8 6. Backup and Data Recovery
9 7. Issues with Specific Versions of cryptsetup
18 This is the FAQ (Frequently Asked Questions) for cryptsetup. It
19 covers Linux disk encryption with plain dm-crypt (one passphrase,
20 no management, no descriptor on disk) and LUKS (multiple user keys
21 with one master key, anti-forensics, descriptor block at start of
22 device, ...). The latest version should usually be available at
23 http://code.google.com/p/cryptsetup/wiki/FrequentlyAskedQuestions
25 ATTENTION: If you are going to read just one thing, make it the
26 section on Backup and Data Recovery. By far the most questions on
27 the cryptsetup mailing list are from people that just managed to
28 somehow format or overwrite the start of their LUKS partitions. In
29 most cases, there is nothing that can be done to help these poor
30 souls recover their data. Make sure you understand the problem and
31 limitations imposed by the LUKS security model BEFORE you face such
37 Current FAQ maintainer is Arno Wagner <arno@wagner.name>. Other
38 contributors are listed at the end. If you want to contribute, send
39 your article, including a descriptive headline, to the maintainer,
40 or the dm-crypt mailing list with something like "FAQ ..." in the
41 subject. Please note that by contributing to this FAQ, you accept
42 the license described below.
44 This work is under the "Attribution-Share Alike 3.0 Unported"
45 license, which means distribution is unlimited, you may create
46 derived works, but attributions to original authors and this
47 license statement must be retained and the derived work must be
48 under the same license. See
49 http://creativecommons.org/licenses/by-sa/3.0/ for more details of
52 Side note: I did text license research some time ago and I think
53 this license is best suited for the purpose at hand and creates the
57 * Where is the project website?
59 There is the project website at http://code.google.com/p/cryptsetup/
60 Please do not post questions there, nobody will read them. Use
61 the mailing-list instead.
64 * Is there a mailing-list?
66 Instructions on how to subscribe to the mailing-list are at on the
67 project website. People are generally helpful and friendly on the
70 The question of how to unsubscribe from the list does crop up
71 sometimes. For this you need your list management URL, which is
72 sent to you initially and once at the start of each month. Go to
73 the URL mentioned in the email and select "unsubscribe". This page
74 also allows you to request a password reminder.
76 Alternatively, you can send an Email to dm-crypt-request@saout.de
77 with just the word "help" in the subject or message body. Make sure
78 to send it from your list address.
84 * Can I encrypt an already existing, non-empty partition to use LUKS?
86 There is no converter, and it is not really needed. The way to do
87 this is to make a backup of the device in question, securely wipe
88 the device (as LUKS device initialization does not clear away old
89 data), do a luksFormat, optionally overwrite the encrypted device,
90 create a new filesystem and restore your backup on the now
91 encrypted device. Also refer to sections "Security Aspects" and
92 "Backup and Data Recovery".
94 For backup, plain GNU tar works well and backs up anything likely
95 to be in a filesystem.
98 * How do I use LUKS with a loop-device?
100 Just the same as with any block device. If you want, for example,
101 to use a 100MiB file as LUKS container, do something like this:
103 head -c 100M /dev/zero > luksfile # create empty file
104 losetup /dev/loop0 luksfile # map luksfile to /dev/loop0
105 cryptsetup luksFormat /dev/loop0 # create LUKS on loop device
107 Afterwards just use /dev/loop0 as a you would use a LUKS partition.
108 To unmap the file when done, use "losetup -d /dev/loop0".
111 * When I add a new key-slot to LUKS, it asks for a passphrase but
112 then complains about there not being a key-slot with that
115 That is as intended. You are asked a passphrase of an existing
116 key-slot first, before you can enter the passphrase for the new
117 key-slot. Otherwise you could break the encryption by just adding a
118 new key-slot. This way, you have to know the passphrase of one of
119 the already configured key-slots in order to be able to configure a
123 * How do I read a dm-crypt key from file?
125 Note that the file will still be hashed first, just like keyboard
126 input. Use the --key-file option, like this:
128 cryptsetup create --key-file keyfile e1 /dev/loop0
131 * How do I read a LUKS slot key from file?
133 What you really do here is to read a passphrase from file, just as
134 you would with manual entry of a passphrase for a key-slot. You can
135 add a new passphrase to a free key-slot, set the passphrase of an
136 specific key-slot or put an already configured passphrase into a
137 file. In the last case make sure no trailing newline (0x0a) is
138 contained in the key file, or the passphrase will not work because
139 the whole file is used as input.
141 To add a new passphrase to a free key slot from file, use something
144 cryptsetup luksAddKey /dev/loop0 keyfile
146 To add a new passphrase to a specific key-slot, use something like
149 cryptsetup luksAddKey --key-slot 7 /dev/loop0 keyfile
151 To supply a key from file to any LUKS command, use the --key-file
152 option, e.g. like this:
154 cryptsetup luksOpen --key-file keyfile /dev/loop0 e1
157 * How do I read the LUKS master key from file?
159 The question you should ask yourself first, is why you would want
160 to do this. The only legitimate reason I can think of is if you
161 want to have two LUKS devices with the same master key. Even then,
162 I think it would be preferable to just use key-slots with the same
163 passphrase, or to use plain dm-crypt instead. If you really have a
164 good reason, please tell me. If I am convinced, I will add how to
168 * What are the security requirements for a key read from file?
170 A file-stored key or passphrase has the same security requirements
171 as one entered interactively, however you can use random bytes and
172 thereby use bytes you cannot type on the keyboard. You can use any
173 file you like as key file, for example a plain text file with a
174 human readable passphrase. To generate a file with random bytes,
175 use something like this:
177 head -c 256 /dev/random > keyfile
180 * If I map a journaled file system using dm-crypt/LUKS, does it still
181 provide its usual transactional guarantees?
183 As far as I know it does (but I may be wrong), but please note that
184 these "guarantees" are far weaker than they appear to be. For
185 example, you not not get a hard flush to disk surface even on a
186 call to fsync. In addition, the HDD itself may do independent
187 write reordering. Some other things can go wrong as well. The
188 filesystem developers are aware of these problems and typically
189 can make it work anyways. That said, dm-crypt/LUKS should not make
192 Personally, I have several instances of ext3 on dm-crypt and have
193 not noticed any specific problems.
195 Update: I did run into frequent small freezes (1-2 sec) when putting
196 a vmware image on ext3 over dm-crypt. This does indicate that the
197 transactional guarantees are in place, but at a cost. When I went
198 back to ext2, the problem went away. This also seems to have gotten
199 better with kernel 2.6.36 and the reworking of filesystem flush
200 locking. Kernel 2.6.37 is expected to improve this even further.
203 * Can I use LUKS or cryptsetup with a more secure (external) medium
204 for key storage, e.g. TPM or a smartcard?
206 Yes, see the answers on using a file-supplied key. You do have to
207 write the glue-logic yourself though. Basically you can have
208 cryptsetup read the key from STDIN and write it there with your
209 own tool that in turn gets the key from the more secure key
213 * Can I resize a dm-crypt or LUKS partition?
215 Yes, you can, as neither dm-crypt nor LUKS stores partition size.
216 Whether you should is a different question. Personally I recommend
217 backup, recreation of the encrypted partition with new size,
218 recreation of the filesystem and restore. This gets around the
219 tricky business of resizing the filesystem. The backup is really
220 non-optional here, as a lot can go wrong, resulting in partial or
221 complete data loss. Using something like gparted to resize an
222 encrypted partition is slow, but pretty safe and should be fine.
223 This will not change the size of the filesystem hidden under the
226 You also need to be aware of size-based limitations. The one
227 currently relevant is that aes-xts-plain should not be used for
228 encrypted container sizes larger than 2TiB. Use aes-xts-plain64
235 * My dm-crypt/LUKS mapping does not work! What general steps are
236 there to investigate the problem?
238 If you get a specific error message, investigate what it claims
239 first. If not, you may want to check the following things.
241 - Check that "/dev", including "/dev/mapper/control" is there. If it
242 is missing, you may have a problem with the "/dev" tree itself or
243 you may have broken udev rules.
245 - Check that you have the device mapper and the crypt target in your
246 kernel. The output of "dmsetup targets" should list a "crypt"
247 target. If it is not there or the command fails, add device mapper
248 and crypt-target to the kernel.
250 - Check that the hash-functions and ciphers you want to use are in
251 the kernel. The output of "cat /proc/crypto" needs to list them.
254 * My dm-crypt mapping suddenly stopped when upgrading cryptsetup.
256 The default cipher, hash or mode may have changed (the mode changed
257 from 1.0.x to 1.1.x). See under "Issues With Specific Versions of
261 * When I call cryptsetup from cron/CGI, I get errors about unknown
264 If you get errors about unknown parameters or the like that are not
265 present when cryptsetup is called from the shell, make sure you
266 have no older version of cryptsetup on your system that then gets
267 called by cron/CGI.For example some distributions install
268 cryptsetup into /usr/sbin, while a manual install could go to
269 /usr/local/sbin. As a debugging aid, call "cryptsetup --version"
270 from cron/CGI or the non-shell mechanism to be sure you have the
274 * Unlocking a LUKS device takes very long. Why?
276 The iteration time for a key-slot (see Section 5 for an explanation
277 what iteration does) is calculated when setting a passphrase. By
278 default it is 1 second on the machine where the passphrase is set.
279 If you set a passphrase on a fast machine and then unlock it on a
280 slow machine, the unlocking time can be much longer. Also take into
281 account that up to 8 key-slots have to be tried in order to find the
284 If this is problem, you can add another key-slot using the slow
285 machine with the same passphrase and then remove the old key-slot.
286 The new key-slot will have an iteration count adjusted to 1 second
287 on the slow machine. Use luksKeyAdd and then luksKillSlot or
290 However, this operation will not change volume key iteration count
291 (MK iterations in output of "cryptsetup luksDump"). In order to
292 change that, you will have to backup the data in the LUKS
293 container, luksFormat on the slow machine and restore the data.
294 Note that in the original LUKS specification this value was fixed
295 to 10, but it is now derived from the PBKDF2 benchmark as well and
296 set to iterations in 0.125 sec or 1000, whichever is larger.
299 * "blkid" sees a LUKS UUID and an ext2/swap UUID on the same device.
302 Some old versions of cryptsetup have a bug where the header does
303 not get completely wiped during LUKS format and an older ext2/swap
304 signature remains on the device. This confuses blkid.
306 Fix: Wipe the unused header areas by doing a backup and restore of
307 the header with cryptsetup 1.1.x:
309 cryptsetup luksHeaderBackup --header-backup-file <file> <device>
310 cryptsetup luksHeaderRestore --header-backup-file <file> <device>
312 If you cannot use a 1.1.x cryptsetup, you can also do a manual wipe
313 of the area in question with the command below. Be very, VERY,
314 careful and make sure to do a backup of the header before. If you
315 get this wrong, your device may become permanently inaccessible.
317 dd if=/dev/zero of=<device> bs=512 seek=2 count=6
320 * cryptsetup segfaults on Gentoo amd64 hardened ...
322 There seems to be some inteference between the hardening and and
323 the way cryptsetup benchmarks PBKDF2. The solution to this is
324 currently not quite clear for an encrypted root filesystem. For
325 other uses, you can apparently specify USE="dynamic" as compile
326 flag, see http://bugs.gentoo.org/show_bug.cgi?id=283470
332 * Can a bad RAM module cause problems?
334 LUKS and dm-crypt can give the RAM quite a workout, especially when
335 combined with software RAID. In particular the combination RAID5 +
336 LUKS + XFS seems to uncover RAM problems that never caused obvious
337 problems before. Symptoms vary, but often the problem manifest
338 itself when copying large amounts of data, typically several times
339 larger than your main memory.
341 Side note: One thing you should always do on large data movements is
342 to run a verify, for example with the "-d" option of "tar" or by
343 doing a set of MD5 checksums on the source or target with
345 find . -type f -exec md5sum \{\} \; > checksum-file
347 and then a "md5sum -c checksum-file" on the other side. If you get
348 mismatches here, RAM is the primary suspect. A lesser suspect is
349 an overclocked CPU. I have found countless hardware problems in
350 verify runs after copying or making backups. Bit errors are much
351 more common than most people think.
353 Some RAM issues are even worse and corrupt structures in one of the
354 layers. This typically results in lockups, CPU state dumps in the
355 system logs, kernel panic or other things. It is quite possible to
356 have the problem with an encrypted device, but not with an
357 otherwise the same unencrypted device. The reason for that is that
358 encryption has an error amplification property: You flip one bit
359 in an encrypted data block, and the decrypted version has half of
360 its bits flipped. This is an important security property for modern
361 ciphers. With the usual modes in cryptsetup (CBC, ESSIV, XTS), you
362 get up to a completely changed 512 byte block per bit error. A
363 corrupt block causes a lot more havoc than the occasionally
364 flipped single bit and can result various obscure errors.
366 Note however that a verify run on copying between encrypted or
367 unencrypted devices can also show you corruption when the copying
368 itself did not report any problems. If you find defect RAM, assume
369 all backups and copied data to be suspect, unless you did a verify.
374 First you should know that overclocking often makes memory problems
375 worse. So if you overclock (which I strongly recommend against in a
376 system holding data that has some worth), run the tests with the
379 There are two good options. One is Memtest86+ and the other is
380 "memtester" by Charles Cazabon. Memtest86+ requires a reboot and
381 then takes over the machine, while memtester runs from a
382 root-shell. Both use different testing methods and I have found
383 problems fast with each one that the other needed long to find. I
384 recommend running the following procedure until the first error is
387 - Run Memtest86+ for one cycle
389 - Run memterster for one cycle (shut down as many other applications
392 - Run Memtest86+ for 24h or more
394 - Run memtester for 24h or more
396 If all that does not produce error messages, your RAM may be sound,
397 but I have had one weak bit that Memtest86+ needed around 60 hours
398 to find. If you can reproduce the original problem reliably, a good
399 additional test may be to remove half of the RAM (if you have more
400 than one module) and try whether the problem is still there and if
401 so, try with the other half. If you just have one module, get a
402 different one and try with that. If you do overclocking, reduce
403 the settings to the most conservative ones available and try with
410 * Should I initialize (overwrite) a new LUKS/dm-crypt partition?
412 If you just create a filesystem on it, most of the old data will
413 still be there. If the old data is sensitive, you should overwrite
414 it before encrypting. In any case, not initializing will leave the
415 old data there until the specific sector gets written. That may
416 enable an attacker to determine how much and where on the
417 partition data was written. If you think this is a risk, you can
418 prevent this by overwriting the encrypted device (here assumed to
419 be named "e1") with zeros like this:
421 dd_rescue -w /dev/zero /dev/mapper/e1
423 or alternatively with one of the following more standard commands:
425 cat /dev/zero > /dev/mapper/e1
426 dd if=/dev/zero of=/dev/mapper/e1
429 * How do I securely erase a LUKS (or other) partition?
431 For LUKS, if you are in a desperate hurry, overwrite the first few
432 kilobytes of the LUKS partition. This erases the master key salt
433 and makes access impossible. However a LUKS header backup or full
434 backup will still grant access to most or all data, so make sure
435 that an attacker does not have access to backups or destroy them as
438 To do this right, overwrite the whole LUKS partition with a single
439 pass of zeros. This is enough for current HDDs. For SSDs you may
440 want to erase the whole drive several times to be sure data is not
441 retained by wear leveling. This is possibly still insecure as SSD
442 technology is not fully understood in this regard. Still, due to
443 the anti-forensic properties of the LUKS key-slots, a single
444 overwrite of an SSD could be enough. If in doubt, use physical
445 destruction in addition. Keep in mind to also erase all backups.
447 Example for a zero-overwrite erase of partition sda10 done with
450 dd_rescue -w /dev/zero /dev/sda10
453 * How do I securely erase a backup of a LUKS partition or header?
455 That depends on the medium it is stored on. For HDD and SSD, use
456 overwrite with zeros. For an SSD, you may want to overwrite the
457 complete SSD several times and use physical destruction in addition,
458 see last item. Treat USB flash drives the same as SSDs. For
459 re-writable CD/DVD, a single overwrite should also be enough, due
460 to the anti-forensic properties of the LUKS keyslots. For
461 write-once media, use physical destruction. For low security
462 requirements, just cut the CD/DVD into several parts. For high
463 security needs, shred or burn the medium. If your backup is on
464 magnetic tape, I advise physical destruction by shredding or
465 burning. The problem with magnetic tape is that it has a higher
466 dynamic range than HDDs and older data may well be recoverable
467 after overwrites. Also write-head alignment issues can lead to
468 data not actually being deleted at all during overwrites.
471 * What about backup? Does it compromise security?
473 That depends. See next section.
476 * Why is all my data gone if I overwrite the LUKS header?
478 Overwriting the LUKS header in part or in full is the most common
479 reason why access to LUKS containers is lost permanently.
480 Overwriting can be done in a number of fashions, like creating a
481 new filesystem on the raw LUKS partition, making the raw partition
482 part of a raid array and just writing to the raw partition.
484 The LUKS header contains a 256 bit "salt" value and without that no
485 decryption is possible. While the salt is not secret, it is
486 key-grade material and cannot be reconstructed. This is a
487 cryptographically strong "cannot". From observations on the
488 cryptsetup mailing-list, people typically go though the usual
489 stages of grief (Denial, Anger, Bargaining, Depression, Acceptance)
490 when this happens to them. Observed times vary between 1 day and 2
491 weeks to complete the cycle. Seeking help on the mailing-list is
492 fine. Even if we usually cannot help with getting back your data,
493 most people found the feedback comforting.
495 If your header does not contain an intact salt, best go directly
496 to the last one ("Acceptance") and think about what to do now.
497 There is one exception that I know of: If your LUKS container is
498 still open, then it may be possible to extract the master key from
499 the running system. Ask on the mailing-list on how to do that and
500 make sure nobody switches off the machine.
505 A salt is a random key-grade value added to the passphrase before
506 it is processed. It is not kept secret. The reason for using salts
507 is as follows: If an attacker wants to crack the password for a
508 single LUKS container, then every possible passphrase has to be
509 tried. Typically an attacker will not try every binary value, but
510 will try words and sentences from a dictionary.
512 If an attacker wants to attack several LUKS containers with the
513 same dictionary, then a different approach makes sense: Compute the
514 resulting slot-key for each dictionary element and store it on
515 disk. Then the test for each entry is just the slow unlocking with
516 the slot key (say 0.00001 sec) instead of calculating the slot-key
517 first (1 sec). For a single attack, this does not help. But if you
518 have more than one container to attack, this helps tremendously,
519 also because you can prepare your table before you even have the
520 container to attack! The calculation is also very simple to
521 parallelize. You could, for example, use the night-time unused CPU
522 power of your desktop PCs for this.
524 This is where the salt comes in. If the salt is combined with the
525 passphrase (in the simplest form, just appended to it), you
526 suddenly need a separate table for each salt value. With a
527 reasonably-sized salt value (256 bit, e.g.) this is quite
531 * Is LUKS secure with a low-entropy (bad) passphrase?
533 This needs a bit of theory. The quality of your passphrase is
534 directly related to its entropy (information theoretic, not
535 thermodynamic). The entropy says how many bits of "uncertainty" or
536 "randomness" are in you passphrase. In other words, that is how
537 difficult guessing the passphrase is.
539 Example: A random English sentence has about 1 bit of entropy per
540 character. A random lowercase (or uppercase) character has about
543 Now, if n is the number of bits of entropy in your passphrase and t
544 is the time it takes to process a passphrase in order to open the
545 LUKS container, then an attacker has to spend at maximum
547 attack_time_max = 2^n * t
549 time for a successful attack and on average half that. There is no
550 way getting around that relationship. However, there is one thing
551 that does help, namely increasing t, the time it takes to use a
552 passphrase, see next FAQ item.
554 Still, if you want good security, a high-entropy passphrase is the
555 only option. Use at least 64 bits for secret stuff. That is 64
556 characters of English text (but only if randomly chosen) or a
557 combination of 12 truly random letters and digits.
559 For passphrase generation, do not use lines from very well-known
560 texts (religious texts, Harry potter, etc.) as they are to easy to
561 guess. For example, the total Harry Potter has about 1'500'000
562 words (my estimation). Trying every 64 character sequence starting
563 and ending at a word boundary would take only something like 20
564 days on a single CPU and is entirely feasible.
566 On the other hand, choosing 1.5 lines from, say, the Wheel of Time
567 is in itself not more secure, but the book selection adds quite a
568 bit of entropy. (Now that I have mentioned it here, don't use tWoT
569 either!) If you add 2 or 3 typos or switch some words around, then
570 this is good passphrase material.
573 * What is "iteration count" and why is decreasing it a bad idea?
575 Iteration count is the number of PBKDF2 iterations a passphrase is
576 put through before it is used to unlock a key-slot. Iterations are
577 done with the explicit purpose to increase the time that it takes
578 to unlock a key-slot. This provides some protection against use of
579 low-entropy passphrases.
581 The idea is that an attacker has to try all possible passphrases.
582 Even if the attacker knows the passphrase is low-entropy (see last
583 item), it is possible to make each individual try take longer. The
584 way to do this is to repeatedly hash the passphrase for a certain
585 time. The attacker then has to spend the same time (given the same
586 computing power) as the user per try. With LUKS, the default is 1
587 second of PBKDF2 hashing.
589 Example 1: Lets assume we have a really bad passphrase (e.g. a
590 girlfriends name) with 10 bits of entropy. With the same CPU, an
591 attacker would need to spend around 500 seconds on average to
592 break that passphrase. Without iteration, it would be more like
593 0.0001 seconds on a modern CPU.
595 Example 2: The user did a bit better and has 32 chars of English
596 text. That would give use about 32 bits of entropy. With 1 second
597 iteration, that means an attacker on the same CPU needs around 136
598 years. That is pretty impressive for such a weak passphrase.
599 Without the iterations, it would be more like 50 days on a modern
600 CPU, and possibly far less.
602 In addition, the attacker can both parallelize and use special
603 hardware like GPUs to speed up the attack. The attack can also
604 happen quite some time after the luksFormat operation and CPUs can
605 have become faster and cheaper. For that reason you want a bit of
606 extra security. Anyways, in Example 1 your are screwed. In example
607 2, not necessarily. Even if the attack is faster, it still has a
608 certain cost associated with it, say 10000 EUR/USD with iteration
609 and 1 EUR/USD without iteration. The first can be prohibitively
610 expensive, while the second is something you try even without
611 solid proof that the decryption will yield something useful.
613 The numbers above are mostly made up, but show the idea. Of course
614 the best thing is to have a high-entropy passphrase.
616 Would a 100 sec iteration time be even better? Yes and no.
617 Cryptographically it would be a lot better, namely 100 times better.
618 However, usability is a very important factor for security
619 technology and one that gets overlooked surprisingly often. For
620 LUKS, if you have to wait 2 minutes to unlock the LUKS container,
621 most people will not bother and use less secure storage instead. It
622 is better to have less protection against low-entropy passphrases
623 and people actually use LUKS, than having them do without
624 encryption altogether.
626 Now, what about decreasing the iteration time? This is generally a
627 very bad idea, unless you know and can enforce that the users only
628 use high-entropy passphrases. If you decrease the iteration time
629 without ensuring that, then you put your users at increased risk,
630 and considering how often LUKS containers are unlocked in a
631 typical work-flow, you do so without a good reason. Don't do it.
632 The iteration time is already low enough that some users will
633 still chose passphrases with entropy low enough that they are
634 vulnerable. Lowering it even further increases this danger
638 * Is LUKS with default parameters less secure on a slow CPU?
640 Unfortunately, yes. However the only aspect affected is the
641 protection for low-entropy passphrase or master-key. All other
642 security aspects are independent of CPU speed.
644 The master key is less critical, as you really have to work at it
645 to give it low entropy. One possibility is to supply the master key
646 yourself. If that key is low-entropy, then you get what you
647 deserve. The other known possibility is to use /dev/urandom for
648 key generation in an entropy-startved situation (e.g. automatic
649 installation on an embedded device without network and other entropy
652 For the passphrase, don't use a low-entropy passphrase. If your
653 passphrase is good, then a slow CPU will not matter. If you insist
654 on a low-entropy passphrase on a slow CPU, use something like
655 "--iter-time=10" or higher and wait a long time on each LUKS unlock
656 and pray that the attacker does not find out in which way exactly
657 your passphrase is low entropy. This also applies to low-entropy
658 passphrases on fast CPUs. Technology can do only so much to
659 compensate for problems in front of the keyboard.
662 * Why was the default aes-cbc-plain replaced with aes-cbc-essiv?
664 The problem is that cbc-plain has a fingerprint vulnerability, where
665 a specially crafted file placed into the crypto-container can be
666 recognized from the outside. The issue here is that for cbc-plain
667 the initialization vector (IV) is the sector number. The IV gets
668 XORed to the first data chunk of the sector to be encrypted. If you
669 make sure that the first data block to be stored in a sector
670 contains the sector number as well, the first data block to be
671 encrypted is all zeros and always encrypted to the same ciphertext.
672 This also works if the first data chunk just has a constant XOR
673 with the sector number. By having several shifted patterns you can
674 take care of the case of a non-power-of-two start sector number of
677 This mechanism allows you to create a pattern of sectors that have
678 the same first ciphertext block and signal one bit per sector to the
679 outside, allowing you to e.g. mark media files that way for
680 recognition without decryption. For large files this is a
681 practical attack. For small ones, you do not have enough blocks to
682 signal and take care of different file starting offsets.
684 In order to prevent this attack, the default was changed to
685 cbc-essiv. ESSIV uses a keyed hash of the sector number, with the
686 encryption key as key. This makes the IV unpredictable without
687 knowing the encryption key and the watermarking attack fails.
690 * Are there any problems with "plain" IV? What is "plain64"?
692 First, "plain" and "plain64" are both not safe to use with CBC, see
695 However there are modes, like XTS, that are secure with "plain" IV.
696 The next limit is that "plain" is 64 bit, with the upper 32 bit set
697 to zero. This means that on volumes larger than 2TiB, the IV
698 repeats, creating a vulnerability that potentially leaks some
699 data. To avoid this, use "plain64", which uses the full sector
700 number up to 64 bit. Note that "plain64" requires a kernel >=
701 2.6.33. Also note that "plain64" is backwards compatible for
702 volume sizes <= 2TiB, but not for those > 2TiB. Finally, "plain64"
703 does not cause any performance penalty compared to "plain".
706 * What about XTS mode?
708 XTS mode is potentially even more secure than cbc-essiv (but only if
709 cbc-essiv is insecure in your scenario). It is a NIST standard and
710 used, e.g. in Truecrypt. At the moment, if you want to use it, you
711 have to specify it manually as "aes-xts-plain", i.e.
713 cryptsetup -c aes-xts-plain luksFormat <device>
715 For volumes >2TiB and kernels >= 2.6.33 use "plain64" (see FAQ
716 item on "plain" and "plain64"):
718 cryptsetup -c aes-xts-plain64 luksFormat <device>
720 There is a potential security issue with XTS mode and large blocks.
721 LUKS and dm-crypt always use 512B blocks and the issue does not
725 6. Backup and Data Recovery
728 * Does a backup compromise security?
730 Depends on how you do it. First, a backup is non-optional with
731 encrypted data just the same way it is with non-encrypted data.
732 Disks do break and they do not care whether they make plain or
733 encrypted data inaccessible.
735 However there are risks introduced by backups. For example if you
736 change/disable a key-slot in LUKS, a binary backup of the partition
737 will still have the old key-slot. To deal with this, you have to
738 be able to change the key-slot on the backup as well, or use a
739 different set-up. One option is to have a different passphrase on
740 the backup and to make the backup with both containers open.
741 Another one is to make a backup of the original, opened container to
742 a single file, e.g. with tar, and to encrypt that file with
743 public-key-cryptography, e.g. with GnuPG. You can then keep the
744 secret key in a safe place, because it is only used to decrypt a
745 backup. The key the backup is encrypted with can be stored without
746 special security measures, as long as an attacker cannot replace
749 If you use dm-crypt, backup is simpler: As there is no key
750 management, the main risk is that you cannot wipe the backup when
751 wiping the original. However wiping the original for dm-crypt
752 should consist of forgetting the passphrase and that you can do
753 without actual access to the backup.
755 In both cases, there is an additional (usually small) risk: An
756 attacker can see how many sectors and which ones have been changed
757 since the backup. This is not possible with the public-key method
760 My personal advice is to use one USB disk (low value date) or three
761 disks (high value data) in rotating order for backups, and either
762 use different passphrases or keep them easily accessible in case
763 you need to disable a key-slot. If you do network-backup or
764 tape-backup, I strongly recommend to go the public-key path,
765 especially as you typically cannot reliably delete data in these
766 scenarios. (Well, you can burn the tape if it is under your
770 * What happens if I overwrite the start of a LUKS partition or damage
771 the LUKS header or key-slots?
773 There are two critical components for decryption: The salt values
774 in the header itself and the key-slots. If the salt values are
775 overwritten or changed, nothing (in the cryptographically strong
776 sense) can be done to access the data, unless there is a backup of
777 the LUKS header. If a key-slot is damaged, the data can still be
778 read with a different key-slot, if there is a remaining undamaged
779 and used key-slot. Note that in order to make a key-slot
780 unrecoverable in a cryptographically strong sense, changing about
781 4-6 bits in random locations of its 128kiB size is quite enough.
784 * What happens if I (quick) format a LUKS partition?
786 I have not tried the different ways to do this, but very likely you
787 will have written a new boot-sector, which in turn overwrites the
788 LUKS header, including the salts. You may also damage the key-slots
789 in part or in full. See also last item.
792 * What does the on-disk structure of dm-crypt look like?
794 There is none. dm-crypt takes a block device and gives encrypted
795 access to each of its blocks with a key derived from the passphrase
796 given. If you use a cipher different than the default, you have to
797 specify that as a parameter to cryptsetup too. If you want to
798 change the password, you basically have to create a second
799 encrypted device with the new passphrase and copy your data over.
800 On the plus side, if you accidentally overwrite any part of a
801 dm-crypt device, the damage will be limited to the are you
805 * What does the on-disk structure of LUKS look like?
807 A LUKS partition consists of a header, followed by 8 key-slot
808 descriptors, followed by 8 key slots, followed by the encrypted
811 Header and key-slot descriptors fill the first 592 bytes. The
812 key-slot size depends on the creation parameters, namely on the
813 number of anti-forensic stripes and on key block alignment.
815 With 4000 stripes (the default), each key-slot is a bit less than
816 128kiB in size. Due to sector alignment of the key-slot start,
817 that means the key block 0 is at offset 0x1000-0x20400, key block
818 1 at offset 0x21000-0x40400, and key block 7 at offset
819 0xc1000-0xe0400. The space to the next full sector address is
820 padded with zeros. Never used key-slots are filled with what the
821 disk originally contained there, a key-slot removed with
822 "luksRemoveKey" or "luksKillSlot" gets filled with 0xff. Start of
823 bulk data (with the default 4000 stripes and 8 key-slots) is at
824 0x101000, i.e. at 1'052'672 bytes, i.e. at 1MiB + 4096 bytes from
825 the start of the partition. This is also the value given by command
826 "luksDump" with "Payload offset: 2056", just multiply by the sector
827 size (512 bytes). Incidentally, "luksHeaderBackup" dumps exactly
828 the first 1'052'672 bytes to file and "luksHeaderRestore" restores
831 The exact specification of the format is here:
832 http://code.google.com/p/cryptsetup/wiki/Specification
835 * How do I backup a LUKS header?
837 While you could just copy the appropriate number of bytes from the
838 start of the LUKS partition, the best way is to use command option
839 "luksHeaderBackup" of cryptsetup. This protects also against errors
840 when non-standard parameters have been used in LUKS partition
844 cryptsetup luksHeaderBackup --header-backup-file h /dev/mapper/c1
847 * How do I backup a LUKS partition?
849 You do a sector-image of the whole partition. This will contain the
850 LUKS header, the keys-slots and the data ares. It can be done
851 under Linux e.g. with dd_rescue (for a direct image copy) and with
852 "cat" or "dd". Example:
854 cat /dev/sda10 > sda10.img
855 dd_rescue /dev/sda10 sda10.img
857 You can also use any other backup software that is capable of making
858 a sector image of a partition. Note that compression is
859 ineffective for encrypted data, hence it does not sense to use it.
862 * Do I need a backup of the full partition? Would the header and
863 key-slots not be enough?
865 Backup protects you against two things: Disk loss or corruption and
866 user error. By far the most questions on the dm-crypt mailing list
867 about how to recover a damaged LUKS partition are related to user
868 error. For example, if you create a new filesystem on a LUKS
869 partition, chances are good that all data is lost permanently.
871 For this case, a header+key-slot backup would often be enough. But
872 keep in mind that a HDD has roughly a failure risk of 5% per year.
873 It is highly advisable to have a complete backup to protect against
877 * Are there security risks from a backup of the LUKS header or a
878 whole LUKS partition?
880 Yes. One risk is that if you remove access rights for specific
881 key-slots by deleting their contents, the data can still be
882 accessed with invalidated passphrase and the backup. The other risk
883 is that if you erase a LUKS partition, a backup could still grant
884 access, especially if you only erased the LUKS header and not the
888 * I think this is overly complicated. Is there an alternative?
890 Yes, you can use plain dm-crypt. It does not allow multiple
891 passphrases, but on the plus side, it has zero on disk description
892 and if you overwrite some part of a plain dm-crypt partition,
893 exactly the overwritten parts are lost (rounded up to sector
897 7. Issues with Specific Versions of cryptsetup
900 * When using the create command for plain dm-crypt with cryptsetup
901 1.1.x, the mapping is incompatible and my data is not accessible
904 With cryptsetup 1.1.x, the distro maintainer can define different
905 default encryption modes for LUKS and plain devices. You can check
906 these compiled-in defaults using "cryptsetup --help". Moreover, the
907 plain device default changed because the old IV mode was
908 vulnerable to a watermarking attack.
910 If you are using a plain device and you need a compatible mode, just
911 specify cipher, key size and hash algorithm explicitly. For
912 compatibility with cryptsetup 1.0.x defaults, simple use the
915 cryptsetup create -c aes-cbc-plain -s 256 -h ripemd160 <name> <dev>
917 LUKS stores cipher and mode in the metadata on disk, avoiding this
921 * cryptsetup on SLED 10 has problems...
923 SLED 10 is missing an essential kernel patch for dm-crypt, which
924 is broken in its kernel as a result. There may be a very old
925 version of cryptsetup (1.0.x) provided by SLED, which should also
926 not be used anymore as well. My advice would be to drop SLED 10.
928 A. Contributors In no particular order: