 unencrypted, turn off swap if it is not encrypted before doing the
955 You can of course use different or no compression and you can use
956 an asymmetric key if you have one and have a backup of the secret
957 key that belongs to it.
959 A second option for a filestem-level backup that can be used when
960 the backup is also on local disk (e.g. an external USB drive) is
961 to use a LUKS container there and copy the files to be backed up
962 between both mounted containers. Also see next item.
965 * Do I need a backup of the full partition? Would the header and
966 key-slots not be enough?
968 Backup protects you against two things: Disk loss or corruption
969 and user error. By far the most questions on the dm-crypt mailing
970 list about how to recover a damaged LUKS partition are related
971 to user error. For example, if you create a new filesystem on a
972 LUKS partition, chances are good that all data is lost
975 For this case, a header+key-slot backup would often be enough. But
976 keep in mind that a well-treated (!) HDD has roughly a failure
977 risk of 5% per year. It is highly advisable to have a complete
978 backup to protect against this case.
981 * *What do I need to backup if I use "decrypt_derived"?
983 This is a script in Debian, intended for mounting /tmp or swap with
984 a key derived from the master key of an already decrypted device.
985 If you use this for an device with data that should be persistent,
986 you need to make sure you either do not lose access to that master
987 key or have a backup of the data. If you derive from a LUKS
988 device, a header backup of that device would cover backing up the
989 master key. Keep in mind that this does not protect against disk
992 Note: If you recreate the LUKS header of the device you derive from
993 (using luksFormat), the master key changes even if you use the same
994 passphrase(s) and you will not be able to decrypt the derived
995 device with the new LUKS header.
998 * Does a backup compromise security?
1000 Depends on how you do it. However if you do not have one, you are
1001 going to eventually lose your encrypted data.
1003 There are risks introduced by backups. For example if you
1004 change/disable a key-slot in LUKS, a binary backup of the partition
1005 will still have the old key-slot. To deal with this, you have to
1006 be able to change the key-slot on the backup as well, securely
1007 erase the backup or do a filesystem-level backup instead of a binary
1010 If you use dm-crypt, backup is simpler: As there is no key
1011 management, the main risk is that you cannot wipe the backup when
1012 wiping the original. However wiping the original for dm-crypt
1013 should consist of forgetting the passphrase and that you can do
1014 without actual access to the backup.
1016 In both cases, there is an additional (usually small) risk with
1017 binary backups: An attacker can see how many sectors and which
1018 ones have been changed since the backup. To prevent this, use a
1019 filesystem level backup methid that encrypts the whole backup in
1020 one go, e.g. as described above with tar and GnuPG.
1022 My personal advice is to use one USB disk (low value data) or
1023 three disks (high value data) in rotating order for backups, and
1024 either use independent LUKS partitions on them, or use encrypted
1025 backup with tar and GnuPG.
1027 If you do network-backup or tape-backup, I strongly recommend to
1028 go the filesystem backup path with independent encryption, as you
1029 typically cannot reliably delete data in these scenarios,
1030 especially in a cloud setting. (Well, you can burn the tape if it
1031 is under your control...)
1034 * What happens if I overwrite the start of a LUKS partition or damage
1035 the LUKS header or key-slots?
1037 There are two critical components for decryption: The salt values
1038 in the header itself and the key-slots. If the salt values are
1039 overwritten or changed, nothing (in the cryptographically strong
1040 sense) can be done to access the data, unless there is a backup
1041 of the LUKS header. If a key-slot is damaged, the data can still
1042 be read with a different key-slot, if there is a remaining
1043 undamaged and used key-slot. Note that in order to make a key-slot
1044 unrecoverable in a cryptographically strong sense, changing about
1045 4-6 bits in random locations of its 128kiB size is quite enough.
1048 * What happens if I (quick) format a LUKS partition?
1050 I have not tried the different ways to do this, but very likely you
1051 will have written a new boot-sector, which in turn overwrites the
1052 LUKS header, including the salts, making your data permanently
1053 irretrivable, unless you have a LUKS header backup. You may also
1054 damage the key-slots in part or in full. See also last item.
1057 * How do I recover the master key from a mapped LUKS container?
1059 This is typically only needed if you managed to damage your LUKS
1060 header, but the container is still mapped, i.e. "luksOpen"ed.
1062 WARNING: This exposes the master key of the LUKS container. Note
1063 that both ways to recreate a LUKS header with the old master key
1064 described below will write the master key to disk. Unless you are
1065 sure you have securely erased it afterwards, e.g. by writing it to
1066 an encrypted partition, RAM disk or by erasing the filesystem you
1067 wrote it to by a complete overwrite, you should change the master
1068 key afterwards. Changing the master key requires a full data
1069 backup, luksFormat and then restore of the backup.
1071 First, there is a script by Milan that tries to automatize the
1072 whole process, including generating a new LUKS header with the old
1075 http://code.google.com/p/cryptsetup/source/browse/trunk/misc/luks-header-from-active
1077 You can also do this manually. Here is how:
1079 - Get the master key from the device mapper. This is done by the
1080 following command. Substitute c5 for whatever you mapped to:
1082 # dmsetup table --target crypt --showkey /dev/mapper/c5
1084 0 200704 crypt aes-cbc-essiv:sha256
1085 a1704d9715f73a1bb4db581dcacadaf405e700d591e93e2eaade13ba653d0d09
1088 The result is actually one line, wrapped here for clarity. The long
1089 hex string is the master key.
1091 - Convert the master key to a binary file representation. You can
1092 do this manually, e.g. with hexedit. You can also use the tool
1093 "xxd" from vim like this:
1095 echo "a1704d9....53d0d09" | xxd -r -p > master_key
1097 - Do a luksFormat to create a new LUKS header. Unmapthe device
1098 before you do that (luksClose). Replace \dev\dsa10 with the device
1099 the LUKS container is on:
1101 cryptsetup luksFormat --master-key-file=master_key \dev\sda10
1103 Note that if the container was created with other than the default
1104 settings of the cryptsetup version you are using, you need to give
1105 additional parameters specifying the deviations. If in doubt, just
1106 do the first step, keep the whole result safe and try with the
1107 script by Milan. It does recover the other parameters as well.
1109 Side note: This is the way the decrypt_derived script gets at the
1110 master key. It just omits the conversion and hashes the master key
1114 * What does the on-disk structure of dm-crypt look like?
1116 There is none. dm-crypt takes a block device and gives encrypted
1117 access to each of its blocks with a key derived from the passphrase
1118 given. If you use a cipher different than the default, you have to
1119 specify that as a parameter to cryptsetup too. If you want to
1120 change the password, you basically have to create a second
1121 encrypted device with the new passphrase and copy your data over.
1122 On the plus side, if you accidentally overwrite any part of a
1123 dm-crypt device, the damage will be limited to the are you
1127 * What does the on-disk structure of LUKS look like?
1129 A LUKS partition consists of a header, followed by 8 key-slot
1130 descriptors, followed by 8 key slots, followed by the encrypted
1133 Header and key-slot descriptors fill the first 592 bytes. The
1134 key-slot size depends on the creation parameters, namely on the
1135 number of anti-forensic stripes, key material offset and master
1138 With the default parameters, each key-slot is a bit less than
1139 128kiB in size. Due to sector alignment of the key-slot start,
1140 that means the key block 0 is at offset 0x1000-0x20400, key
1141 block 1 at offset 0x21000-0x40400, and key block 7 at offset
1142 0xc1000-0xe0400. The space to the next full sector address is
1143 padded with zeros. Never used key-slots are filled with what the
1144 disk originally contained there, a key-slot removed with
1145 "luksRemoveKey" or "luksKillSlot" gets filled with 0xff. Start of
1146 bulk data is at 0x101000, i.e. at 1'052'672 bytes, i.e. at 1MiB
1147 + 4096 bytes from the start of the partition. This is also the
1148 value given by command "luksDump" with "Payload offset: 2056",
1149 just multiply by the sector size (512 bytes). Incidentally,
1150 "luksHeaderBackup" for a LUKS container created with default
1151 parameters dumps exactly the first 1'052'672 bytes to file and
1152 "luksHeaderRestore" restores them.
1154 For non-default parameters, you have to figure out placement
1155 yourself. "luksDump" helps. For the most common non-default
1156 settings, namely aes-xts-plain with 512 bit key, the offsets are:
1157 1st keyslot 0x1000-0x3f800, 2nd keyslot 0x40000-0x7e000, 3rd
1158 keyslot 0x7e000-0xbd800, ..., and start of bulk data at 0x200000.
1160 The exact specification of the format is here:
1161 http://code.google.com/p/cryptsetup/wiki/Specification
1164 * I think this is overly complicated. Is there an alternative?
1166 Not really. Encryption comes at a price. You can use plain
1167 dm-crypt to simplify things a bit. It does not allow multiple
1168 passphrases, but on the plus side, it has zero on disk description
1169 and if you overwrite some part of a plain dm-crypt partition,
1170 exactly the overwritten parts are lost (rounded up to sector
1174 7. Interoperability with other Disk Encryption Tools
1177 * What is this section about?
1179 Cryptsetup for plain dm-crypt can be used to access a number of
1180 on-disk formats created by tools like loop-aes patched into
1181 losetup. This somtimes works and sometimes does not. This section
1182 collects insights into what works, what does not and where more
1183 information is required.
1185 Additional information may be found in the mailing-list archives,
1186 mentioned at the start of this FAQ document. If you have a
1187 solution working that is not yet documented here and think a wider
1188 audience may be intertested, please email the FAQ maintainer.
1191 * loop-aes: General observations.
1193 One problem is that there are different versions of losetup around.
1194 loop-aes is a patch for losetup. Possible problems and deviations
1195 from cryptsetup option syntax include:
1197 - Offsets specifed in bytes (cryptsetup: 512 byte sectors)
1199 - The need to specify an IV offset
1201 - Encryption mode needs specifying (e.g. "-c twofish-cbc-plain")
1203 - Key size needs specifying (e.g. "-s 128" for 128 bit keys)
1205 - Passphrase hash algorithm needs specifying
1207 Also note that because plain dm-crypt and loop-aes format does not
1208 have metadata, autodetection, while feasible in most cases, would
1209 be a lot of work that nobody really wants to do. If you still have
1210 the old set-up, using a verbosity option (-v) on mapping with the
1211 old tool or having a look into the system logs after setup could
1212 give you the information you need.
1215 * loop-aes patched into losetup on debian 5.x, kernel 2.6.32
1217 In this case, the main problem seems to be that this variant of
1218 losetup takes the offset (-o option) in bytes, while cryptsetup
1219 takes it in sectors of 512 bytes each. Example: The losetupp
1222 losetup -e twofish -o 2560 /dev/loop0 /dev/sdb1
1223 mount /dev/loop0 mountpoint
1227 cryptsetup create -c twofish -o 5 --skip 5 e1 /dev/sdb1
1228 mount /dev/mapper/e1 mountpoint
1231 * loop-aes with 160 bit key
1233 This seems to be sometimes used with twofish and blowfish and
1234 represents a 160 bit ripemed160 hash output padded to 196 bit key
1235 length. It seems the corresponding options for cryptsetup are
1237 --cipher twofish-cbc-null -s 192 -h ripemd160:20
1240 8. Issues with Specific Versions of cryptsetup
1243 * When using the create command for plain dm-crypt with cryptsetup
1244 1.1.x, the mapping is incompatible and my data is not accessible
1247 With cryptsetup 1.1.x, the distro maintainer can define different
1248 default encryption modes for LUKS and plain devices. You can check
1249 these compiled-in defaults using "cryptsetup --help". Moreover, the
1250 plain device default changed because the old IV mode was
1251 vulnerable to a watermarking attack.
1253 If you are using a plain device and you need a compatible mode, just
1254 specify cipher, key size and hash algorithm explicitly. For
1255 compatibility with cryptsetup 1.0.x defaults, simple use the
1258 cryptsetup create -c aes-cbc-plain -s 256 -h ripemd160 <name> <dev>
1260 LUKS stores cipher and mode in the metadata on disk, avoiding this
1264 * cryptsetup on SLED 10 has problems...
1266 SLED 10 is missing an essential kernel patch for dm-crypt, which
1267 is broken in its kernel as a result. There may be a very old
1268 version of cryptsetup (1.0.x) provided by SLED, which should also
1269 not be used anymore as well. My advice would be to drop SLED 10.
1271 A. Contributors In no particular order: